6.阅读下面计算过程:
$\frac{1}{\sqrt{2}+1}$=$\frac{1×(\sqrt{2}-1)}{(\sqrt{2}+1)(\sqrt{2}-1)}$=$\sqrt{2}$-1;
$\frac{1}{\sqrt{3}+\sqrt{2}}$=$\frac{1×(\sqrt{3}-\sqrt{2})}{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})}$=$\sqrt{3}$-$\sqrt{2}$;
$\frac{1}{\sqrt{5}+2}$=$\frac{1×(\sqrt{5}-2)}{(\sqrt{5}+2)(\sqrt{5}-2)}$=$\sqrt{5}$-2.
试求:(1)$\frac{1}{\sqrt{7}+\sqrt{6}}$=$\sqrt{7}$-$\sqrt{6}$.
(2)$\frac{1}{\sqrt{n+1}+\sqrt{n}}$(n为正整数)=$\sqrt{n+1}$-$\sqrt{n}$.
(3)$\frac{1}{1+\sqrt{2}}$+$\frac{1}{\sqrt{2}+\sqrt{3}}$+$\frac{1}{\sqrt{3}+\sqrt{4}}$+…+$\frac{1}{\sqrt{398}+\sqrt{399}}$+$\frac{1}{\sqrt{399}+\sqrt{400}}$的值.