练习册

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    .先化简.再求值:.其中． 解法一:原式·································································· 2分 ······················································································································· 6分 当时.原式···················································································· 8分 解法二:原式··········································· 2分 ······················································································································· 6分 当时.原式···················································································· 8分 【查看更多】

     

    题目列表(包括答案和解析)

    （1）计算：(-
    1
    2
    )    -1    +(2008-π)0+
    		3
    tan30°
    （2）先化简，再求值：
    x2-2x
    x2-1
    ÷(x-1-
    2x-1
    x+1
    )    ，其中x=
    1
    2
    ．

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    （1）计算：（-4a2b4c）÷（
    1
    2
    a2b3）•2ab2
    （2）计算：(-
    1
    2
    )-2+(3+2π)0+(
    1
    2
    )2008×(-2)2009
    （3）先化简，再求值：[（xy+2）（xy-2）-2x2y2+4]÷（xy），其中x=10，y=-
    1
    25
    ．

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    （2009年重庆市江津区）先化简，再求值
     ，其中 =" 3" ．

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    （1）计算：(-
    1
    2
    )    -1    +(2008-π)0+
    		3
    tan30°
    （2）先化简，再求值：
    x2-2x
    x2-1
    ÷(x-1-
    2x-1
    x+1
    )    ，其中x=
    1
    2
    ．

    查看答案和解析>>

    （2009年重庆市江津区）先化简，再求值
     ，其中 =" 3" ．

    查看答案和解析>>


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