22. 解:(1)设购买乙种电冰箱台.则购买甲种电冰箱台. 丙种电冰箱台.根据题意.列不等式:·························································· 1分 .······················································· 3分 解这个不等式.得.·························································································· 4分 至少购进乙种电冰箱14台.······················································································ 5分 (2)根据题意.得.·············································································· 6分 解这个不等式.得.·························································································· 7分 由(1)知. . 又为正整数. .··········································································································· 8分 所以.有三种购买方案: 方案一:甲种电冰箱为28台.乙种电冰箱为14台.丙种电冰箱为38台, 方案二:甲种电冰箱为30台.乙种电冰箱为15台.丙种电冰箱为35台, 方案三:甲种电冰箱为32台.乙种电冰箱为16台.丙种电冰箱为32台.·················· 10分 【查看更多】

 

题目列表(包括答案和解析)

(本小题满分10分)解方程或不等式组:

    ⑴ 解方程:   

 

查看答案和解析>>

运算求解(本小题满分10分)

(1)解不等式,并把它的解集在数轴上表示出来.           

(2)解方程: 

 

查看答案和解析>>

(本小题满分10分)解不等式组或方程

1.(1) 

 2.(2)

 

查看答案和解析>>

(本小题满分10分)
学习过三角函数,我们知道在直角三角形中,一个锐角的大小与两条边长的比值相互唯一确定,因此边长与角的大小之间可以相互转化.
类似的,可以在等腰三角形中建立边角之间的联系,我们定义:等腰三角形中底边与腰的比叫做顶角的正对(sad).如图,在△ABC中,AB=AC,顶角A的正对记作sadA,这时sad A=.容易知道一个角的大小与这个角的正对值也是相互唯一确定的.
根据上述对角的正对定义,解下列问题:

(1)sad 的值为(  )
A.B.1C.D.2
(2)对于,∠A的正对值sad A的取值范围是        .
(3)已知,其中为锐角,试求sad的值.

查看答案和解析>>

(本小题满分10分)解方程或不等式组:

    ⑴ 解方程:   

 

查看答案和解析>>


同步练习册答案