1g H2燃烧生成液态水.放出142.9kJ热量.表示该反应的热化学方程式为 ( ) A. H2+1/2O2==H2O,△H= -142.9kJ/mol B. H2(g) + 1/2O2(g)==H2O(l),△H= -285.8kJ/mol C. 2H2(g) +O2(g) ==2H2O(l),△H= -142.9kJ/mol D.2H2(g)+ O2(g)==2H2O(l),△H= +571.6kJ/mol 查看更多

 

题目列表(包括答案和解析)

1g氢气燃烧生成液态水,放出142.9KJ热量,下列表示该反应的热化学方程式正确的是

[  ]

A.H2(g)+O2(g)H2O(l)  △H=-285.8kJ/mol

B.2H2(g)+O2(g)2H2O(l)  △H=-142.9kJ/mol

C.2H2+O2H2O      △H=-571.6kJ/mol

D.2H2(g)+O2(g)2H2O(l)  △H=+571.6kJ/mol

查看答案和解析>>

1g氢气燃烧生成液态水,放出142.9kJ热量,下列表示该反应的热化学方程式正确的是

[  ]

A.2H2(g)+O2(g)=2H2O(l);ΔH=-142.9kJ·mol-1

B.H2(g)+O2(g)=H2O(l);ΔH=-285.8kJ·mol-1

C.2H2(g)+O2=2H2O(l);ΔH=-571.6kJ·mol-1

D.2H2(g)+O2(g)=2H2O(l);ΔH=+571.6kJ·mol-1

查看答案和解析>>


1g H2燃烧生成液态水放出142.9kJ的热量,下列热化学方程式正确的是( )

A.2H2(g)+ O 2(g) =" " 2H2O(1)H =" " —142.9kJ·molˉl
B.2H2(g)+ O 2(g) =" " 2H2O(1)H =" " —571.6kJ·molˉl
C.2H2+O2 = 2H2OH = —571.6lkJ·molˉl
D.H2(g)+O 2(g) = H2O(1)H = +285.8kJ·molˉl

查看答案和解析>>

1g H2燃烧生成液态水放出142.9kJ的热量,下列热化学方程式正确的是

A.2H2(g)+ O 2(g) = 2H2O(1)                          H = —142.9kJ·molˉl

B.2H2(g)+ O 2(g) = 2H2O(1)                           H = —571.6kJ·molˉl

C.2H2+O2 = 2H2O                                  H = —571.6lkJ·molˉl

D.H2(g)+O 2(g) = H2O(1)                          H = +285.8kJ·molˉl

 

查看答案和解析>>

1g H2燃烧生成液态水放出142.9kJ的热量,下列热化学方程式正确的是(  )

     A.2H2(g)+ O 2(g) = 2H2O(1)           H = —142.9kJ·molˉl

     B.2H2(g)+ O 2(g) = 2H2O(1)           H = —571.6kJ·molˉl

     C.2H2+O2 = 2H2O                     H = —571.6lkJ·molˉl

     D.H2(g)+O 2(g) = H2O(1)           H = +285.8kJ·molˉl

 

查看答案和解析>>


同步练习册答案