ÒÒÈ©(CH3CHO)ÔÚ´ß»¯¼Á´æÔÚµÄÌõ¼þÏ£¬¿ÉÒÔ±»¿ÕÆøÑõ»¯³ÉÒÒËᣮÒÀ¾Ý´ËÔ­ÀíÉè¼ÆÊµÑéÖÆµÃ²¢ÔÚÊÔ¹ÜCÖÐÊÕ¼¯µ½ÉÙÁ¿ÒÒËáÈÜÒº(ÈçͼËùʾ£ºÊÔ¹ÜAÖÐ×°ÓÐ40£¥µÄÒÒȩˮÈÜÒº¡¢Ñõ»¯Í­·ÛÄ©£»ÊÔ¹ÜCÖÐ×°ÓÐÊÊÁ¿ÕôÁóË®£»ÉÕ±­BÖÐ×°ÓÐijҺÌå)£®ÒÑÖªÔÚ60¡æ¡«80¡æÊ±ÓÃË«Á¬´òÆøÇò¹ÄÈë¿ÕÆø¼´¿É·¢ÉúÒÒÈ©µÄÑõ»¯·´Ó¦£¬Á¬Ðø¹ÄÈëÊ®¼¸´Î£¬·´Ó¦»ù±¾ÍêÈ«£®ÓйØÎïÖʵķеã¼ûÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)ÊÔ¹ÜAÄÚÔÚ60¡æ¡«80¡æÊ±·¢ÉúµÄÖ÷Òª·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ(×¢Ã÷·´Ó¦Ìõ¼þ)

________£®ÈçͼËùʾ£¬ÔÚʵÑéµÄ²»Í¬½×¶Î£¬ÐèÒªµ÷ÕûζȼÆÔÚÊÔ¹ÜAÄÚµÄλÖã¬ÔÚʵÑ鿪ʼʱζȼÆË®ÒøÇòµÄλÖÃÓ¦ÔÚ________£»µ±ÊÔ¹ÜAÄÚµÄÖ÷Òª·´Ó¦Íê³ÉºóζȼÆË®ÒøÇòµÄλÖÃÓ¦ÔÚ________£®

(3)ÉÕ±­BÄÚÊ¢×°µÄÒºÌå¿ÉÒÔÊÇ________£®

(4)ÊÔ¹ÜCÖÐÊÕ¼¯µ½µÄÊÇ´Ö²úÆ·£¬ÈôÏë½øÒ»²½Ìá´¿£¬¿É²ÉÓõķ½·¨ÊÇ________£»

Ìá´¿ºóµÄ²úÆ·ÈôÔÚÖÊÆ×ÒÇÖнøÐвⶨ£¬ÆäÖʺɱÈ×î´óÊÇ________(ÌîÊýÖµ)£»ÈôÔں˴ʲÕñÒÇÖнøÐвⶨ£¬ÆäºË´Å¹²ÕñÇâÆ×¹²ÓÐ________Öַ壬·åÃæ»ýÖ®±ÈΪ________£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÓÐA¡¢B¡¢CÈýÖÖÌþµÄÑÜÉúÎÏ໥ת»¯¹ØÏµÈçÏ£º

ÆäÖÐB¿É·¢ÉúÒø¾µ·´Ó¦£¬C¸úʯ»Òʯ·´Ó¦²úÉúÄÜʹ³ÎÇåʯ»ÒË®±ä»ë×ÇµÄÆøÌ壮
£¨1£©A¡¢B¡¢CµÄ½á¹¹¼òʽºÍÃû³ÆÒÀ´ÎÊÇ
CH3CH2OHÒÒ´¼
CH3CH2OHÒÒ´¼
¡¢
CH3CHOÒÒÈ©
CH3CHOÒÒÈ©
¡¢
CH3COOHÒÒËá
CH3COOHÒÒËá
£®
£¨2£©Ð´³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ
A¡úB
2CH3CH2OH+O2
Cu
¡÷
2CH3CHO+2H2O
2CH3CH2OH+O2
Cu
¡÷
2CH3CHO+2H2O

B¡úC
2CH3CHO+O2¡ú
´ß»¯¼Á
¡÷
2CH3COOH
2CH3CHO+O2¡ú
´ß»¯¼Á
¡÷
2CH3COOH

B¡úA
CH3CHO+H2
Ò»¶¨Ìõ¼þ
CH3CH2OH
CH3CHO+H2
Ò»¶¨Ìõ¼þ
CH3CH2OH
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

µÈÎïÖʵÄÁ¿µÄÏÂÁÐÓлúÎïÔÚÑõÆøÖгä·ÖȼÉÕ£¬ÏûºÄÑõÆø×î¶àµÄÊÇ(    )

A.ÒÒÈ©(CH3CHO)                              B.ÒÒ´¼(CH3CH2OH)

C.¼º¶þ´¼(HOCH2CH2OH)                  D.¼×Ëá¼×õ¥(HCOOCH3)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚº¸½ÓÍ­Æá°üÏßµÄÏßͷʱ£¬³£°ÑÏßÍ··ÅÔÚ»ðÉÏÉÕһϣ¬²¢Á¢¼´Ôھƾ«ÖÐÕºÒ»ÏÂÔÙº¸½Ó£¬ºÚÉ«Ñõ»¯Í­ÓÖ±ä³Éºìɫͭ£¬Í¬Ê±²úÉúÓд̼¤ÐÔÆøÎ¶µÄÒºÌåÒÒÈ©(CH3CHO),ÕâÊÇÒòΪ(Óû¯Ñ§·½³Ìʽ±íʾ)£º

