Question

»¯Ñ§ÄܵÄת»¯ÔÚÏÖʵÉú»îÖеõ½Á˹㷺µÄÀûÓ᣻شðÒÔÏÂÎÊÌ⣺
£¨¢ñ£©(1)ÔÚ25¡æ¡¢101kPaÏ£¬1g¼×ÍéÍêȫȼÉÕÉú³ÉCO₂ºÍҺ̬H₂O£¬·Å³ö55 kJµÄÈÈÁ¿£¬Ð´³ö±íʾ¼×ÍéȼÉÕµÄÈÈ»¯Ñ§·½³Ìʽ£º                                   ¡£
(2)2Zn£¨s£©+O₂£¨g£©=2ZnO£¨s£©  ¦¤H₁=" ¡ª702" kJ/mol
2Hg£¨l£©+O₂£¨g£©=2HgO£¨s£©  ¦¤H₂=" ¡ª182" kJ/mol
ÓÉ´Ë¿ÉÖªZnO£¨s£©+Hg£¨l£©= Zn£¨s£©+HgO£¨s£© ¡÷H₃=          ¡£
£¨3£©20ÊÀ¼Í30Äê´ú£¬EyringºÍPelzerÔÚÅöײÀíÂ۵Ļù´¡ÉÏÌá³ö»¯Ñ§·´Ó¦µÄ¹ý¶É̬ÀíÂÛ£º»¯Ñ§·´Ó¦²¢²»ÊÇͨ¹ý¼òµ¥µÄÅöײ¾ÍÄÜÍê³ÉµÄ£¬¶øÊÇÔÚ·´Ó¦Îïµ½Éú³ÉÎïµÄ¹ý³ÌÖо­¹ýÒ»¸ö¸ßÄÜÁ¿¹ý¶É̬¡£ÏÂͼÊÇNO₂ºÍCO·´Ó¦Éú³ÉCO₂ºÍNO¹ý³ÌÖÐÄÜÁ¿±ä»¯Ê¾Òâͼ£¬Çëд³öNO₂ºÍCO·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º                                  

£¨¢ò£©ÏÂͼΪÏ໥´®ÁªµÄ¼×ÒÒÁ½¸öµç½â³Ø£º

Çë»Ø´ð£º
£¨1£©¼×³ØÈôΪÓõç½âÔ­Àí¾«Á¶Í­µÄ×°Öã¬Ôò£º
A¼«ÊÇ¡¡¡¡¡¡¼«£¬²ÄÁÏÊÇ          £¬µç¼«·´Ó¦Îª¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¬
B¼«ÊÇ¡¡¡¡¡¡¼«£¬²ÄÁÏÊÇ          £¬µç¼«·´Ó¦Îª¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¬
µç½âÖÊÈÜҺΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨2£©ÒÒ³ØÖÐÈôµÎÈëÉÙÁ¿·Ó̪ÊÔÒº£¬¿ªÊ¼Ò»¶Îʱ¼äºó£¬Fe¼«¸½½ü³Ê¡¡¡¡¡¡¡¡¡¡É«¡£
£¨3£©Èô¼×²ÛÒõ¼«ÔöÖØ12£®8g£¬ÔòÒÒ²ÛÑô¼«·Å³öÆøÌåÔÚ±ê×¼×´¿öϵÄÌå»ý
£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£
£¨4£©Í¬Ê±ÈôÒÒ²ÛÊ£ÓàÒºÌåΪ400mL£¬Ôòµç½âºóµÃµ½¼îÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ
__   ¡¡¡¡¡¡  _____¡£

Answer 1

£¨¢ñ£©£¨1£©CH₄£¨g£©+2O₂£¨g£©==== CO₂£¨g£©+ 2H₂O£¨g£©   ¦¤H =" ¡ª880" kJ/mol
£¨2£©+260 kJ/mol 
£¨3£©NO₂£¨g£©+CO£¨g£©="===" CO₂£¨g£©+NO£¨g£©¡¡¦¤H =" ¡ª234" kJ/mol
£¨¢ò£©£¨1£©Òõ¡¡´¿Í­¡¡Cu²⁺+2e^-=Cu¡¡Ñô¡¡´ÖÍ­¡¡Cu-2e^-=Cu²⁺  CuSO₄ÈÜÒº
£¨2£©ºì
£¨3£©4.48 L
£¨4£©1mol/L

£¨¢ñ£©£¨1£©ÓÉÌâÄ¿ÐÅÏ¢¿ÉÕÛËã³ö1mol¼×ÍéÍêȫȼÉÕÉú³ÉÎȶ¨µÄÑõ»¯ÎïʱËù·Å³öµÄÈÈÁ¿Îª16¡Á55=880kJ£¬Ôò¼×ÍéȼÉÕµÄÈÈ»¯Ñ§·½³ÌʽΪCH₄£¨g£©+2O₂£¨g£©==== CO₂£¨g£©+ 2H₂O£¨g£©   ¦¤H =" ¡ª880" kJ/mol
£¨2£©¸ù¾ÝËù¸øÁ½ÈÈ»¯Ñ§·½³Ìʽ¿ÉµÃµ½£º
¢ÙZnO£¨s£©=Zn£¨s£©+1/2O₂£¨g£©  ¦¤H₁=" +351" kJ/mol
¢ÚHg£¨l£©+1/2O₂£¨g£©=HgO£¨s£©  ¦¤H₂= ¡ª91kJ/mol
¢Ù+¢ÚµÃµ½£ºZnO£¨s£©+Hg£¨l£©= Zn£¨s£©+HgO£¨s£© ¡÷H₃=+260 kJ/mol
£¨3£©ÓÉͼ¿ÉÖª£¬¸Ã·´Ó¦Îª·ÅÈÈ·´Ó¦£¬¡÷H₃=134¡ª368=¡ª234 kJ/mol£¬¹ÊÈÈ»¯Ñ§·½³ÌʽΪ£º
NO₂£¨g£©+CO£¨g£©="===" CO₂£¨g£©+NO£¨g£©¡¡¦¤H =" ¡ª234" kJ/mol
II£¨1£©¼×³ØÈôΪ¾«Á¶Í­µÄ×°Ö㬵ç½âÖÊÈÜҺӦΪͭÑΣ¬¾­³£ÓÃÁòËáÍ­ÈÜÒº£¬Ôò£º
´ÖÍ­×öÑô¼«£¬¼´ÓëÍâµçÔ´µÄÕý¼«ÏàÁ¬µÄB¼«£ºCu-2e^-=Cu²⁺
´¿Í­×öÒõ¼«£¬¼´A¼«£ºCu²⁺+2e^-=Cu
£¨2£©ÒÒ³ØÖÐÌú¼«×öΪµç½â³ØµÄÒõ¼«£º2H₂O£«2e^£­=H₂¡ü£«2OH^£­£¬ÈÜÒº³Ê¼îÐÔ£¬µÎÈë·Ó̪ºó³ÊºìÉ«
£¨3£©¼×²ÛÒõ¼«Îö³öÍ­ÔöÖØ£¬ÔòÒÒ²ÛÑô¼«·Å³öÂÈÆø£º2Cl-2e^£­=Cl₂¡ü£¬ÓɹØϵʽCu¡«2e^£­¡«Cl₂¡ü£¬¿ÉÖªÂÈÆøÔÚ±ê×¼×´¿öϵÄÌå»ýΪ=4.48L
£¨4£©ÓɹØϵʽ2OH^£­¡«Cl₂¡ü¿ÉÖª£¬c(OH^£­)==1mol/L