Question

³£ÎÂÏ£¬¹ØÓÚ0.1mol/L NaHYÈÜÒº£¬ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ£¨¡¡¡¡£©

• A¡¢½«NaHY¾§Ìå¼ÓÈëË®ÖÐÒ»¶¨ÄÜ´Ù½øË®µÄµçÀë
• B¡¢ÈôNaHYµÄË®ÈÜÒºÏÔ¼îÐÔ£¬¸ÃÈÜÒºÖÐÁ£×ÓŨ¶È¹ØϵΪ£ºc £¨Na⁺£©£¾c £¨OH^-£©£¾c £¨H⁺£©£¾c £¨HY^-£©
• C¡¢ÈôÈÜÒºÖÐc£¨H⁺£©+c£¨H₂Y£©=c£¨OH^-£©+c£¨Y^2-£©£¬ÔòNaHYµÄË®ÈÜÒºÒ»¶¨ÏÔ¼îÐÔ
• D¡¢ÈôNaHYÈÜÒºµÄpH=4£¬¸ÃÈÜÒºÖÐÁ£×ÓŨ¶È¹ØϵΪ£ºc £¨Na⁺£©£¾c £¨HY^-£©£¾c £¨H⁺£©£¾c £¨Y^2-£©£¾c £¨H₂Y£©

Answer 1

¿¼µã£ºÀë×ÓŨ¶È´óСµÄ±È½Ï

רÌ⣺ÑÎÀàµÄË®½âרÌâ

·ÖÎö£ºA¡¢HY^-µÄµçÀë³Ì¶ÈÓëË®½â³Ì¶È´óС£¬¾ö¶¨Á˶ÔË®µÄµçÀë³Ì¶ÈµÄÓ°Ï죻
B¡¢NaHYµÄË®ÈÜÒºÏÔ¼îÐÔ£¬HY^-µÄµçÀë³Ì¶ÈСÓÚÆäË®½â³Ì¶È£¬ÇâÑõ¸ùÀë×ÓÀ´×ÔË®µÄµçÀëºÍHY^-µÄË®½â£»
C¡¢¸ù¾ÝÈÜÒºµçÖÐÐÔÔ­ÔòºÍÎïÁÏÊغãµÄ½Ç¶È·ÖÎö£»
D¡¢ÈôNaHYÈÜÒºµÄpH=4£¬ËµÃ÷HY^-µçÀë³Ì¶È´óÓÚHY^-Ë®½â³Ì¶È£®

½â´ð£º ½â£ºA¡¢ÈçµçÀë³Ì¶È´óÓÚË®½â³Ì¶È£¬ÒÖÖÆË®µÄµçÀ룬ÈçË®½â³Ì¶È´óÓÚµçÀë³Ì¶È£¬´Ù½øË®µÄµçÀ룬¹ÊA´íÎó£»
B¡¢ÈôNaHYµÄË®ÈÜÒºÏÔ¼îÐÔ£¬ËµÃ÷HY^-Ë®½â³Ì¶È´óÓÚHY^-µçÀë³Ì¶È£¬µ«Ë®½â³Ì¶ÈÒ»°ã½ÏÈõ£¬Ó¦´æÔÚc£¨HY^-£©£¾c£¨OH^-£©£¬¹ÊB´íÎó£»
C¡¢ÎÞÂÛÈÜÒº³ÊËáÐÔ£¬»¹ÊdzʼîÐÔ£¬ÈÜÒºÖдæÔÚµçºÉÊغ㣺c£¨H⁺£©+c£¨Na⁺£©=c£¨HY^-£©+2c£¨Y^2-£©+c£¨OH^-£©£¬ÎïÁÏÊغ㣺c£¨Na⁺£©=c£¨HY^-£©+c£¨Y^2-£©+c£¨H₂Y£©£¬¶þÕßÁªÊ½¿ÉµÃc£¨H⁺£©+c£¨H₂Y£©=c£¨OH^-£©+c£¨Y^2-£©£¬¹ÊC´íÎó£»
D¡¢ÈôNaHYÈÜÒºµÄpH=4£¬ËµÃ÷HY^-µçÀë³Ì¶È´óÓÚHY^-Ë®½â³Ì¶È£¬ÔòÓÐc£¨Y^2-£©£¾c£¨H₂Y£©£¬ÒòÈÜÒºÖл¹´æÔÚË®µÄµçÀ룬Ôòc£¨H⁺£©£¾c£¨Y^2-£©£¬¹Êc£¨Na⁺£©£¾c£¨HY^-£©£¾c£¨H⁺£©£¾c£¨Y^2-£©£¾c£¨H₂Y£©£¬¹ÊDÕýÈ·£»
¹ÊÑ¡D£®

µãÆÀ£º±¾Ì⿼²éÀë×ÓŨ¶ÈµÄ´óС±È½Ï£¬ÌâÄ¿ÄѶÈÖеȣ¬±¾ÌâÒ×´íµãΪC£¬×¢Òâ´ÓÈÜÒºµÄµçºÉÊغãºÍÎïÁÏÊغãµÄ½Ç¶È·ÖÎö£¬ÎÞÂÛÊÇËáÐÔÈÜÒº»¹ÊǼîÐÔÈÜÒº£¬¶¼´æÔÚc£¨H⁺£©+c£¨H₂Y£©=c£¨OH^-£©+c£¨Y^2-£©£®