(1)____________________________________________________________£¬

(2)____________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêºþ±±Ê¡ÏåÑôÊи߶þÏÂѧÆÚËÄУÁª¿¼ÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÊµÑéÌâ

£¨9·Ö£©ÒÒÈ©(CH3CHO)ÔÚ´ß»¯¼Á´æÔÚµÄÌõ¼þÏ£¬¿ÉÒÔ±»¿ÕÆøÑõ»¯³ÉÒÒËá¡£ÒÀ¾Ý´ËÔ­ÀíÉè¼ÆÊµÑéÖÆµÃ²¢ÔÚÊÔ¹ÜCÖÐÊÕ¼¯µ½ÉÙÁ¿ÒÒËáÈÜÒº£¨ÈçͼËùʾ£ºÊÔ¹ÜAÖÐ×°ÓÐ40%µÄÒÒȩˮÈÜÒº¡¢Ñõ»¯Í­·ÛÄ©£»ÊÔ¹ÜCÖÐ×°ÓÐÊÊÁ¿ÕôÁóË®£»ÉÕ±­BÖÐ×°ÓÐijҺÌ壩¡£ÒÑÖªÔÚ60¡æ~80¡æÊ±ÓÃË«Á¬´òÆøÇò¹ÄÈë¿ÕÆø¼´¿É·¢ÉúÒÒÈ©µÄÑõ»¯·´Ó¦£¬Á¬Ðø¹ÄÈëÊ®¼¸´Î£¬·´Ó¦»ù±¾ÍêÈ«¡£ÓйØÎïÖʵķеã¼ûÏ£º

ÎïÖÊ
ÒÒÈ©
ÒÒËá
¸ÊÓÍ
ÒÒ´¼
Ë®
·Ðµã/¡æ
20.8
117.9
290
78.2
100
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÊÔ¹ÜAÄÚÔÚ60¡æ~80¡æÊ±·¢ÉúµÄÖ÷Òª·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£¨×¢Ã÷·´Ó¦Ìõ¼þ£©
¡¡¡¡¡¡_________________________________________¡£
£¨2£©ÈçͼËùʾ£¬ÔÚʵÑéµÄ²»Í¬½×¶Î£¬ÐèÒªµ÷ÕûζȼÆÔÚÊÔ¹ÜAÄÚµÄλÖã¬ÔÚʵÑ鿪ʼʱÎÂ
¶È¼ÆË®ÒøÇòµÄλÖÃÓ¦ÔÚ________£»µ±ÊÔ¹ÜAÄÚµÄÖ÷Òª·´Ó¦Íê³ÉºóζȼÆË®ÒøÇòµÄλÖÃÓ¦ÔÚ_______¡£

£¨3£©ÉÕ±­BÄÚÊ¢×°µÄÒºÌå¿ÉÒÔÊÇ_______¡£
£¨4£©ÊÔ¹ÜCÖÐÊÕ¼¯µ½µÄÊÇ´Ö²úÆ·£¬ÈôÏë½øÒ»²½Ìá´¿£¬¿É²ÉÓõķ½·¨Êǣߣߣߣߣߣ»
¡¡¡¡¡¡Ìá´¿ºóµÄ²úÆ·ÈôÔÚÖÊÆ×ÒÇÖнøÐвⶨ£¬ÆäÖʺɱÈ×î´óÊǣߣߣߣߣ¨ÌîÊýÖµ£©£»
¡¡¡¡¡¡ÈôÔں˴ʲÕñÒÇÖнøÐвⶨ£¬ÆäºË´Å¹²ÕñÇâÆ×¹²ÓУߣßÖַ壬·åÃæ»ýÖ®±ÈΪ£ß£ß¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêÉÂÎ÷Ê¡¸ßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§Ìâ ÌâÐÍ£ºÑ¡ÔñÌâ

ÒÑÖª£º(1)´¼ÀàÎïÖÊÔÚ´ß»¯¼Á´æÔÚÌõ¼þÏ¿ɷ¢ÉúÀàËÆÓÚÒÒ´¼µÄÍÑÇâÑõ»¯¡£        

 


(2)ôÊ»ù(        ) ÓëÁ½¸öÌþ»ùÏàÁ¬¹¹³ÉµÄ»¯ºÏÎï½Ðͪ(Èç±ûͪ             )£»¶ø·Ö±ð

 

ÓëÌþ»ùºÍÇâÏàÁ¬¹¹³ÉµÄ»¯ºÏÎï½ÐÈ©£¨ÈçÒÒÈ©CH3CHO£©¡£ÏÂÁд¼±»Ñõ»¯Ê±£¬²»¿ÉÄܵõ½È©À໯ºÏÎïµÄÊÇ        £¨    £©

  A£®(CH3)2CHOH                        B£®(CH3)2CHCH2OH

    C£®CH3CH2CH2OH                   D£®(CH3)3CCH2OH

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