Question

д³öÏÂÁл¯Ñ§±ä»¯µÄ»¯Ñ§·½³Ìʽ²¢Íê³ÉÓйØÎÊÌâ
(1)ľ̿ÔÚÑõÆøÖÐȼÉÕ£º
________________________________£¬Æä²úÎï¿ÉÓÃ________________¼ìÑé¡£
(2)¶þÑõ»¯Ì¼Í¨ÈëµÎÓÐ×ÏɫʯÈïÊÔÒºµÄË®ÖУº
________________________________£¬¸Ã·´Ó¦ÏÖÏóΪ________________¡£
(3) ʵÑéÊÒÓùýÑõ»¯ÇâºÍ¶þÑõ»¯ÃÌÖÆÈ¡ÑõÆø£º_______________________£»¸Ã·´Ó¦Ç°ºó¶þÑõ»¯Ã̵Ä_______________________ºÍ_______________________²»±ä£¬ÊÇ·´Ó¦µÄ_______________________
(4) Ìú·ÛÓëÏ¡ÑÎËá·´Ó¦£º_______________________£¬
»ù±¾·´Ó¦ÀàÐÍ_______________________£»·´Ó¦ºóÈÜÒºÓÉÎÞÉ«±äΪ_______________________¡£
(5)¾ÃÖÃʯ»ÒË®µÄÊÔ¼ÁÆ¿ÄÚ±Ú³£»áÐγÉÒ»²ã°×É«¹ÌÌ壺___________________________£¬Ï´È¥¸Ã°×É«¹ÌÌåÐèÒªÓõÄÊÔ¼ÁÊÇ________________£¨ÌîÃû³Æ£©

Answer 1

£¨1£©C£«O2     CO2 ³ÎÇåʯ»ÒË®
£¨2£©CO2£«H2OH2CO3  ±äºì
£¨3£©2H2O22H2O+O2¡ü ÖÊÁ¿ »¯Ñ§ÐÔÖÊ  ´ß»¯¼Á
£¨4£©Fe£«2HClFeCl2£«H2¡ü Öû» dzÂÌÉ«
£¨5£©CO2£«Ca(OH)2CaCO3 ¡ý£«H2O Ï¡ÑÎËá

£º£¨1£©¸ù¾Ý̼£¨»òÑõÆø£©µÄ»¯Ñ§ÐÔÖʿɵã¬Ä¾Ì¿ÔÚÑõÆøÖÐȼÉյĻ¯Ñ§·½³ÌʽΪ£º£©C£«O2  = CO2£»¸ù¾Ý¶þÑõ»¯Ì¼µÄ¼ìÑé·½·¨¿ÉÖª£¬ÆäȼÉÕ²úÎï¿ÉÓóÎÇåµÄʯ»ÒË®¼ìÑ飮
£¨2£©¸ù¾Ý¶þÑõ»¯Ì¼µÄ»¯Ñ§ÐÔÖʿɵ㬶þÑõ»¯Ì¼Í¨ÈëµÎÓÐ×ÏɫʯÈïÊÔÒºµÄË®Öз¢ÉúµÄ»¯Ñ§·½³ÌʽΪ£ºCO₂+H₂O=H₂CO₃£¬¸Ã·´Ó¦ÏÖÏóΪ×ÏɫʯÈïÊÔÒº±ä³ÉºìÉ«£®
£¨3£©¸ù¾ÝÑõÆøµÄʵÑéÊÒÖÆÈ¡·´Ó¦Ô­ÀíºÍ´ß»¯¼ÁµÄ¸ÅÄî¿ÉµÃ£¬ÊµÑéÊÒÓùýÑõ»¯ÇâºÍ¶þÑõ»¯ÃÌÖÆÈ¡ÑõÆøµÄ»¯Ñ§·½³ÌʽΪ£º2H2O22H2O+O2¡ü£»¸Ã·´Ó¦Ç°ºó¶þÑõ»¯Ã̵ÄÖÊÁ¿ºÍ»¯Ñ§ÐÔÖʲ»±ä£¬ÊÇ·´Ó¦µÄ´ß»¯¼Á£®
£¨4£©¸ù¾ÝÌú£¨»òÏ¡ÑÎËᣩµÄ»¯Ñ§ÐÔÖÊ£¬ÒÔ¼°Öû»·´Ó¦µÄ¸ÅÄîºÍÌصã¿ÉµÃ£¬Ìú·ÛÓëÏ¡ÑÎËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºFe+2HCl=FeCl₂+H₂¡ü£¬»ù±¾·´Ó¦ÀàÐÍÖû»·´Ó¦£»·´Ó¦ºóÈÜÒºÓÉÎÞÉ«±äΪdzÂÌÉ«£®
£¨5£©¸ù¾Ý¶þÑõ»¯Ì¼£¨»òÇâÑõ»¯¸Æ£©µÄ»¯Ñ§ÐÔÖÊ£¬ÒÔ¼°Ì¼Ëá¸Æ£¨»òÏ¡ÑÎËᣩµÄ»¯Ñ§ÐÔÖʿɵ㬾ÃÖÃʯ»ÒË®µÄÊÔ¼ÁÆ¿ÄÚ±Ú³£»áÐγÉÒ»²ã°×É«¹ÌÌ壬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCa£¨OH£©₂+CO₂=CaCO₃¡ý+H₂O£¬Ï´È¥¸Ã°×É«¹ÌÌåÐèÒªÓõÄÊÔ¼ÁÊÇÏ¡ÑÎËᣮ