ÎÒ¹ú¹æ¶¨ÒûÓÃË®ÖÊÁ¿±ê×¼±ØÐë·ûºÏÏÂÁÐÒªÇó£º

pH

6.5¡ª8.5

Ca2+£¬Mg2+×ÜŨ¶È

<0.0045mol/L

ϸ¾ú×ÜÊý

<100¸ö/mL

¼ÓÈëÄý¾Û¼Á

ͨÈë¶þÑõ»¯Ì¼

 
ÒÔÏÂʹԴˮ´¦Àí³É×ÔÀ´Ë®µÄ¹¤ÒÕÁ÷³ÌʾÒâͼ£º

¶þ¼¶³Á½µ³Ø

 

¹ýÂ˳Ø

 

×ÔÀ´Ë®

 

¼ÓÈëʯ»Ò

 


ͨÈëÆøÌåA

 

                                                                 

£¨1£©Ô´Ë®Öк¬Ca2+¡¢Mg2+¡¢HCO3-¡¢Cl-µÈ£¬¼ÓÈëʯ»ÒºóÉú³ÉCa(OH)2£¬½ø¶ø·¢ÉúÈô¸É¸´·Ö½â·´Ó¦£¬Ð´³öÆäÖÐÒ»¸öÀë×Ó·½³Ìʽ£º                       ¡£

£¨2£©Äý¾Û¼Á³ýÈ¥Ðü¸¡¹ÌÌå¿ÅÁ£µÄ¹ý³Ì           £¨Ìîд±àºÅ£©

¢Ù Ö»ÊÇÎïÀí¹ý³Ì   ¢Ú Ö»ÊÇ»¯Ñ§¹ý³Ì   ¢Û ÊÇÎïÀíºÍ»¯Ñ§¹ý³Ì

FeSO4??7H2OÊdz£ÓõÄÄý¾Û¼Á£¬ËüÔÚË®ÖÐ×îÖÕÉú³É             ³Áµí¡£

£¨3£©Í¨Èë¶þÑõ»¯Ì¼µÄÄ¿µÄÊÇ                ºÍ                 ¡£

£¨4£©ÆøÌåAµÄ×÷ÓÃÊÇ                 ¡£ÕâÖÖ×÷ÓÃÊÇ»ùÓÚÆøÌåAºÍË®·´Ó¦µÄ²úÎï¾ßÓР                ÐÔ¡£

£¨5£©ÏÂÁÐÎïÖÊÖУ¬         ¿ÉÒÔ×÷ÎªÆøÌåAµÄ´úÓÃÆ·¡££¨Ìîд±àºÅ£©

¢Ù Ca(ClO)2   ¢Ú NH3£¨Òº£©   ¢Û K2FeO4   ¢Ü SO2

£¨1£©¼û½âÎö

£¨2£©£©¢Û         ½º×´Fe(OH)3  

£¨3£©³ýÈ¥Ca2+    µ÷½ÚPHÖµ 

£¨4£©É±¾úÏû¶¾   Ç¿Ñõ»¯ 

£¨5£©¢Ù    ¢Û


½âÎö:

±¾Ìâ×¢ÖØ¿¼ºËѧÉú¶Ô»ù´¡ÖªÊ¶Àí½âµÄÉî¶È£¬ÒªÇóѧÉúÔÚËùѧ»¯Ñ§ÖªÊ¶µÄ»ù´¡ÉÏ»á˼¿¼¡¢»á·ÖÎö£¬ÄÜÓúÃ֪ʶ¡¢Óûî֪ʶ¡£±¾ÌâÄܰÑѧ¿ÆÖªÊ¶ÓëÉç»á¡¢Éú²ú¡¢Éú»îÇé¾°Ï໥¹µÍ¨£¬Ê¹Ñ§ÉúÌå»áµ½Ñ§ÓÐËù»ñ¡¢Ñ§ÓÐËùÓá£ÊÔÌ⻹ҪÇóѧÉúÔÚ½âÌâ¹ý³ÌÖÐÉÆÓÚµ÷ÓÃÒÑÐγɵÄÖªÊ¶ÍøÂ磬°ÑË®µÄ¾»»¯ºÍÈí»¯µÄ֪ʶ×ۺϺóÇ¨ÒÆµ½±¾ÌâÖÐÀ´£¬Õâ¶ÔѧÉúµ÷ÓÃ֪ʶ¿éµÄЧÂʺÍËÙ¶ÈÌá³öÁ˸ßÒªÇó¡££¨1£©HCO3-+OH-=CO32-+H2O

