设是函数的反函数.则与的大小关系为 查看更多

 

题目列表(包括答案和解析)

设随机变量,记,则

A.        B.     C.       D. 的大小关系不定

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阅读下面的短文,然后按照要求写一篇150词左右的英文短文。

The Use of Examinations

A good education should make people think for themselves. But the exam can never do anything like that.

First, examinations are second to none because it brings anxiety to students. As soon as a child begins school, he enters a world of terrible competition.

Second, exams do not interest students to read or to learn widely. They do not help students to look for more and more knowledge, but try to put as much as possible into the students’ head.

Third, they lower the standards of teaching, for they do not give any freedom to teachers to decide what to teach. Teachers themselves have no choice but to train their students in exam techniques. The most successful students are not always the best educated but the best trained in the technique of exams.

Fourth, they can tell you nothing about a person’s true ability. The exams are often nothing more than a subjective assessment(主观评价) by some examiners.

However, if there are no exams, few students or even no one will do any revision or study!

【写作内容】

1.       概括短文的内容要点,该部分的词数大约30;

2.       就“中学生学习成绩与能力的相互关系”为题发表你的看法,至少包括以下的内容要点,该部分的词数大约120。

(1)    你每次考试之前的心情如何?

(2)    你是如何备考的?

(3)    你认为考试成绩能反映你的学习能力吗?

【写作要求】

你可以使用实例或其他论述方法支持你的观点,也可以参照阅读材料的内容,但不得直接引用原文中的句子。

   【评分标准】

    概括准确、语言规范、内容合适、篇章连贯。

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此题要求改正所给短文中的错误。对标有题号的每一行做出判断:
如无错误,该行右边横线上画一个勾(√);
如有错误(每行只有一个错误),则按下列情况改正:
此行多一个词:把多余的词用斜线(\)划掉,在该行右边横线上写出该词,并也用斜线划掉。
此行缺一个词:在缺词处加一个漏字符号(∧),在该行右边横线上写出该加的词。
此行错一个词:在错的词下划一横线,在该行右边横线上写出改正后的词。
注意:原行没有错的不要改。
(请在答题卡的指定位置作答)
第三节书法展示(满分5分)
请抄写下面的文章,注意本题是按照书法的好坏评分的,格式要求与原文一致。
建议:先在草稿纸上练习,找找手感,再答卷。
My Hometown
Welcome to my hometown which is located on the Bohai Bay. It is very beautiful! Living here makes you feel quite good. Miles of beaches stretch along the coast. You can lie on the beach, bathing in the sun and enjoying the fresh air. The blue sky and beautiful scenery here will make you relaxed and excited.
People here are very friendly and considerate. They are ready to offer help to people from the country and abroad. There are plenty of tidy hotels and inns for visitors to stay in. Most importantly, you can enjoy all kinds of tasty special foods. I am sure you will have a good time here. 
(请在答题卡的指定位置作答)

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请阅读下列应用文及其相关信息,并按照要求匹配信息。请在答题卡上将对应题号的相应选项字母涂黑。下面是一篇应用文及其应用场合的信息, 请阅读下列应用文和相关信息,并按照要求匹配信息。
首先, 请阅读下列六则卡通人物的性格介绍:
Why do you remember Hello Kitty, Snoopy and all the other cartoon characters? What makes you love them? Well, maybe because they're like the people around you. Think about it! You may find a friend or classmate who is like them.
A. As sweet as Hello Kitty: She likes to eat cake. She loves to make new friends. She likes to ask friends to her parties. Her smile is so lovely.
B. As clever as Snoopy: He went to school when he was nine. He learned to use a typewriter in two years! He thinks a lot. He is so clever that you like to be with him.
C. As sarcastic (讽刺的) as Garfield: He sits happily in the seat and says sharp words to you. Sometimes he is not nice. He doesn't really like you? He thinks you're a fool? No, in his heart, he loves you. He is a friend with hard words but a warm heart.
D. As naughty as MashiMaro: He doesn't look like a good boy. He has sleepy eyes and looks naughty. He always plays tricks. So you may get angry with him and don't like him very much. His mind is active and full of ideas. He tries to be big and catch your eyes. But, he' s still a child.
E. As confident as Prince of Tennis: He has faith in himself and always wants to win.
F. As friendly as Mickey: He is clever and kind. He has a good heart and is glad to help others. Everyone likes to turn to him for help whenever they are in trouble.
请阅读Susan, Tom, John, Bob, George的个性描述,然后匹配与他们个性相当的卡通人物。
【小题1】Tom is a warm-hearted boy, and he cares for others very much. If you meet with any difficulty, you can tell him, and he will surely help you.
【小题2】Susan has many friends and she likes to stay with them in many kinds of parties. On her face there is always a smile.
【小题3】John likes thinking and can always find ways to solve any difficult problems.
【小题4】Bob seems to be very rude and impolite and his words are unpleasant to hear, but his inner heart is full of concerns for others.
【小题5】George believes in himself, and he always wants to win the first place in almost everything.

