A.y′=                                                         B.y′=e^x·lnx

C.y′=e^xlnx+                                              D.y′=

A.y′=（x²－1） e                                             B.y′=2x e

C.y′=（x²－1）e^x                                                    D.y′= e

A.·ln10                                                  B.

C.                                                   D.

A.（xlnx）′=lnx+1                                            B.（e^2x+1）′=2e^2x+1

C.［log_a（x²+1）］′=                        D.（a^2x－1）′=（2x－1）·e^2x－2