25. 解:(1)①轴.轴. 四边形为矩形. 轴.轴. 四边形为矩形. 轴.轴. 四边形均为矩形.············ 1分 . . . . . . .······························································································ 2分 ②由(1)知. . .············································································································ 4分 . .································································································ 5分 . .············································································································· 6分 轴. 四边形是平行四边形. .············································································································· 7分 同理. .············································································································· 8分 (2)与仍然相等.························································································· 9分 . . 又. .································· 10分 . . . . . .············································································································ 11分 轴. 四边形是平行四边形. . 同理. .·········································································································· 12分 【查看更多】

 

题目列表(包括答案和解析)

(本题满分12分)如图,直线l1的解析表达式为:,且l1与x轴
交于点D,直线l2经过点A,B,直线l1,l2交于点C.
【小题1】(1)求直线l2的函数关系式;
【小题2】(2)求△ADC的面积;
【小题3】(3)若点H为坐标平面内任意一点,在坐标平面内是否存在这样的点H,使以A、D、C、H为顶点的四边形是平行四边形?若存在,请直接写出点H的坐标;若不存在,请说明理由.

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(本题满分12分)如图,直线l1的解析表达式为:,且l1与x轴
交于点D,直线l2经过点A,B,直线l1,l2交于点C.
【小题1】(1)求直线l2的函数关系式;
【小题2】(2)求△ADC的面积;
【小题3】(3)若点H为坐标平面内任意一点,在坐标平面内是否存在这样的点H,使以A、D、C、H为顶点的四边形是平行四边形?若存在,请直接写出点H的坐标;若不存在,请说明理由.

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(本题满分12分)如图,直线l1的解析表达式为:,且l1与x轴
交于点D,直线l2经过点A,B,直线l1,l2交于点C.
小题1:(1)求直线l2的函数关系式;
小题2:(2)求△ADC的面积;
小题3:(3)若点H为坐标平面内任意一点,在坐标平面内是否存在这样的点H,使以A、D、C、H为顶点的四边形是平行四边形?若存在,请直接写出点H的坐标;若不存在,请说明理由.

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(本小题满分12分)

在平面直角坐标系xOy中,抛物线的解析式是y =+1,点C的坐标为(–4,0),平行四边形OABC的顶点A,B在抛物线上,AB与y轴交于点M,已知点Q(x,y)在抛物线上,点P(t,0)在x轴上.

 (1) 写出点M的坐标;

 (2) 当四边形CMQP是以MQ,PC为腰的梯形时.

① 求t关于x的函数解析式和自变量x的取值范围;

② 当梯形CMQP的两底的长度之比为1:2时,求t的值.

 

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(本小题满分12分)
在平面直角坐标系xOy中,抛物线的解析式是y =+1,点C的坐标为(–4,0),平行四边形OABC的顶点A,B在抛物线上,AB与y轴交于点M,已知点Q(x,y)在抛物线上,点P(t,0)在x轴上.

(1) 写出点M的坐标;
(2) 当四边形CMQP是以MQ,PC为腰的梯形时.
① 求t关于x的函数解析式和自变量x的取值范围;
② 当梯形CMQP的两底的长度之比为1:2时,求t的值.

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