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一个四棱锥和一个三棱锥恰好可以拼接成一个三棱柱.这个四棱锥的底面为正方形,且底面边长与各侧棱长相等,这个三棱锥的底面边长与各侧棱长也都相等.设四棱锥、三棱锥、三棱柱的高分别为,则(  )

A.           B.                  C.              D.

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1.解析:,故选A。

2.解析:抽取回族学生人数是,故选B。

3.解析:由,得,此时,所以,,故选C。

4.解析:∵,∴,∴,故选C。

5.解析:设公差为,由题意得,,解得,故选C。

6.解析:∵双曲线的右焦点到一条渐近线的距离等于焦距的,∴,又∵,∴,∴双曲线的渐近线方程是,故选D.

7.解析:∵为正实数,∴,∴;由均值不等式得恒成立,,故②不恒成立,又因为函数是增函数,∴,故恒成立的不等式是①③④。故选C.

8.解析:∵,∴在区间上恒成立,即在区间上恒成立,∴,故选D。

9.解析:∵

,∴此函数的最小正周期是,故选C。

10.解析:如图,∵正三角形的边长为,∴,∴,又∵,∴,故选D。

11.解析:∵在区间上是增函数且,∴其反函数在区间上是增函数,∴,故选A

12.解析:如图,①当时,圆面被分成2块,涂色方法有20种;②当时,圆面被分成3块,涂色方法有60种;

③当时,圆面被分成4块,涂色方法有120种,所以m的取值范围是,故选A。

13.解析:将代入结果为,∴时,表示直线右侧区域,反之,若表示直线右侧区域,则,∴是充分不必要条件。

学科网(Zxxk.Com)14.解析:∵,∴时,,又时,满足上式,因此,

学科网(Zxxk.Com)15.解析:设正四面体的棱长为,连,取的中点,连,∵的中点,∴,∴或其补角为所成角,∵,∴,∴,又∵,∴,∴所成角的余弦值为

学科网(Zxxk.Com)16.解析:∵,∴,∵点的准线与轴的交点,由向量的加法法则及抛物线的对称性可知,点为抛物线上关于轴对称的两点且做出图形如右图,其中为点到准线的距离,四边形为菱形,∴,∴,∴,∴,∴,∴向量的夹角为

17.(10分)解析:(Ⅰ)由正弦定理得,,…2分

,………4分

(Ⅱ)∵,∴,∴,………………………6分

又∵,∴,∴,………………………8分

。………………………10分

18.解析:(Ⅰ)∵,∴;……………………理3文4分

(Ⅱ)∵三科会考不合格的概率均为,∴学生甲不能拿到高中毕业证的概率;……………………理6文8分

(Ⅲ)∵每科得A,B的概率分别为,∴学生甲被评为三好学生的概率为。……………………12分

19.(12分)解析:(Ⅰ)∵,∴

 ,,……………3分

(Ⅱ)∵,∴

,∴数列自第2项起是公比为的等比数列,………………………6分

,………………………8分

(Ⅲ)∵,∴,………………10分

。………………………12分

20.解析:(Ⅰ)∵,∴,∵底面,∴,∴平面,∴,又∵平面,∴,∴平面,∴。………………………4分

(Ⅱ)∵平面,∴,∴为二面角的平面角,………………………6分

,∴,又∵平面,∴,∴二面角的正切值的大小为。………………………8分

(Ⅲ)过点,交于点,∵平面,∴在平面内的射影,∴与平面所成的角,………………………10分

学科网(Zxxk.Com),∴,又∵,∴与平面所成的角相等,∴与平面所成角的正切值为。………………………12分

解法2:如图建立空间直角坐标系,(Ⅰ)∵,,∴点的坐标分别是,∴,设,∵平面,∴,∴,取,∴,∴。………………………4分

(Ⅱ)设二面角的大小为,∵平面的法向量是,平面的法向量是,∴,∴,∴二面角的正切值的大小为。………………………8分

(Ⅲ)设与平面所成角的大小为,∵平面的法向量是,∴,∴,∴与平面所成角的正切值为。………………………12分

21.解析:(Ⅰ)设抛物线方程为,将代入方程得

所以抛物线方程为。………………………2分

由题意知椭圆的焦点为

设椭圆的方程为

∵过点,∴,解得,

∴椭圆的方程为。………………………5分

(Ⅱ)设的中点为的方程为:

为直径的圆交两点,中点为

,则

  

………………………8分

………………………10分

时,

此时,直线的方程为。………………………12分

22.(12分)解析:(Ⅰ)∵是偶函数,∴

又∵,………………………2分

得,

时,时,时,;∴时,函数