(16·Ö) ͼ¢ñÊÇʵÑéÊÒÖг£ÓÃÓÚÖÆ±¸ºÍ¸ÉÔïÆøÌåµÄ×°ÖÃ:

(1)   ¼×ͬѧÓÃͼ¢ñ×°Öá¢Í­ºÍŨÏõËáÖÆ±¸²¢ÊÕ¼¯¸ÉÔïµÄNO2ÆøÌ壺

¢Ù BÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ_____________________________¡£

¢Ú ÊÕ¼¯NO2ÆøÌåµÄ·½·¨                               £»

¢Û ½«ÊÕ¼¯ÂúNO2µÄÉÕÆ¿ÃÜ·â½þÈë±ùË®ÖУ¬ÉÕÆ¿ÄÚÆøÌåÑÕÉ«±ädz, ÔòÏÂÁз´Ó¦£º

 2NO2 (g) N2O4(g)  ¦¤H ÖеĦ¤H     0£¨Ìî¡°>¡±»ò¡°<¡±£©

   £¨2£© ÒÒͬѧÓÃͼ¢ñ×°ÖÃÖÆÈ¡NH3ºÍO2µÄ»ìºÏÆøÌ壬ÓÃͼ¢ò×°ÖÃÑéÖ¤°±µÄijЩÐÔÖÊ£º

ÍùAÖмÓÈëŨ°±Ë®£¬BÖмÓÈëNa2O2¹ÌÌ壬CÖмÓÈë¼îʯ»Ò£¬DÄÚ·ÅÖô߻¯¼Á£¨²¬Ê¯ÃÞ£©£¬°´ÆøÁ÷·½Ïòa¡ú b¡úc¡ú hÁ¬½Ó¸÷ÒÇÆ÷ £º

¢Ù ʵÑéÖй۲쵽DÄÚÓкì×ØÉ«ÆøÌå³öÏÖ£¬Ö¤Ã÷°±Æø¾ßÓÐ____£¨Ìî¡°Ñõ»¯ÐÔ¡±»ò¡°»¹Ô­ÐÔ¡±£©¡£

¢Ú DÖз´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________    _____¡¢                          .

¢Û Ϊ·ÀÖ¹NO2 ÎÛȾ»·¾³£¬E×°ÖÃÖÐ×°µÄÊÔ¼Á¿ÉÒÔÊÇ                  ¡£

 

¡¾´ð°¸¡¿

£¨16·Ö £©

£¨1£© ¢ÙCu + 4HNO3£½£½ Cu£¨NO3£©2+ 2NO2¡ü+ 2H2O  £¨3·Ö£©

¢ÚÏòÉÏÅÅÆø·¨  £¨2·Ö£©     ¢Û <£¨2·Ö£©

£¨2£©  ¢Ù»¹Ô­ÐÔ  £¨2·Ö£©

¢Ú 4NH3 + 5O2 4NO + 6H2O  £¨3·Ö£©£»2NO + O2 £½£½ 2NO2 £¨2·Ö£©£»

¢Û  NaOHÈÜÒº£¨2·Ö£©

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(16·Ö) ͼ¢ñÊÇʵÑéÊÒÖг£ÓÃÓÚÖÆ±¸ºÍ¸ÉÔïÆøÌåµÄ×°ÖÃ:

(1)  ¼×ͬѧÓÃͼ¢ñ×°Öá¢Í­ºÍŨÏõËáÖÆ±¸²¢ÊÕ¼¯¸ÉÔïµÄNO2ÆøÌ壺

¢Ù BÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ_____________________________¡£

¢Ú ÊÕ¼¯NO2ÆøÌåµÄ·½·¨                              £»

