练习册

  • 练习册
  • 试题
    Find the inverse of the following matrices: (i) (ii) (iii) (iv) This leads us into the realm of simultaneous equations: Consider the problem of solving the set of simultaneous equations: This can be represented as The purpose of solving these equations is to find the values of x and y. Therefore we need to remove the matrix at the front of the column matrix. This can be done by multiplying by the inverse of . Using the method above or by using your calculator find the inverse which is . Therefore the solution is x = -2 and y = 3. Type in the matrix you are working with: Use the ANS feature to find the inverse: Multiply the inverse by the answer matrix. This of course means we can solve very complex sets of simultaneous equations with ease. Exercise 4: 【查看更多】

     

    题目列表(包括答案和解析)

    以下是用Scilab编写的程序，输出a，b的含义是________________．

    a=input(“please give the first number”)

    b=input(“please give the second number”)

    while　a＜＞b

    　　　if　a＞=b

    　　　　a=a－b；

    　　　else

    　　　　b=b－a；

    　　end

    end

    print(％io(2)，a，b)

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    以下是用Scilab编写的程序，输出a，b的含义是________________．

    a=input(“please give the first number”)

    b=input(“please give the second number”)

    while　a＜＞b

    　　　if　a＞=b

    　　　　a=a－b；

    　　　else

    　　　　b=b－a；

    　　end

    end

    print(％io(2)，a，b)

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    i是虚数单位，
    5i
    2-i
    =（　　）
    A、1+2iB、-1-2i
    C、1-2iD、-1+2i

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    若f（tanx）=cos2x，则f(-tan
    π
    3
    )    的值是（　　）
    A、
    1
    2
    B、-
    		3
    2
    C、-
    1
    2
    D、
    		3
    2

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    过点A（a，a）可作圆x2+y2-2ax+a2+2a-3=0的两条切线，则实数a的取值范围为（　　）
    A、a＜-3或1＜a＜
    3
    2
    B、1＜a＜
    3
    2
    C、a＜-3
    D、-3＜a＜1或a＞
    3
    2

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