解:(1)105×32-3232÷32,
=3360-101,
=3159;
(2)125×3

×0.8×

,
=125×0.8×(

×

),
=100×1,
=100;
(3)(

-

)×63-

,
=

×63-

×63-

,
=9-7-

,
=2-

,
=1

;
(4)210.5×[(6.05-3.35)÷1.5],
=210.5×[(6.05-3.35)÷1.5],
=210.5×[2.7÷1.5],
=210.5×1.8,
=378.9;
(5)(

-

)×

÷

,
=(

-

)×

×2,
=

×

×2,
=

;
(6)0.75×16+

,
=0.75×16+0.75×5-0.75,
=(16+5-1)×0.75,
=20×0.75,
=15.
分析:(1)把32看作30+2,根据乘法分配律求出105×(30+2)=3150+210,同时计算出3232÷32=101,然后通过拆项和加法结合律简算;
(2)运用乘法交换律和结合律简算;
(3)运用乘法分配律计算(

-

)×63,然后与

相减即可;
(4)按运算顺序进行计算,先算小括号内的减法,再算中括号内的除法,最后算括号外的乘法;
(5)把除法改为乘法,然后按运算顺序计算,此题应注意约分;
(6)把分数和百分数化为小数,用乘法分配的逆运算简算.
点评:此题考查了学生对四则混合运算顺序的掌握,以及运用运算定律简算的能力.