ÏÂÁйØÓÚ·´Ó¦ÈȵÄÃèÊöÖÐÕýÈ·µÄÊÇ

A. ÓÉH£«(aq)£«OH£­(aq)===H2O£¨l£©¦¤H£½£­57.3 kJ¡¤mol£­1¿ÉÖª£ºº¬1 mol CH3COOHµÄÈÜÒºÓ뺬1 mol NaOHµÄÈÜÒº»ìºÏ£¬·Å³öÈÈÁ¿Îª57.3 kJ

B. ÓÉC(ʯī£¬s)===C(½ð¸Õʯ£¬s)¡¡¦¤H£½1.9 kJ¡¤mol£­1£¬¿ÉÖª£ºÊ¯Ä«±È½ð¸Õʯ¸üÎȶ¨

C. 500¡æ¡¢30 MPaÏ£¬½«0.5 mol N2ºÍ1.5 mol H2ÖÃÓÚÃܱÕÈÝÆ÷Öгä·Ö·´Ó¦Éú³ÉNH3(g)£¬·ÅÈÈ19.3 kJ£¬ÆäÈÈ»¯Ñ§·½³ÌʽΪN2(g)£«3H2(g)2NH3(g) ¦¤H£½£­38.6 kJ¡¤mol£­1

D. ¼×ÍéµÄ±ê׼ȼÉÕÈÈ£¨¦¤H£©Îª£­890.3 kJ¡¤mol£­1£¬Ôò¼×ÍéȼÉÕµÄÈÈ»¯Ñ§·½³Ìʽ¿É±íʾΪCH4(g)£«2O2(g)===CO2(g)£«2H2O(g)¡¡¦¤H£½£­890.3 kJ¡¤mol£­1

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016~2017ѧÄê½­ËÕÊ¡ËÞǨÊи߶þѧҵˮƽ²âÊÔÄ£Ä⣨¶þ£©»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

¹¤ÒµÉÏÉú²úµª»¯¹èÌÕ´É·´Ó¦Îª3SiCl4£«2N2£«6H2Si3N4£«12HCl£¬Óйظ÷´Ó¦Ëµ·¨ÕýÈ·µÄÊÇ

A. SiCl4ÊÇÑõ»¯¼Á B. N2ʧµç×Ó C. H2±»»¹Ô­ D. N2·¢Éú»¹Ô­·´Ó¦

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄê¹ã¶«Ê¡Õ¿½­Êи߶þÉÏѧÆÚÆÚÄ©µ÷Ñп¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁи÷ÎïÖÊͶÈëË®ÖУ¬Òò´Ù½øË®µÄµçÀë¶øʹÈÜÒº³ÊËáÐÔµÄÊÇ

A. NaHSO4 B. Na3PO4 C. CH3COOH D. NH4Cl

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄ긣½¨Ê¡ÕÄÖÝÊи߶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÔÚ³£ÎÂÏ£¬½«pH£½9µÄNaOHÈÜÒºÓëpH£½11µÄNaOHÈÜÒºµÈÌå»ý»ìºÏºó£¬ÈÜÒºµÄpH×î½Ó½üÓÚ

A. 9.3 B. 9.7 C. 10 D. 10.7

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄ긣½¨Ê¡ÕÄÖÝÊи߶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

΢ÉúÎïµç³ØÊÇÖ¸ÔÚ΢ÉúÎïµÄ×÷ÓÃϽ«»¯Ñ§ÄÜת»¯ÎªµçÄܵÄ×°Öã¬Æ乤×÷Ô­ÀíÈçͼËùʾ¡£ÏÂÁÐÓйØ΢ÉúÎïµç³ØµÄ˵·¨´íÎóµÄÊÇ

A. Õý¼«·´Ó¦ÖÐÓÐCO2Éú³É

B. ΢ÉúÎï´Ù½øÁË·´Ó¦Öеç×ÓµÄתÒÆ

C. ÖÊ×Óͨ¹ý½»»»Ä¤´Ó¸º¼«ÇøÒÆÏòÕý¼«Çø

D. µç³Ø×Ü·´Ó¦ÎªC6H12O6+6O2=6CO2+6H2O

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄêºÓ±±Ê¡ÕżҿÚÊи߶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º¼ò´ðÌâ

¢ñ£®ÊÒÎÂÏ£¬½«Ò»ÔªËáHAµÄÈÜÒººÍKOHÈÜÒºµÈÌå»ý»ìºÏ£¨ºöÂÔ»ìºÏºóÈÜÒºµÄÌå»ý±ä»¯£©£¬ÊµÑéÊý¾ÝÈçÏÂ±í£º

ʵÑéÐòºÅ

ÆðʼŨ¶È£¯£¨mol¡¤L£­1£©

·´Ó¦ºóÈÜÒºµÄpH

c£¨HA£©

c£¨KOH£©

¢Ù

0.1

0.1

9

¢Ú

x

0.2

7

Çë»Ø´ð£º

£¨1£©HAÈÜÒººÍKOHÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽΪ________¡£

