Question

£¨2013?º¼ÖÝ£©³¤ÆÚºôÎüPM2.5³¬±êµÄ¿ÕÆø£¬¶ÔÈËÌåµÄ½¡¿µ»á²úÉúÑÏÖصÄΣº¦£®PM2.5ÖеĿÅÁ£³É·Ö¸´ÔÓ£¬ÏõËáÑοÅÁ£ºÍÁòËáÑοÅÁ££¨Ö÷ÒªÒÔÏõËá°´ºÍÁòËá°´µÄÐÎʽ´æÔÚ£©ÊÇÆäÖеÄÖ÷Òª³É·Ö£®Ð¡Ã÷ÏëÓû¯Ñ§·½·¨´óÖ²ⶨPM2.5ÖÐÏõËá°´ºÍÁòËá°´µÄº¬Á¿¸ßµÍ£¬Ëû½«²É¼¯PM2.5µÄÂËĤÓÃÒ»¶¨Á¿µÄÕôÁóË®³ä·ÖÏ´µÓ£¬½«Ï´µÓÒº·ÖΪµÈÁ¿µÄV₁£¬V₂Á½·Ý£®
£¨1£©ÏÈÍùÏ´µÓÒºV₁ÖмÓÈë×ãÁ¿µÄÏõËá±µÈÜÒº£¬µÃµ½ÁòËá±µ³ÁµíM¿Ë£®Ï´µÓÒºV₁ÖÐÁòËá°´µÄÖÊÁ¿ÊǶàÉÙ¿Ë£¿£¨ÁÐʽ¼ÆË㣬Ïà¶ÔÔ­×ÓÖÊÁ¿£º£¨H-l£»  N-14£»   S-32£»  0-16£»  Ba-137£©
£¨2£©ÔÙÍùÏ´µÓÒºV₂ÖмÓÈë×ãÁ¿µÄÇâÑõ»¯ÄÆ£¬²¢¼ÓÈÈ£¬ÊÕ¼¯µ½°±ÆøN¿Ë£®£¨²»¿¼ÂÇ°±ÆøÈܽ⣩
ÒÑÖª£ºNH₄ NO₃+NaOH

¡÷   .

NaNO₃+H₂O+NH₃¡ü£»
£¨NH₄£©₂SO₄+2NaOH

¡÷   .

Na₂SO₄+2H₂O+2NH₃¡ü
ÈôÒªÖªµÀÏ´µÓÒºV₂ÖÐÏõËá淋ÄÖÊÁ¿£¬ÏÂÒ»²½¼ÆËãÐèÒªÏÈÇó³ö

ÁòËá狀ÍÇâÑõ»¯ÄÆÈÜÒº·´Ó¦Éú³É°±Æø

µÄÖÊÁ¿£®

Answer 1

·ÖÎö£ºÏõËá鱗»ÄܺÍÏõËá±µ·´Ó¦£¬Í¨¹ýÁòËá狀ÍÏõËá±µ·´Ó¦Éú³ÉµÄÁòËá±µµÄÖÊÁ¿£¬¿ÉÒÔÇó³öÁòËá淋ÄÖÊÁ¿£»
¸ù¾ÝÁòËá狀ÍÇâÑõ»¯ÄÆ·´Ó¦Éú³É°±ÆøµÄÖÊÁ¿£¬¿ÉÒÔÇó³öÏõËá狀ÍÇâÑõ»¯ÄÆ·´Ó¦Éú³É°±ÆøµÄÖÊÁ¿£¬½øÒ»²½¿ÉÒÔÇó³öÏõËá淋ÄÖÊÁ¿£®

½â´ð£º½â£º£¨1£©ÉèÏ´µÓÒºV₁ÖÐÁòËá淋ÄÖÊÁ¿ÎªX£¬
£¨NH₄£©₂SO₄+Ba£¨NO₃£©₂¨TBaSO₄¡ý+2NH₄NO₃
132                  233
 X                   M¿Ë

132

233

=

X

M¿Ë

X=

132

233

M¿Ë£»
´ð£ºÏ´µÓÒºV₁ÖÐÁòËá淋ÄÖÊÁ¿Îª

132

233

M¿Ë£®
£¨2£©ÁòËá狀ÍÏõËá臨¼Äܹ»ÓëÇâÑõ»¯ÄÆ·´Ó¦Éú³É°±Æø£¬×ÜÖÊÁ¿ÊÇN¿Ë£¬
ÔÚ£¨1£©ÖУ¬ÒѾ­Çó³öÁòËá淋ÄÖÊÁ¿£¬¿ÉÒÔ¸ù¾ÝÁòËá狀ÍÇâÑõ»¯ÄÆ·´Ó¦µÄ»¯Ñ§·½³ÌʽÇó³öÉú³É°±ÆøµÄÖÊÁ¿£¬
ÄÇôÏõËá狀ÍÇâÑõ»¯ÄÆ·´Ó¦Éú³ÉµÄ°±ÆøµÄÖÊÁ¿¾Í¿ÉÒÔÇó³ö£¬´Ó¶ø½øÒ»²½Çó³öÏõËá淋ÄÖÊÁ¿£®
¹ÊÌÁòËá狀ÍÇâÑõ»¯ÄÆÈÜÒº·´Ó¦Éú³É°±Æø£®

µãÆÀ£º±¾Ìâ±È½ÏÈÝÒ×£¬Ó¦¸Ã×¢ÒâµÄÊÇÈçºÎÇóÏ´µÓÒºV₂ÖУ¬ÏõËáï§ÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦Éú³ÉµÄ°±ÆøµÄÖÊÁ¿£®