Mg2++2OH-=Mg(OH)2¡ý

Ca2++HCO3-+OH-=CaCO3¡ý+H2O

£¨2£©Äý¾Û¼Á¼ÓÈëË®ÖÐÒ»°ãÏÈ·¢ÉúË®½â£¨»¯Ñ§¹ý³Ì£©£¬Éú³ÉµÄ½º×´ÎïÎü¸½Ðü¸¡ÎÎïÀí¹ý³Ì£©¡£FeSO4??7H2OÈÜÓÚË®ºó£¬¾­¹ýË®½âºÍÑõ»¯×îÖÕÉú³ÉFe(OH)3¡£

£¨3£©¼ÓÈë¶þÑõ»¯Ì¼¿ÉÒÔ³ýÈ¥¹ýÁ¿µÄCa(OH)2£¬Æä×÷ÓÃÊdzýÈ¥Ca2+ºÍµ÷½ÚpH¡£

£¨4£©³ýȥˮÖеÄÐü¸¡Îïºó£¬¾Í±ØÐë¶ÔË®½øÐÐÏû¶¾¡£ËùÒÔͨÈëÆøÌåAµÄ×÷Óö¨ÎªÉ±¾úÏû¶¾£¨Èç¿ÉͨÈëÂÈÆø£©£¬ÏÔÈ»ÊÇÀûÓÃÆøÌåA¸úË®·´Ó¦µÄ²úÎï¾ßÓÐÇ¿Ñõ»¯ÐÔ¡£

£¨5£©¸ù¾Ý£¨4£©µÄ·ÖÎö£¬×÷ÎªÆøÌåAµÄ´úÓÃÆ·±ØÐë¾ßÓÐÇ¿Ñõ»¯ÐÔ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2000?ÉϺ££©ÎÒ¹ú¹æ¶¨ÒûÓÃË®ÖÊÁ¿±ê×¼±ØÐë·ûºÏÏÂÁÐÒªÇó£º
pHÖµ 6.5-8.5
Ca2+£¬Mg2+×ÜŨ¶È £¼0.0045mol/L
ϸ¾ú×ÜÊý £¼100¸ö/mL
ÒÔÏÂÊÇÔ´Ë®´¦Àí³É×ÔÀ´Ë®µÄ¹¤ÒÕÁ÷³ÌʾÒâͼ

£¨1£©Ô´Ë®Öк¬Ca2+¡¢Mg2+¡¢HCO3-¡¢Cl-µÈ£¬¼ÓÈëʯ»ÒºóÉú³ÉCa£¨OH£©2£¬½ø¶ø·¢ÉúÈô¸É¸´·Ö½â·´Ó¦£¬Ð´³öÆäÖÐÒ»¸öÀë×Ó·½³Ìʽ
HCO3-+OH-=CO32-+H2O£»
HCO3-+OH-=CO32-+H2O£»