£¨2£©ÊµÑé¢Ù·´Ó¦ºóµÄÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨OH£­£©£½________mol¡¤L£­1£»x________0.2mol¡¤L£­1£¨Ìî¡°£¾¡±¡°£¼¡±»ò¡°£½¡±£©¡£

£¨3£©ÏÂÁйØÓÚʵÑé¢Ú·´Ó¦ºóµÄÈÜҺ˵·¨²»ÕýÈ·µÄÊÇ________£¨Ìî×Öĸ£©¡£

a£®ÈÜÒºÖÐÖ»´æÔÚ×ÅÁ½¸öƽºâ

b£®ÈÜÒºÖУºc£¨A£­£©£«c£¨HA£©£¾0.1mol¡¤L£­1

c£®ÈÜÒºÖУºc£¨K£«£©£½c£¨A£­£©£¾c£¨OH£­£©£½c£¨H£«£©

¢ò£®ÒÑÖª2H2£¨g£©£«O2£¨g£©£½2H2O£¨1£© ¦¤H£½£­572kJ¡¤mol£­1¡£Ä³ÇâÑõȼÁϵç³ØÒÔÊèËɶà¿×ʯī°ôΪµç¼«£¬KOHÈÜҺΪµç½âÖÊÈÜÒº¡£

£¨4£©Ð´³ö¸Ãµç³Ø¹¤×÷ʱ¸º¼«µÄµç¼«·´Ó¦Ê½________¡£

£¨5£©Èô¸ÃÇâÑõȼÁϵç³ØÿÊÍ·Å228.8kJµçÄÜʱ£¬»áÉú³É1molҺ̬ˮ£¬Ôò¸Ãµç³ØµÄÄÜÁ¿×ª»¯ÂÊΪ________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄêºÓ±±Ê¡ÕżҿÚÊи߶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÒÑ֪ζÈTʱˮµÄÀë×Ó»ý³£ÊýΪKW£¬¸ÃζÈÏ£¬½«Å¨¶ÈΪamol¡¤L£­1µÄÒ»ÔªËáHAÓëbmol¡¤L£­1µÄÒ»Ôª¼îBOHµÈÌå»ý»ìºÏ£¬¿ÉÅж¨¸ÃÈÜÒº³ÊÖÐÐÔµÄÒÀ¾ÝÊÇ

A. a£½b

B. »ìºÏÈÜÒºµÄpH£½7

C. »ìºÏÈÜÒºÖÐc(H+)=mol?L-1

D. »ìºÏÈÜÒºÖУ¬c£¨H£«£©£«c£¨B£«£©£½c£¨OH£­£©£«c£¨A£­£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄêºÓ±±Ê¡ÕżҿÚÊиßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º¼ò´ðÌâ

¹¤ÒµÉÏÓóàÌú¿ó£¨º¬Fe2O3¡¢FeO£¬Ò²º¬ÓÐAl2O3¡¢MnO2¡¢CuO¡¢SiO2µÈ£©ÖƱ¸ÂÌ·¯£¨FeSO4¡¤7H2O£©µÄÁ÷³ÌÈçÏ£º

£¨1£©ÂËÒº¢ñÖÐËùº¬µÄÒõÀë×ÓÓÐ________¡£

£¨2£©ÊÔ¼ÁaΪ________£¬ÊÔ¼ÁbͶÈëµ½ÂËÒº¢ò·¢ÉúµÄËùÓз´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________¡£

£¨3£©ÊµÑéÊÒÖвÙ×÷¢ÙËùÐèµÄ²£Á§ÒÇÆ÷ÓÐ________¡£

£¨4£©²Ù×÷¢ÜµÄÃû³ÆΪ________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄêÁÉÄþÊ¡´óÁ¬Êи߶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ£¨ÎÄ£©»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÔÚʵÑéÊÒÖУ¬ÏÂÁÐʹʴ¦Àí»òʵÑé²Ù×÷ÕýÈ·µÄÊÇ

A. ÓдóÁ¿µÄÂÈÆøй©ʱ£¬ÓÃÉÕ¼îÈÜÒº½þʪÈí²¼ÃÉÃ棬²¢Ñ¸ËÙÀ뿪ÏÖ³¡

B. ½ðÊôÄÆ×Å»ðȼÉÕʱ£¬ÓÃÅÝÄ­Ãð»ðÆ÷Ãð»ð

C. ÉÙÁ¿Å¨ÁòËáÕ´ÔÚƤ·ôÉÏ£¬Á¢¼´ÓÃÇâÑõ»¯ÄÆÈÜÒº³åÏ´

D. ¹ýÂËʱ£¬²£Á§°ôÓëÈý²ãÂËÖ½µÄÒ»±ß½Ó´¥

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