已知点A(a.).B(2a.y).C(3a.y)都在抛物线上. (1)求抛物线与x轴的交点坐标, (2)当a=1时.求△ABC的面积, (3)是否存在含有.y.y.且与a无关的等式?如果存在.试给出一个.并加以证明,如果不存在.说明理由. 解:(1)由5=0.·············································································· 得..·················································································· ∴抛物线与x轴的交点坐标为(0.0).(.0).······································· (2)当a=1时.得A.B.C.······························ 分别过点A.B.C作x轴的垂线.垂足分别为D.E.F.则有 =S - - ···················································· =--···································· =5········································································ (3)如:. ········································································· 事实上. =45a2+36a. 3()=3[5×(2a)2+12×2a-(5a2+12a)] =45a2+36a.············ ∴. ···················································································· 查看更多

 

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如图,在方格纸中,我们把每个小正方形的顶点称为格点,已知点A、B、C都在格点上,且每个小正方形的边长都为1.
(1)画线段AB,并过点C作CD⊥AB,垂足为点D;
(2)连结AC、BC.
①求△ABC的面积;②已知AB=5,
求(1)中线段CD的长.

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13、兰州市“安居工程”新建成的一批楼房都是8层高,房子的价格y(元/平方米)随楼层数x(楼)的变化而变化(x=1,2,3,4,5,6,7,8);已知点(x,y)都在一个二次函数的图象上(如图所示),则6楼房子的价格为
2080
元/平方米.

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某市“安居工程”新建成的经济房都是8层高,房子的价格y(元/m2)随楼层数x(楼)的变化而变化(x=1,2,3,4,5,6,7,8);已知点(x,y)都在一个二次函数的图象(如图)上,对称轴方程为:x=4,则6楼房子的价格为
3080
3080
元/m2

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已知点A,B,C都在直线l上,且AB=6cm,BC=2cm,则A,C两点的距离是
4cm或8cm
4cm或8cm

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某市“安居工程”新建成的一批楼房都是8层高,房子的价格y(元/平方米)随楼层数x(楼)的变化而变化(x=1,2,3,4,5,6,7,8);已知点(xy)都在一个二次函数的图象上(如图所示),则6楼房子的价格为__________元/平方米

.

 

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