£¨2£©Äý¾Û¼Á³ýÈ¥Ðü¸¡¹ÌÌå¿ÅÁ£µÄ¹ý³Ì
¢Û
¢Û
£¨Ìîд±àºÅ£¬¶àÑ¡µ¹¿Û£©
¢ÙÖ»ÓÐÎïÀí¹ý³Ì    ¢ÚÖ»ÊÇ»¯Ñ§¹ý³Ì     ¢ÛÊÇÎïÀíºÍ»¯Ñ§¹ý³Ì
FeSO4?7H2O³£ÓõÄÄý¾Û¼Á£¬ËüÔÚË®ÖÐ×îÖÕÉú³É
½º×´Fe£¨OH£©3
½º×´Fe£¨OH£©3
³Áµí£®
£¨3£©Í¨Èë¶þÑõ»¯Ì¼µÄÄ¿µÄÊÇ
³ýÈ¥Ca2+
³ýÈ¥Ca2+
ºÍ
µ÷½ÚPHÖµ
µ÷½ÚPHÖµ
£®
£¨4£©ÆøÌåAͨ³£Ê¹ÓÃÂÈÆø£¬ÂÈÆøµÄ×÷ÓÃÊÇ»ùÓÚÆäºÍË®·´Ó¦µÄ²úÎïÖ®Ò»¾ßÓÐ
Ç¿Ñõ»¯
Ç¿Ñõ»¯
ÐÔ£¬Çëд³öÂÈÆøÓëË®·´Ó¦µÄÀë×Ó·´Ó¦·½³Ìʽ
Cl2+H2O=H++Cl-+HClO
Cl2+H2O=H++Cl-+HClO
£®
£¨5£©ÏÂÁÐÎïÖÊÖÐÄÜ×÷ΪÂÈÆøµÄ´úÓÃÆ·µÄÊÇ
¢Ù¢Û
¢Ù¢Û
£¨Ìîд±àºÅ£¬¶àÑ¡µ¹¿Û£©
¢ÙCa£¨ClO£©2        ¢ÚNH3£¨Òº£©        ¢ÛK2FeO4          ¢ÜSO2£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÎÒ¹ú¹æ¶¨ÒûÓÃË®ÖÊÁ¿±ê×¼±ØÐë·ûºÏÏÂÁÐÒªÇó£º
PH 6.5¡«8.5
Ca2+¡¢Mg2+×ÜŨ¶È £¼0.0045mol/L
ϸ¾ú×ÜÊý £¼100¸ö/mL
ij×ÛºÏʵ¼ù»î¶¯Ð¡×éµ½×ÔÀ´Ë®³§²Î¹Û£¬Á˽⵽Դˮ´¦Àí³É×ÔÀ´Ë®µÄ¹¤ÒÕÁ÷³ÌʾÒâͼÈçÏ£º¾«Ó¢¼Ò½ÌÍø
£¨1£©Ô´Ë®Öк¬ÓÐCa2+¡¢Mg2+¡¢HCO3-¡¢Cl-µÈ£¬¼ÓÈëCaOºó·¢ÉúÈô¸É¸ö»¯Ñ§·´Ó¦£¬Çëд³öÆäÖÐÈÎÒâÒ»¸ö·´Ó¦µÄÀë×Ó·½³Ìʽ£º
 

£¨2£©¼ÓÈëÐõÄý¼Á¿ÉÒÔ³ýÈ¥ÆäÖеÄÐü¸¡¹ÌÌå¿ÅÁ££¬¸Ã¹ý³ÌÊÇ
 
£¨ÌîÐòºÅ£©
¢ÙÖ»ÓÐÎïÀí¹ý³Ì£¬ÎÞ»¯Ñ§¹ý³Ì£»
¢ÚÖ»Óл¯Ñ§¹ý³Ì£¬ÎÞÎïÀí¹ý³Ì£»
¢Û¼ÈÓÐÎïÀí¹ý³Ì£¬ÓÖÓл¯Ñ§¹ý³Ì£®
£¨3£©FeSO4?7H2OÊdz£ÓõÄÐõÄý¼Á£¬¼ÓÈëºó×îÖÕÉú³ÉºìºÖÉ«½º×´³Áµí£¬ÔòÕâÖÖ³ÁµíÊÇ
 
