25小时另外4人步行了1.25km.此时他们与考场的距离为(km) ·······························································——青夏教育精英家教网—

25小时另外4人步行了1.25km.此时他们与考场的距离为(km) ······························································································································ 7分设汽车返回后先步行的4人相遇. .解得．汽车由相遇点再去考场所需时间也是．······················································· 9分所以用这一方案送这8人到考场共需．所以这8个个能在截止进考场的时刻前赶到．······················································· 10分方案2:8人同时出发.4人步行.先将4人用车送到离出发点的处.然后这4个人步行前往考场.车回去接应后面的4人.使他们跟前面4人同时到达考场．···························································· 6分由处步行前考场需. 汽车从出发点到处需先步行的4人走了. 设汽车返回(h)后与先步行的4人相遇.则有.解得. ······························································································································ 8分所以相遇点与考场的距离为．由相遇点坐车到考场需．所以先步行的4人到考场的总时间为. 先坐车的4人到考场的总时间为. 他们同时到达.则有.解得．将代入上式.可得他们赶到考场所需时间为．．他们能在截止进考场的时刻前到达考场【查看更多】

题目列表(包括答案和解析)

某学校的一名学生从家到校去上课，他先以每小时4千米的速度步行了全程的一半后，再搭上速度为20千米/时的顺路班车，所以比原来需要的时间早到了一小时，问他家到学校的距离是多少千米？

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一位法官在审理一起盗窃案中，对涉及到的四名嫌疑犯甲、乙、丙、丁进行了审问。四人分别供述如下：甲说：“罪犯在乙、丙、丁三人之中。” 乙说：“我没有做案，是丙偷的。” 丙说：“在甲和丁之间有一个是罪犯。” 丁说：“乙说的是事实。” 经过调查，证实这四人中有两人说的是真话，另外两人说了假话，那么罪犯是（）。

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某工厂现有工人2300人，与去年相比男工人增加了25％，女工人减少了25％，全厂人数增加了15％，设去年全厂有男工人x人，女工人y人，那么可列方程组

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A．