¢Û ½«ÊÕ¼¯ÂúNO2µÄÉÕÆ¿ÃÜ·â½þÈë±ùË®ÖУ¬ÉÕÆ¿ÄÚÆøÌåÑÕÉ«±ädz, ÔòÏÂÁз´Ó¦£º

 2NO2(g) N2O4(g)  ¦¤H ÖеĦ¤H     0£¨Ìî¡°>¡±»ò¡°<¡±£©

   £¨2£© ÒÒͬѧÓÃͼ¢ñ×°ÖÃÖÆÈ¡NH3ºÍO2µÄ»ìºÏÆøÌ壬ÓÃͼ¢ò×°ÖÃÑéÖ¤°±µÄijЩÐÔÖÊ£º

ÍùAÖмÓÈëŨ°±Ë®£¬BÖмÓÈëNa2O2¹ÌÌ壬CÖмÓÈë¼îʯ»Ò£¬DÄÚ·ÅÖô߻¯¼Á£¨²¬Ê¯ÃÞ£©£¬°´ÆøÁ÷·½Ïòa¡ú b¡úc¡ú hÁ¬½Ó¸÷ÒÇÆ÷ £º

¢Ù ʵÑéÖй۲쵽DÄÚÓкì×ØÉ«ÆøÌå³öÏÖ£¬Ö¤Ã÷°±Æø¾ßÓÐ____£¨Ìî¡°Ñõ»¯ÐÔ¡±»ò¡°»¹Ô­ÐÔ¡±£©¡£

¢Ú DÖз´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________    _____¡¢                         .

¢Û Ϊ·ÀÖ¹NO2 ÎÛȾ»·¾³£¬E×°ÖÃÖÐ×°µÄÊÔ¼Á¿ÉÒÔÊÇ                 ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011¡ª2012ѧÄê¹ã¶«Ê¡ÂÞ¶¨ÖÐѧ¸ßÈýÀí×ÛÖܲ⻯ѧÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

(16·Ö) ͼ¢ñÊÇʵÑéÊÒÖг£ÓÃÓÚÖÆ±¸ºÍ¸ÉÔïÆøÌåµÄ×°ÖÃ:

(1)  ¼×ͬѧÓÃͼ¢ñ×°Öá¢Í­ºÍŨÏõËáÖÆ±¸²¢ÊÕ¼¯¸ÉÔïµÄNO2ÆøÌ壺
¢Ù BÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ_____________________________¡£
¢Ú ÊÕ¼¯NO2ÆøÌåµÄ·½·¨                              £»
¢Û ½«ÊÕ¼¯ÂúNO2µÄÉÕÆ¿ÃÜ·â½þÈë±ùË®ÖУ¬ÉÕÆ¿ÄÚÆøÌåÑÕÉ«±ädz,ÔòÏÂÁз´Ó¦£º
2NO2 (g)N2O4(g) ¦¤H ÖеĦ¤H    0£¨Ìî¡°>¡±»ò¡°<¡±£©
£¨2£© ÒÒͬѧÓÃͼ¢ñ×°ÖÃÖÆÈ¡NH3ºÍO2µÄ»ìºÏÆøÌ壬ÓÃͼ¢ò×°ÖÃÑéÖ¤°±µÄijЩÐÔÖÊ£º
ÍùAÖмÓÈëŨ°±Ë®£¬BÖмÓÈëNa2O2¹ÌÌ壬CÖмÓÈë¼îʯ»Ò£¬DÄÚ·ÅÖô߻¯¼Á£¨²¬Ê¯ÃÞ£©£¬°´ÆøÁ÷·½Ïòa¡ú b¡úc¡ú hÁ¬½Ó¸÷ÒÇÆ÷ £º

¢Ù ʵÑéÖй۲쵽DÄÚÓкì×ØÉ«ÆøÌå³öÏÖ£¬Ö¤Ã÷°±Æø¾ßÓÐ____£¨Ìî¡°Ñõ»¯ÐÔ¡±»ò¡°»¹Ô­ÐÔ¡±£©¡£
¢Ú DÖз´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________   _____¡¢                         .
¢ÛΪ·ÀÖ¹NO2 ÎÛȾ»·¾³£¬E×°ÖÃÖÐ×°µÄÊÔ¼Á¿ÉÒÔÊÇ                 ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄê¹ã¶«Ê¡¸ßÈýѧÄê»á¿¼£¨Àí×Û£©»¯Ñ§²¿·Ö ÌâÐÍ£ºÌî¿ÕÌâ

