Question

计算：
①

8

-2sin45°+(2-π)0-(

1

3

)-1
②tan30°sin60°+cos²30°-sin²45°tan45°．

Answer 1

①原式=2

2

-2×

2

2

+1-3
=2

2

-

2

+1-3
=

2

-2；

②原式=

3

3

×

3

2

+（

3

2

）²-（

2

2

）²•1
=

1

2

+

3

4

-

1

2

=

3

4

．