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【题目】对于函数fxax2bx+ca∈R,且a≠0,在使fx≥M成立的所有实数M中,我们把M的最大值Mmax叫做函数fxax2bx+c的下确界,则fx=x2-4x+6的下确界为________.

【答案】2

【解析】fx=x2-4x+6=x-22+2≥2,则fx=x2-4x+6的下确界为2.

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