Question

Óû¯Ñ§·½³Ìʽ˵Ã÷ÏÂÁÐÎÊÌ⣺
£¨1£©·Ï¸Éµç³ØµÄпƬ¾­´¦Àíºó£¬¿ÉÓÃÓÚʵÑéÊÒÖÆÇâÆø£º

 

£¨2£©ÇâÑõ»¯ÄÆÒªÃÜ·â±£´æ£¬·ñÔò»á±äÖÊ£º

 

£¨3£©ÓÃÏ¡ÁòËáÀ´Çå³ýÌúÖÆÆ·±íÃæµÄÐ⣺

 

£¨4£©ÓÃÉÕ¼îÈÜÒºÎüÊÕÑÌ´Ñð³öµÄºÚÑÌ£¨º¬SO₂£©£¬ÒÔ¼õÉÙÆä»·¾³µÄÎÛȾ£º

 

£¨5£©Óú¬ÓÐÇâÑõ»¯ÂÁµÄÒ©ÎïÀ´ÖÎÁÆθËá¹ý¶à£º

 

£¨6£©ÓÃÊìʯ»ÒÖкÍÁòË᳧º¬ÁòËáµÄ·ÏÒº£º

 

£¨7£©ÓÃÏ¡ÑÎËáÇåÏ´Ë®ºøµÄË®¹¸£¨Ö÷Òª³É·ÖÊÇ̼Ëá¸Æ£©£¬µ«²»Äܳ¤Ê±¼ä½þÅÝ£¬·ñÔò»áËð»µÂÁºø£º
¢Ù

 

¢Ú

 

£®

Answer 1

¿¼µã£ºÊéд»¯Ñ§·½³Ìʽ¡¢ÎÄ×Ö±í´ïʽ¡¢µçÀë·½³Ìʽ

רÌ⣺»¯Ñ§ÓÃÓïºÍÖÊÁ¿Êغ㶨ÂÉ

·ÖÎö£º£¨1£©Ð¿ºÍÏ¡ÁòËá·´Ó¦Éú³ÉÁòËáпºÍÇâÆø£»
£¨2£©ÇâÑõ»¯ÄÆÄܺͿÕÆøÖеĶþÑõ»¯Ì¼·´Ó¦Éú³É̼ËáÄƺÍË®£»
£¨3£©ÌúÐâµÄÖ÷Òª³É·ÖÊÇÑõ»¯Ìú£¬Ñõ»¯ÌúºÍÏ¡ÁòËá·´Ó¦Éú³ÉÁòËáÌúºÍË®£»
£¨4£©ÇâÑõ»¯ÄÆÄܺͶþÑõ»¯Áò·´Ó¦Éú³ÉÑÇÁòËáÄƺÍË®£»
£¨5£©ÇâÑõ»¯ÂÁºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯ÂÁºÍË®£»
£¨6£©ÇâÑõ»¯¸ÆºÍÏ¡ÁòËá·´Ó¦Éú³ÉÁòËá¸ÆºÍË®£»
£¨7£©Ì¼Ëá¸ÆºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯¸Æ¡¢Ë®ºÍ¶þÑõ»¯Ì¼£»
ÂÁºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯ÂÁºÍÇâÆø£®

½â´ð£º½â£º£¨1£©Ð¿ºÍÏ¡ÁòËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºZn+H₂SO₄¨TZnSO₄+H₂¡ü£»
£¨2£©ÇâÑõ»¯ÄƺͶþÑõ»¯Ì¼·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2NaOH+CO₂¨TNa₂CO₃+H₂O£»
£¨3£©Ñõ»¯ÌúºÍÏ¡ÁòËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºFe₂O₃+3H₂SO₄¨TFe₂£¨SO₄£©₃+3H₂O£»
£¨4£©ÇâÑõ»¯ÄƺͶþÑõ»¯Áò·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2NaOH+SO₂¨TNa₂SO₃+H₂O£»
£¨5£©ÇâÑõ»¯ÂÁºÍÏ¡ÑÎËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºAl£¨OH£©₃+3HCl¨TAlCl₃+3H₂O£»
£¨6£©ÓÃÊìʯ»ÒÖкÍÁòË᳧º¬ÁòËáµÄ·ÏҺʱ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCa£¨OH£©₂+H₂SO₄¨TCaSO₄+2H₂O£»
£¨7£©¢Ù̼Ëá¸ÆºÍÏ¡ÑÎËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCO₃+2HCl¨TCaCl₂+H₂O+CO₂¡ü£»
¢ÚÂÁºÍÏ¡ÑÎËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2Al+6HCl¨T2AlCl₃+3H₂¡ü£®
¹ÊÌZn+H₂SO₄¨TZnSO₄+H₂¡ü£»2NaOH+CO₂¨TNa₂CO₃+H₂O£» Fe₂O₃+3H₂SO₄¨TFe₂£¨SO₄£©₃+3H₂O£»2NaOH+SO₂¨TNa₂SO₃+H₂O£»
 Al£¨OH£©₃+3HCl¨TAlCl₃+3H₂O£»Ca£¨OH£©₂+H₂SO₄¨TCaSO₄+2H₂O£»CaCO₃+2HCl¨TCaCl₂+H₂O+CO₂¡ü£»2Al+6HCl¨T2AlCl₃+3H₂¡ü£®

µãÆÀ£ºÊéд»¯Ñ§·½³ÌʽҪעÒâËIJ½£ºÒ»ÊÇ·´Ó¦ÎïºÍÉú³ÉÎïµÄ»¯Ñ§Ê½ÒªÕýÈ·£»¶þÊÇÒª×ñÑ­ÖÊÁ¿Êغ㶨ÂÉ£¬¼´Åäƽ£»ÈýÊÇÒªÓбØÒªµÄÌõ¼þ£»ËÄÊÇ¿´ÊÇ·ñÐèÒª¡°¡ü¡±»ò¡°¡ý¡±£®