NAΪ°¢·ü¼ÓµÂÂÞ³£Êý£¬ÏÂÁÐ4ÏîÐðÊöÖÐÕýÈ·µÄÓм¸Ï £©
¢Ù106g Na2CO3¾§ÌåÖеÄÀë×Ó×ÜÊý´óÓÚ3NA
¢Ú±ê×¼×´¿öÏ£¬16gO3ºÍO2»ìºÏÆøÌåÖк¬ÓеÄÑõÔ×ÓÊýΪNA
¢Û½«FeCl3µÄ±¥ºÍÈÜÒº£¨º¬FeCl3 0.1mol£©¼ÓÈë·ÐË®Öгä·Ö×÷ÓÃÖƳɽºÌ壬ÆäÖк¬ÓнºÌåÁ£×ÓµÄÊýĿΪ0.1NA
¢Ül mol N2ºÍ3mol H2ÔÚÒ»¶¨Ìõ¼þϵÄÃܱÕÈÝÆ÷Öгä·Ö·´Ó¦£¬ÈÝÆ÷ÄڵķÖ×ÓÊý´óÓÚ2NA£®
A£®1Ïî
B£®2Ïî
C£®3Ïî
D£®4Ïî
¡¾´ð°¸¡¿
·ÖÎö£º¢ÙÖÊÁ¿ºÍĦ¶ûÖÊÁ¿À´»»ËãÎïÖʵÄÁ¿£¬½áºÏ¾§Ìå¹¹³É·ÖÎöÅжϣ»
¢Úµ¥Öʶ¼ÊÇÑõÔªËØ×é³É£¬ÑõÔªËØÖÊÁ¿Êغ㣬¼ÆËã16gÑõÔªËØÎïÖʵÄÁ¿¼´¿É£»
¢Û½ºÌåÁ£×ÓÊÇÇâÑõ»¯ÌúµÄ¼¯ºÏÌ壻
¢ÜºÏ³É°±·´Ó¦Ç°ºóÌå»ý¼õÉÙ£¬·´Ó¦ÊÇ¿ÉÄæ¹ý³Ì·ÖÎö£®
½â´ð£º½â£º¢Ù106g Na
2CO
3¾§ÌåÎïÖʵÄÁ¿=
=1mol£¬º¬ÄÆÀë×Ó2mol£¬º¬Ì¼Ëá¸ùÀë×Ó1mol£¬¹²º¬Àë×ÓÊýΪ3N
A£¬¹Ê¢Ù´íÎó£»
¢Ú±ê×¼×´¿öÏ£¬16gO
3ºÍO
2»ìºÏÆøÌåÖк¬ÓÐÑõÔªËØÎïÖʵÄÁ¿Îª1mol£¬¼´º¬ÑõÔ×ÓÎïÖʵÄÁ¿Îª1mol£¬Ô×ÓÊýΪN
A£¬¹Ê¢ÚÕýÈ·£»
¢Û½ºÌåÁ£×ÓÊÇÇâÑõ»¯ÌúÐγɵļ¯ºÏÌ壬΢Á£ÊýÒ»¶¨Ð¡ÓÚ0.1N
A£¬¹Ê¢Û´íÎó£»
¢Ül mol N
2ºÍ3mol H
2·´Ó¦¸ù¾Ý»¯Ñ§·½³Ìʽ¿ÉÖª·´Ó¦Ç°ºóÎïÖʵÄÁ¿¼õÉÙ2£¬¼õÉÙµÄÁ¿ÎªÉú³É°±ÆøµÄÁ¿Îª2£¬·´Ó¦ÊÇ¿ÉÄæ·´Ó¦£¬ËùÒÔÃܱÕÈÝÆ÷Öгä·Ö·´Ó¦£¬ÈÝÆ÷ÄڵķÖ×ÓÊýÒ»¶¨´óÓÚ2N
A£¬¹Ê¢ÜÕýÈ·£»
¹ÊÑ¡B£®
µãÆÀ£º±¾Ì⿼²éÁË°¢·üÙ¤µÂÂÞ³£ÊýµÄÓ¦Óã¬Ö÷Òª¿¼²éÖÊÁ¿»»ËãÎïÖʵÄÁ¿¼ÆËã΢Á£Êý£¬½ºÌåÁ£×ÓµÄʵÖÊ£¬¿ÉÄæ·´Ó¦µÄÅжÏÓ¦Óã®