£¨Ìѧʽ£©
£¨4£©Í¨Èë¶þÑõ»¯Ì¼µÄÄ¿µÄÊÇ
 
ºÍ
 
£®
£¨5£©ÎïÖÊAµÄ×÷ÓÃÊÇ
 
£¬ÔòA¿ÉÒÔÑ¡ÔñÏÂÁÐÎïÖÊÖеÄ
 
£¨ÌîÐòºÅ£©
¢ÙClO2     ¢ÚSO2     ¢ÛÒºÂÈ     ¢ÜCa£¨ClO2£©2     ¢ÝŨÁòËᣮ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÎÒ¹ú¹æ¶¨ÒûÓÃË®ÖÊÁ¿±ê×¼±ØÐë·ûºÏÏÂÁÐÒªÇó£º

                   PH

6.5¡ª8.5

Ca2+¡¢Mg2+×ÜŨ¶È/mol¡¤L-1

£¼0.0045

ϸ¾ú×ÜÊý/¸ö¡¤mol

£¼100¸ö

ͼ3-14ÊÇÔ­Ë®´¦Àí³É×ÔÀ´Ë®µÄ¹¤ÒÕÁ÷³ÌʾÒâͼ£º

                                                                   ͼ3-14

(1)Ô­Ë®Öк¬Ca2+¡¢Mg2+¡¢¡¢Cl-µÈ£¬¼ÓÈëʯ»ÒºóÉú³ÉCa(OH)2£¬½ø¶ø·¢ÉúÈô¸É¸´·Ö½â·´Ó¦£¬Ð´³öÆäÖÐÒ»¸öÀë×Ó·½³Ìʽ__________________________________________________¡£

(2)Äý¾Û¼Á³ýÈ¥Ðü¸¡¹ÌÌå¿ÅÁ£µÄ¹ý³Ì___________________________¡£(Ìîд±àºÅ£¬¶àÑ¡µ¹¿Û)

¢ÙÖ»ÊÇÎïÀí¹ý³Ì  ¢ÚÖ»ÊÇ»¯Ñ§¹ý³Ì  ¢ÛÊÇÎïÀíºÍ»¯Ñ§¹ý³Ì

FeSO4¡¤7H2OÊdz£ÓõÄÄý¾Û¼Á£¬ËüÔÚË®ÖÐ×îÖÕÉú³É___________________________³Áµí¡£

(3)ͨÈë¶þÑõ»¯Ì¼µÄÄ¿µÄÊÇ__________________ºÍ____________________¡£

(4)ÆøÌåAµÄ×÷ÓÃÊÇ___________¡£ÕâÖÖ×÷ÓÃÊÇ»ùÓÚÆøÌåAºÍË®·´Ó¦µÄ²úÎï¾ßÓÐ________ÐÔ¡£

(5)ÏÂÁÐÎïÖÊÖУ¬______________¿ÉÒÔ×÷ÎªÆøÌåAµÄ´úÓÃÆ·¡£(Ìîд±àºÅ£¬¶àÑ¡µ¹¿Û)

¢ÙCa(ClO)2  ¢ÚŨ°±Ë®  ¢ÛK2FeO4  ¢ÜSO2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÎÒ¹ú¹æ¶¨ÒûÓÃË®ÖÊÁ¿±ê×¼±ØÐë·ûºÏÏÂÁÐÒªÇó£ºpHΪ6.5¡ª8.5£¬Ca2+ºÍMg2+×ÜŨ¶ÈСÓÚ0.004 5 mol¡¤L-1£¬Ï¸¾ú×ÜÊýСÓÚ100¸öÿºÁÉý¡£ÏÂͼÊÇÔ´Ë®´¦Àí³É×ÔÀ´Ë®µÄ¹¤ÒÕÁ÷³ÌʾÒâͼ¡£

(1)Ô´Ë®Öк¬Ca2+¡¢Mg2+¡¢¡¢Cl-µÈ£¬¼ÓÈëʯ»Òºó£¬Éú³ÉCa(OH)2£¬½ø¶ø·¢Éú¶à¸ö¸´·Ö½â·´Ó¦£¬Çëд³öÆäÖÐÈý¸ö·´Ó¦µÄÀë×Ó·½³Ìʽ£º¢Ù__________________£»¢Ú__________________£»¢Û_________________________________¡£

