已知:5x2-2xy+y2+4x+1=0,求x,y的值. 查看更多

 

题目列表(包括答案和解析)

已知5x2+2y2+2xy-14x-10y+17=0,则x=________,y=________.

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15、已知M=3x2-2xy+y2,N=2x2+xy-3y2,则M+N=
5x2-xy-2y2
,M-N=
x2-3xy+4y2

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已知多项式5x2-2mxy-13y2-x+y-1与多项式4x2-2xy-10y2+x-y+1的和不含xy项,求m的值.

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计算与化简:
(1) a3b+(a3b-2c)-2(a3b-c)
(2)-4xy+3(
1
3
xy-2x)

(3)(4a2-2a-6)-2(2a2-2a-5)
(4)2x-(3x-
x-1
2
)+[5x-
3
2
(x-2)]
(5) 3(4x2-3x+2)-2(1-4x2+x)
(6)已知A=3x2-2xy+y2,B=5x2-4xy-2y2,求A-2B.

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(1)化简(4x2-2x-1)-{5x2-[8x-2-3(x2+x)]-x2}
(2)先化简,5abc-{2a2b-[3abc-(4ab2-a2b)]}+3ab2,其a=1,b=-1,c=-
13

(3)已知(x-2)2+|xy-4|=0,先化简再求值.3x2y+{-2x2y-[-2xy+(x2y-4x2)-xy]+xy2}.

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