(5·Ö)

           Óîֿů»¯·Ê¨D¨D¹ú¼ÊÊ×´´

Ö÷Òª³É·Ö£ºÌ¼ËáÇâï§£¨NH4HCO3£©

º¬µªÁ¿¾ÓÈ«Çò»¯·ÊÖ®Ê×£º24£¥

¾»º¬Á¿£º50kg/´ü

¡°ÓîÖæ¡±»¯·ÊÓÐÏÞÔðÈι«Ë¾³öÆ·

 

 

 

 

 

 

 

 

ijÉú²ú»¯·Ê̼ËáÇâï§(NH4HCO3)µÄÆóÒµ£¬×÷ÁËÒ»¸ö´óÐÍ»§Íâ¹ã¸æ¡£ÈçͼËùʾ£º¸ù¾ÝÏà¹ØÐÅÏ¢¼ÆË㣺

£¨1£©Ì¼ËáÇâï§NH4HCO3Öеª¡¢Çâ¡¢Ñõ¡¢Ì¼ËÄÖÖÔªËØµÄÖÊÁ¿±È_______________

£¨2£©Í¨¹ý¼ÆËãÅÐ¶Ï¸Ã¹ã¸æÊôÓÚ__________(Ìî¡°Ðé¼Ù¡±»ò¡°ÕæÊµ¡±)¹ã¸æ£¿

£¨1£©ÇëÄãд³ö¼ÆËã¹ý³ÌºÍÅжÏÒÀ¾Ý¡£

¼ÆËã¹ý³Ì£º                                           

                                                      £¨½á¹û¾«È·µ½0. 1£¥£©

¢Üÿ´ü¸Ã»¯·ÊÖеªÔªËصÄÖÊÁ¿×î¶àΪ¶àÉÙkg£¿

 

14:5:48:12   Ðé¼Ù    8.85

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(5·Ö)

           Óîֿů»¯·Ê¨D¨D¹ú¼ÊÊ×´´

Ö÷Òª³É·Ö£ºÌ¼ËáÇâï§£¨NH4HCO3£©

º¬µªÁ¿¾ÓÈ«Çò»¯·ÊÖ®Ê×£º24£¥

¾»º¬Á¿£º50kg/´ü

¡°ÓîÖæ¡±»¯·ÊÓÐÏÞÔðÈι«Ë¾³öÆ·

 

 

 

 

 

 

 

 

ijÉú²ú»¯·Ê̼ËáÇâï§(NH4HCO3)µÄÆóÒµ£¬×÷ÁËÒ»¸ö´óÐÍ»§Íâ¹ã¸æ¡£ÈçͼËùʾ£º¸ù¾ÝÏà¹ØÐÅÏ¢¼ÆË㣺

£¨1£©Ì¼ËáÇâï§NH4HCO3Öеª¡¢Çâ¡¢Ñõ¡¢Ì¼ËÄÖÖÔªËØµÄÖÊÁ¿±È_______________

£¨2£©Í¨¹ý¼ÆËãÅÐ¶Ï¸Ã¹ã¸æÊôÓÚ__________(Ìî¡°Ðé¼Ù¡±»ò¡°ÕæÊµ¡±)¹ã¸æ£¿

£¨1£©ÇëÄãд³ö¼ÆËã¹ý³ÌºÍÅжÏÒÀ¾Ý¡£

¼ÆËã¹ý³Ì£º                                           

                                                      £¨½á¹û¾«È·µ½0. 1£¥£©

¢Üÿ´ü¸Ã»¯·ÊÖеªÔªËصÄÖÊÁ¿×î¶àΪ¶àÉÙkg£¿

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2011ÄêÉÂÎ÷Ê¡³õÈýÉÏѧÆÚµÚ¶þ´ÎÔ¿¼»¯Ñ§¾í ÌâÐÍ£º¼ÆËãÌâ

(5·Ö)

