Question

°×ÓñµÄ»¯Ñ§Ê½¿ÉÓÃCa_xMg_ySi_pO₂₂£¨OH£©₂±íʾ£¨Ò²¿ÉÓÃCa¡¢Mg¡¢Si¡¢HµÄÑõ»¯Îï±íʾ£©£®
£¨l£©È¡8.10g°×Óñ·ÛÄ©×ÆÉÕÖÁºãÖØ£¬¹ÌÌå¼õÉÙÁË0.18g£¬Ôò°×ÓñµÄĦ¶ûÖÊÁ¿Îª______£®
£¨2£©ÁíÈ¡4.05g°×Óñ·ÛÄ©¼ÓÈë1mol/LµÄÑÎËál00mLÖгä·ÖÈܽ⣬×îÖյò»ÈÜÑõ»¯Îï2.40g£®¹ýÂË£¬½«ÂËÒººÍÏ´µÓÒººÏ²¢ºóÍùÆäÖмÓÈë×ãÁ¿µÄÌúм£¬µÃµ½ÆøÌå336mL£¨±ê×¼×´¿öÏ£©£®Ôò
¢Ùp=______£»
¢Ú°×ÓñµÄ»¯Ñ§Ê½£¨ÓÃÑõ»¯ÎïµÄÐÎʽ£©±íʾΪ______£®

Answer 1

£¨1£©°×Óñ·ÛÄ©×ÆÉÕºó£¬ÖÊÁ¿¼õÉÙµÄÊÇË®£¬¸ù¾ÝÇâÔ­×ÓÊغãµÃ°×ÓñºÍË®µÄ¹Øϵʽ£¬Éè°×ÓñµÄĦ¶ûÖÊÁ¿ÎªM£¬
Ca_xMg_ySi_pO₂₂£¨0H£©₂--H₂O
1mol 1mol

8.10g

M

0.18g

18g/mol

ËùÒÔM=810g/mol£¬
¹Ê´ð°¸Îª£º810£»
£¨2£©¢Ùͨ¹ýÌâÒâÖª£¬Ëá¹ýÁ¿£¬ËùÒÔ²»ÈÜÎïÊǶþÑõ»¯¹è£¬¸ù¾Ý¹èÔ­×ÓÊغãµÃ°×ÓñÓë¶þÑõ»¯¹èµÄ¹Øϵʽ£¬
Ca_xMg_ySi_pO₂₂£¨0H£©₂--pSiO₂£¬
1molpmol

4.05g

810g/mol

2.40g

60g/mol

1mol£ºpmol=

4.05g

810g/mol

£º

2.40g

60g/mol

½âµÃp=8£¬
¹Ê´ð°¸Îª£º8£»
¢Ú4.05g°×ÓñµÄÎïÖʵÄÁ¿Îªn=

4.05g

810g/mol

=0.005mol£»
ÓÉ FeCl₂¡«H₂¹Øϵʽ£¬µÃn£¨ FeCl₂£©=n£¨H₂£©=

0.336L

22.4L/mol

=0.015mol£»
ÓÉClÔ­×ÓÊغ㣬Áз½³Ì£º2¡Á0.005xmol+2¡Á0.005ymol+2¡Á0.015mol=0.1L¡Álmol/L£»
ÓÉ°×ÓñµÄÏà¶ÔÔ­×ÓÖÊÁ¿Îª810£¬Áз½³Ì£º40x+24y+28¡Á8+16¡Á22+17¡Á2=810£»
ÁªÁ¢·½³Ì£¬½âµÃ£ºx=2£»y=5
°×ÓñµÄ»¯Ñ§Ê½Îª£ºCa₂Mg₅Si₈O₂₂£¨0H£©₂£¬¸ù¾Ý»¯Ñ§Ê½¸Äд³ÉÏàÓ¦µÄÑõ»¯ÎïµÄÐÎʽ£¬°´ÕÕ»îÆýðÊôÑõ»¯Îï¡¢½Ï»îÆýðÊôÑõ»¯Îï¡¢SiO₂¡¢H₂OµÄ˳ÐòÀ´Êéд£¬ËùÒÔÆäÑõ»¯ÎïÐÎʽΪ£º2CaO?5MgO?8SiO₂?H₂O£¬
¹Ê´ð°¸Îª£º2CaO?5MgO?8SiO₂?H₂O£®