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    067](1)解:∵直角梯形 当时.四边形 为平行四边形． 由题意可知: 当时.四边形为平行四边形．································································· 3分 (2)解:设与相切于点 过点作垂足为 直角梯形 由题意可知: 为的直径. 为的切线 ····················································· 5分 在中.. 即:.. .因为在边运动的时间为秒 而..当秒时.与相切．································ 8分 [068]解:(1)如图4.过B作 则 过Q作 则 ························································································· 要使四边形PABQ是等腰梯形.则. 即 或(此时是平行四边形.不合题意.舍去)························· (2)当时.. ··············································· ···················································· ··································································· (3)①当时.则 ···························································································· ②当时. 即······················································ ③当时. ········· 综上.当时.△PQF是等腰三角形．·············· 【查看更多】

     

    题目列表(包括答案和解析)

    23、已知直角梯形ABCD的四条边长分别为AB=1，BC=CD=10，AD=6，过B、D两点作圆，与BA的延长线交于点E，与CB的延长线交于点F，并延长CD交圆于G点．
    （1）试证：BF=DG；
    （2）求BE-BF的值．

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    9、已知直角梯形ABCD的四条边长分别为AB=2，BC=CD=10，AD=6，过B、D两点作圆，与BA的延长线交于点E，与CB的延长线交于点F，则BE-BF的值为
    4
    ．

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    7、下列命题中，真命题是（　　）

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    已知：直角梯形OABC的四个顶点是O（0，0），A（
    3
    2
    ，1），精英家教网B（s，t），C（
    7
    2
    ，0），抛物线y=x2+mx-m的顶点P是直角梯形OABC内部或边上的一个动点，m为常数．
    （1）求s与t的值，并在直角坐标系中画出直角梯形OABC；
    （2）当抛物线y=x2+mx-m与直角梯形OABC的边AB相交时，求m的取值范围．

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    已知：直角梯形OABC的四个顶点是O（0，0），A（，1），B（s，t），C（，0），抛物线y=x2+mx-m的顶点P是直角梯形OABC内部或边上的一个动点，m为常数．
    （1）求s与t的值，并在直角坐标系中画出直角梯形OABC；
    （2）当抛物线y=x2+mx-m与直角梯形OABC的边AB相交时，求m的取值范围．

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