           Óîֿů»¯·Ê¨D¨D¹ú¼ÊÊ×´´[À´Ô´:ѧ+¿Æ+Íø]

Ö÷Òª³É·Ö£ºÌ¼ËáÇâï§£¨NH4HCO3£©

º¬µªÁ¿¾ÓÈ«Çò»¯·ÊÖ®Ê×£º24£¥

¾»º¬Á¿£º50kg/´ü

¡°ÓîÖæ¡±»¯·ÊÓÐÏÞÔðÈι«Ë¾³öÆ·[À´Ô´:ѧ,¿Æ,ÍøZ,X,X,K]

 

 

 

 

 

 

 

 

ijÉú²ú»¯·Ê̼ËáÇâï§(NH4HCO3)µÄÆóÒµ£¬×÷ÁËÒ»¸ö´óÐÍ»§Íâ¹ã¸æ¡£ÈçͼËùʾ£º¸ù¾ÝÏà¹ØÐÅÏ¢¼ÆË㣺

£¨1£©Ì¼ËáÇâï§NH4HCO3Öеª¡¢Çâ¡¢Ñõ¡¢Ì¼ËÄÖÖÔªËØµÄÖÊÁ¿±È_______________

£¨2£©Í¨¹ý¼ÆËãÅÐ¶Ï¸Ã¹ã¸æÊôÓÚ__________(Ìî¡°Ðé¼Ù¡±»ò¡°ÕæÊµ¡±)¹ã¸æ£¿

£¨1£©ÇëÄãд³ö¼ÆËã¹ý³ÌºÍÅжÏÒÀ¾Ý¡£

¼ÆËã¹ý³Ì£º                                           

                                                       £¨½á¹û¾«È·µ½0. 1£¥£©

¢Üÿ´ü¸Ã»¯·ÊÖеªÔªËصÄÖÊÁ¿×î¶àΪ¶àÉÙkg£¿

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2011Äêɽ¶«Ê¡³õÈýµÚһѧÆÚÆÚÄ©»¯Ñ§¾í ÌâÐÍ£º¼ÆËãÌâ

(5·Ö)

           Óîֿů»¯·Ê¨D¨D¹ú¼ÊÊ×´´[À´Ô´:ѧ+¿Æ+Íø]

Ö÷Òª³É·Ö£ºÌ¼ËáÇâï§£¨NH4HCO3£©

º¬µªÁ¿¾ÓÈ«Çò»¯·ÊÖ®Ê×£º24£¥

¾»º¬Á¿£º50kg/´ü

¡°ÓîÖæ¡±»¯·ÊÓÐÏÞÔðÈι«Ë¾³öÆ·[À´Ô´:ѧ,¿Æ,ÍøZ,X,X,K]

 

 

 

 

 

 

 

 

ijÉú²ú»¯·Ê̼ËáÇâï§(NH4HCO3)µÄÆóÒµ£¬×÷ÁËÒ»¸ö´óÐÍ»§Íâ¹ã¸æ¡£ÈçͼËùʾ£º¸ù¾ÝÏà¹ØÐÅÏ¢¼ÆË㣺

£¨1£©Ì¼ËáÇâï§NH4HCO3Öеª¡¢Çâ¡¢Ñõ¡¢Ì¼ËÄÖÖÔªËØµÄÖÊÁ¿±È_______________

£¨2£©Í¨¹ý¼ÆËãÅÐ¶Ï¸Ã¹ã¸æÊôÓÚ__________(Ìî¡°Ðé¼Ù¡±»ò¡°ÕæÊµ¡±)¹ã¸æ£¿

£¨1£©ÇëÄãд³ö¼ÆËã¹ý³ÌºÍÅжÏÒÀ¾Ý¡£

¼ÆËã¹ý³Ì£º                                           

                                                       £¨½á¹û¾«È·µ½0. 1£¥£©

¢Üÿ´ü¸Ã»¯·ÊÖеªÔªËصÄÖÊÁ¿×î¶àΪ¶àÉÙkg£¿

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