(2)Äý¾Û¼Á³ýÈ¥Ðü¸¡¹ÌÌå¿ÅÁ£µÄ¹ý³ÌÊÇ______________________ (ÌîÐòºÅ)¡£

A.Ö»ÊÇÎïÀí¹ý³Ì             B.Ö»ÊÇ»¯Ñ§¹ý³Ì          C.ÊÇÎïÀíºÍ»¯Ñ§¹ý³Ì

(3)ÂÌ·¯ÔÚË®ÖÐ×îÖÕÉú³É______________________³Áµí¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄê½­Î÷ʡЭ×÷Ìå¸ßÈý5Ôµڶþ´ÎÁª¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨1£©ÏÂÁйØÓÚ¹¤ÒµÉú²ú˵·¨ÕýÈ·µÄÊÇ             ¡££¨ÌîÐòºÅ£©

A£®ÔÚºîÊÏÖÆ¼î¹¤ÒµÖУ¬Ïò±¥ºÍÂÈ»¯ÄÆÈÜÒºÖÐÏÈͨ¶þÑõ»¯Ì¼£¬ºóͨ°±Æø

B£®ÔÚÁòËṤҵ¡¢ºÏ³É°±¹¤Òµ¡¢ÏõËṤҵÖУ¬½Ô²ÉÓÃÑ­»·²Ù×÷Ìá¸ßÔ­ÁÏÀûÓÃÂÊ

C£®ÔÚÂȼҵ£¬µç½â²Û±»Àë×Ó½»»»Ä¤¸ô³ÉÒõ¼«ÊÒºÍÑô¼«ÊÒ

D£®¹¤ÒµÉϲÉÓõç½âÈÛÈÚÂÈ»¯ÂÁµÄ·½·¨ÖÆÈ¡½ðÊôÂÁ

E£®Ê¯ÓÍÁÑ»¯ÊôÓÚ»¯Ñ§±ä»¯£¬Ö÷ҪĿµÄÊÇΪÁË»ñµÃ¶ÌÁ´²»±¥ºÍÆøÌ¬Ìþ

£¨2£©ÎÒ¹ú¹æ¶¨ÒûÓÃË®ÖÊÁ¿±ê×¼¹æ¶¨±ØÐë·ûºÏϱíÖÐÒªÇó£º

pH

Ca2+  ¡¢Mg2+×ÜŨ¶È

ϸ¾ú×ÜÊý

6.5¡«8.5

£¼ 0.004 5 mol¡¤L-1?

£¼100¸ö¡¤mL-1?

 

ÒÔÏÂÊÇÔ­Ë®´¦Àí³É×ÔÀ´Ë®µÄ¹¤ÒÕÁ÷³ÌʾÒâͼ£º

¢ÙÔ­Ë®Öк¬Ca2+  ¡¢Mg2+  ¡¢HCO3- ¡¢Cl-µÈ£¬¼ÓÈëʯ»ÒÉú³ÉCa(OH)2£¬½ø¶ø·¢ÉúÈô¸É¸´·Ö½â·´Ó¦£¬Ð´³öÆäÖеÄÀë×Ó·½³Ìʽ£¨Ö»ÒªÇóд³öÁ½¸ö£©£º                 £»                 ¡£

¢ÚFeSO4¡¤7H2OÊdz£ÓõÄÄý¾Û¼Á£¬ËüÔÚË®ÖÐ×îÖÕÉú³É                         ³Áµí£»Í¨Èë¶þÑõ»¯Ì¼µÄÄ¿µÄÊÇ                 ºÍ                   ¡£

¢ÛÆøÌåAµÄ×÷ÓÃÊÇ          £¬ÏÂÁÐÎïÖÊÖР          ¿ÉÒÔ×÷ÎªÆøÌåAµÄ´úÓÃÆ·£¨Ìî±àºÅ£©¡£

a£®ClO2      b£®Å¨°±Ë®       c£®K2FeO4        d£®SO2       e.Ư°×·Û

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