Question

（12a^2m+1b^m+3-20a^m+1b^2m+4+4a^m+1b^m+2）÷4a^mb^m+1=______．

Answer 1

（12a^2m+1b^m+3-20a^m+1b^2m+4+4a^m+1b^m+2）÷4a^mb^m+1
=12a^2m+1b^m+3÷4a^mb^m+1-20a^m+1b^2m+4÷4a^mb^m+1+4a^m+1b^m+2÷4a^mb^m+1
=3a^m+1b²-5ab^m+3+ab．