Question

                                                            

                                                            

实验室用锌和稀硫酸反应制取氢气（反应方程式：Zn+H₂SO₄═ZnSO₄+H₂↑），现用6.5g锌与足量稀硫酸反应，求生成氢气的质量是多少？                                                

Answer 1

【考点】根据化学反应方程式的计算．                             

【专题】有关化学方程式的计算．                                 

【分析】欲正确解答本题，需根据化学方程式得出各物质之间的质量比，列出比例式，通过计算得出生成氢气的质量．                                                            

【解答】解：设生成氢气的质量为x，                              

Zn+H₂SO₄═ZnSO₄+H₂↑                                          

65              2                                           

6.5g            x                                           

                                                    

x=0.2g                                                      

答：生成氢气的质量为0.2g．                                     

【点评】本题主要考查学生运用化学方程式进行计算的能力．