(16·Ö)°±ÆøÊÇÒ»ÖÖÖØÒªµÄ»ù´¡»¯¹¤Ô­ÁÏ£¬ÓÃ;¹ã·º¡£

£¨1£©ÔÚ΢µç×Ó¹¤ÒµÖУ¬°±Ë®¿É×÷¿ÌÊ´¼ÁH2O2 µÄÇå³ý¼Á£¬²úÎï²»ÎÛȾ»·¾³¡£¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2NH+ 3H2O2=         +6H2O

£¨2£©¹¤ÒµÖг£ÓÃÒÔÏ·´Ó¦ºÏ³É°±£ºN2+3H22NH¡÷H£¼0¡£Ä³ÊµÑéÊÒÔÚÈý¸ö²»Í¬Ìõ¼þµÄÃܱÕÈÝÆ÷ÖУ¬·Ö±ð¼ÓÈëN2ºÍH2£¬Å¨¶È¾ùΪc(N2) = 0.100mol/L, c(H2) = 0.300mol/L£¬½øÐз´Ó¦Ê±, N2µÄŨ¶ÈËæÊ±¼äµÄ±ä»¯Èçͼ¢Ù¡¢¢Ú¡¢¢ÛÇúÏßËùʾ¡£

¸Ã·´Ó¦Æ½ºâ³£ÊýµÄÊýѧ±í´ïʽΪ             £»ÊµÑé¢ÚƽºâʱH2µÄת»¯ÂÊΪ_____        ¡£

£¨3£©¾ÝͼËùʾ£¬¢Ú¡¢¢ÛÁ½×°ÖÃÖи÷ÓÐÒ»¸öÌõ¼þÓë¢Ù²»Í¬¡£ÇëÖ¸³ö£¬²¢ËµÃ÷ÅжϵÄÀíÓÉ¡£

¢ÚÌõ¼þ£º_______      ÀíÓÉ£º                                      ________

¢ÛÌõ¼þ£º_______      ÀíÓÉ£º                                      ________

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄê¹ã¶«Ê¡ÖÐɽÊиßÈý»¯Ñ§Ä£ÄâÊÔ¾í£¨¾Å£© ÌâÐÍ£ºÌî¿ÕÌâ

(16·Ö)°±ÆøÊÇÒ»ÖÖÖØÒªµÄ»ù´¡»¯¹¤Ô­ÁÏ£¬ÓÃ;¹ã·º¡£

ÔÚ΢µç×Ó¹¤ÒµÖУ¬°±Ë®¿É×÷¿ÌÊ´¼ÁH2O2 µÄÇå³ý¼Á£¬²úÎï²»ÎÛȾ»·¾³¡£¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2NH3+3H2O2=      +6H2O

¹¤ÒµÖг£ÓÃÒÔÏ·´Ó¦ºÏ³É°±£ºN2+3H22NH¡÷H£¼0¡£Ä³ÊµÑéÊÒÔÚÈý¸ö²»Í¬Ìõ¼þµÄÃܱÕÈÝÆ÷ÖУ¬·Ö±ð¼ÓÈëŨ¶È¾ùΪC(N2)=0.100mol/L, C(H2)=0.300mol/L½øÐз´Ó¦Ê±, N2µÄŨ¶ÈËæÊ±¼äµÄ±ä»¯ÈçÏÂͼ¢Ù¡¢¢Ú¡¢¢ÛÇúÏßËùʾ¡£

£¨1£©¸Ã·´Ó¦Æ½ºâ³£ÊýµÄÊýѧ±í´ïʽ             £»ÊµÑé¢ÚƽºâʱH2µÄת»¯ÂÊΪ_______

£¨2£©¾ÝͼËùʾ£¬¢Ú¡¢¢ÛÁ½×°ÖÃÖи÷ÓÐÒ»¸öÌõ¼þÓë¢Ù²»Í¬¡£ÇëÖ¸³ö£¬²¢ËµÃ÷ÅжϵÄÀíÓÉ¡£

¢ÚÌõ¼þ£º_______      ÀíÓÉ£º                                      ________

¢ÛÌõ¼þ£º_______      ÀíÓÉ£º                                      ________

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