ÈçͼËùʾÊÇijÖÖ¼Ó¸ÆÊ³ÑεÄÍâ°ü×°±êÇ©ÉϵIJ¿·ÖÎÄ×Ö£¬Çë×ÐϸÔĶÁºó»Ø´ðÏÂÁÐÎÊÌ⣺

(1)´ËÍâ°ü×°±êÇ©Éϸƺ¬Á¿ÊÇÖ¸________(Ìî¡°µ¥Öʸơ±¡¢¡°Ì¼Ëá¸Æ¡±»ò¡°¸ÆÔªËØ¡±)£®

(2)ΪÁ˼ìÑé´ËʳÑÎÖÐÊÇ·ñº¬ÓÐ̼Ëá¸Æ£¬ÔÚ¼ÒÍ¥³ø·¿Àï¿ÉÑ¡ÓõÄÊÔ¼ÁÊÇ________£®

(3)ΪÁ˲ⶨ´ËʳÑÎÖÐ̼Ëá¸ÆµÄº¬Á¿£¬È¡10 g´ËʳÑÎÈÜÓÚË®£¬¼ÓÈë×ãÁ¿ÑÎËᣬÉú³É0.132 g¶þÑõ»¯Ì¼£®¼ÆËã¸Ã¼Ó¸ÆÊ³ÑÎÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

ÈçͼËùʾÊÇÎÒÊ¡Éú²úµÄijÖÖ¼Ó¸ÆÊ³Ñΰü×°±êÇ©ÉϵIJ¿·ÖÎÄ×Ö£®Çë×ÐϸÔĶÁºó»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©°ü×°±êÇ©Éϸƺ¬Á¿ÊÇÖ¸
¸ÆÔªËØ
¸ÆÔªËØ
£¨Ìî¡°µ¥Öʸơ±¡¢¡°Ì¼Ëá¸Æ¡±¡¢¡°¸ÆÔªËØ¡±ÖеÄÒ»ÖÖ£©£®
£¨2£©ÎªÁ˼ìÑé´ËÑÎÖÐÊÇ·ñº¬ÓÐ̼Ëá¸Æ£¬ÔÚ¼ÒÍ¥³ø·¿Àï¿ÉÑ¡ÓõÄÎïÖÊÊÇ
ʳ´×
ʳ´×
£®
£¨3£©ÎªÁ˲ⶨ´ËÑÎÖеĸÆÔªËصĺ¬Á¿£¬È¡10gÕâÖÖÑÎÈÜÓÚË®£¬¼ÓÈë×ãÁ¿µÄÑÎËᣬÉú³É0.132g¶þÑõ»¯Ì¼£®¢ÙÇë¼ÆËã´Ë¼Ó¸ÆÊ³ÑÎÖиÆÔªËصÄÖÊÁ¿·ÖÊý£¨Ìáʾ£º·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCO3+2HCl¨TCaCl2+H2O+CO2¡ü£®£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