Question

Çë²Î¿¼ÌâÖÐͼ±í£¬ÒÑÖªE1£½134 kJ¡¤mol£­1¡¢E2£½368 kJ¡¤mol£­1£¬¸ù¾ÝÒªÇó»Ø´ðÎÊÌ⣺

¡¡

£¨1£©Í¼¢ñÊÇ1 mol NO2(g)ºÍ1 mol CO(g)·´Ó¦Éú³ÉCO2ºÍNO¹ý³ÌÖеÄÄÜÁ¿±ä»¯Ê¾Òâͼ£¬ÈôÔÚ·´Ó¦ÌåϵÖмÓÈë´ß»¯¼Á£¬·´Ó¦ËÙÂÊÔö´ó£¬E1µÄ±ä»¯ÊÇ________(Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±»ò¡°²»±ä¡±£¬ÏÂͬ)£¬¦¤HµÄ±ä»¯ÊÇ________¡£Çëд³öNO2ºÍCO·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º________________________________¡£

£¨2£©¼×´¼ÖÊ×Ó½»»»Ä¤È¼Áϵç³ØÖн«¼×´¼ÕôÆûת»¯ÎªÇâÆøµÄÁ½ÖÖ·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÈçÏ£º

¢ÙCH3OH(g)£«H2O(g)=CO2(g)£«3H2(g)¦¤H£½£«49£®0 kJ¡¤mol£­1

¢ÚCH3OH(g)£«O2(g)=CO2(g)£«2H2(g)¦¤H£½£­192£®9 kJ¡¤mol£­1

ÓÖÖª¢ÛH2O(g)=H2O(l)¡¡¦¤H£½£­44 kJ¡¤mol£­1£¬Ôò¼×´¼ÕôÆûȼÉÕΪҺ̬ˮµÄÈÈ»¯Ñ§·½³ÌʽΪ______________________¡£

£¨3£©Èç±íËùʾÊDz¿·Ö»¯Ñ§¼üµÄ¼üÄܲÎÊý£º

»¯Ñ§¼ü	P¡ªP	P¡ªO	O=O	P=O
¼üÄÜ/kJ¡¤mol£­1	a	b	c	x

 

ÒÑÖª°×Á×µÄȼÉÕÈÈΪd kJ¡¤mol£­1£¬°×Á×¼°ÆäÍêȫȼÉյIJúÎïµÄ½á¹¹Èçͼ¢òËùʾ£¬Ôò±íÖÐx£½________ kJ¡¤mol£­1(Óú¬a¡¢b¡¢c¡¢dµÄ´ú±íÊýʽ±íʾ)¡£

 

Answer 1

£¨1£©¼õС¡¡²»±ä¡¡NO2(g)£«CO(g)=CO2(g)£«NO(g)¡¡¦¤H£½£­234 kJ¡¤mol£­1

£¨2£©CH3OH(g)£«O2(g)=CO2(g)£«2H2O(l)¡¡¦¤H£½£­764£®7 kJ¡¤mol£­1

£¨3£© (d£«6a£«5c£­12b)

¡¾½âÎö¡¿£¨1£©¹Û²ìͼÏñ£¬E1ӦΪ·´Ó¦µÄ»î»¯ÄÜ£¬¼ÓÈë´ß»¯¼Á·´Ó¦µÄ»î»¯ÄܽµµÍ£¬µ«ÊǦ¤H²»±ä£»1 mol NO2(g)ºÍ1 mol CO(g)·´Ó¦Éú³ÉCO2ºÍNOµÄ·´Ó¦ÈÈÊýÖµ¼´·´Ó¦ÎïºÍÉú³ÉÎïµÄÄÜÁ¿²î£¬Òò´Ë¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪNO2(g)£«CO(g)=CO2(g)£«NO(g)¡¡¦¤H£½£­234 kJ¡¤mol£­1¡£

£¨2£©¹Û²ì·½³Ìʽ£¬ÀûÓøÇ˹¶¨ÂÉ£¬½«Ëù¸øÈÈ»¯Ñ§·½³Ìʽ×÷ÈçÏÂÔËË㣺¢Ú¡Á3£­¢Ù¡Á2£«¢Û¡Á2£¬¼´¿ÉÇó³ö¼×´¼ÕôÆûȼÉÕµÄÈÈ»¯Ñ§·½³Ìʽ¡£

£¨3£©°×Á×ȼÉյĻ¯Ñ§·½³ÌʽΪP4£«5O2P4O10£¬½áºÏͼ¢òÖа×Á×¼°ÆäÍêȫȼÉÕ²úÎïµÄ½á¹¹£¬¸ù¾Ý¡°·´Ó¦ÈÈ£½·´Ó¦Îï¼üÄÜ×ܺͣ­Éú³ÉÎï¼üÄÜ×ܺ͡±ÓëȼÉÕÈȸÅÄî¿ÉµÃµÈʽ£º6a£«5c£­(4x£«12b)£½£­d£¬¾Ý´Ë¿ÉµÃx£½ (d£«6a£«5c£­12b)¡£