练习册

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    已知x1=logax2=log(a+1)x3＞0,0＜a＜1,则x1.x2.x3的大小关系是( ) A.x3＜x2＜x1 B.x2＜x1＜x3 C.x1＜x3＜x2 D.x2＜x3＜x1 答案:B 解析:由0＜a＜1可知0＜x1,x2＜1,a+1＞1,即有x3＞1. 又x1=logax2=logax12=logax2x12=x2,故x1＞x2. 即有0＜x2＜x1＜1＜x3. 【查看更多】

     

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    已知x1=logax2=log(a+1)x3＞0,0＜a＜1,则x1、x2、x3的大小关系是(    )

    A.x3＜x2＜x1                                                     B.x2＜x1＜x3

    C.x1＜x3＜x2                                                     D.x2＜x3＜x1

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