ij¶þÔªËáH2AµÄµçÀë·½³ÌʽÊÇ£ºH2A=H++HA-£¬HA-A2-+H+¡£»Ø´ðÏÂÁÐÎÊÌ⣺

¡¡ £¨1£©Na2AÈÜÒºÏÔ¡¡¡¡¡¡ ÐÔ£¬ÀíÓÉÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £»

¡¡ £¨2£©NaHAÈÜÒºÏÔ¡¡¡¡¡¡ ÐÔ¡±£¬ÀíÓÉÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £»

¡¡ £¨3£©Èô0.1mol?L-1NaHAÈÜÒºµÄpH=2£¬Ôò0.1mol?L-1H2AÈÜÒºÖÐÇâÀë×ÓµÄÎïÖʵÄÁ¿Å¨¶È¿ÉÄÜ¡¡¡¡¡¡ 0.11mol?L-1£¨Ìî¡°£¼¡±¡¢¡°£¾¡±»ò¡°=¡±£½£ºÀíÓÉÊÇ¡¡¡¡¡¡¡¡¡¡ ¡¡¡¡¡¡¡¡¡¡¡¡¡¡£»

¡¡ £¨4£©0.1mol?L-1NaHAÈÜÒºÖи÷Àë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£

£¨1£©¼îÐÔ  A2-+H2OHA-+OH-   £¨2£©ËáÐÔ  HA-H++A2-

   £¨3£©£¼   H2AµÚÒ»²½µçÀë²úÉúµÄH+¶ÔHA-µÄµçÀëÆðÁËÒÖÖÆ×÷ÓÃ

   £¨4£©c£¨Na+£©>c£¨HA-£©>c£¨H+£©>c£¨A2-£©>c£¨OH-£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ij¶þÔªËáH2AµÄµçÀëÇé¿öΪ£ºH2A=H++HA-£»HA-?H++A2-£®Çë¾Ý´Ë»Ø´ðÏÂÁÐÓйØÎÊÌ⣺
£¨1£©Na2AÈÜÒº³Ê
Èõ¼îÐÔ
Èõ¼îÐÔ
£¨Ìî¡°ÈõËáÐÔ¡±¡¢¡°ÖÐÐÔ¡±»ò¡°Èõ¼îÐÔ¡±£©£¬ÆäÀíÓÉÊÇ
A2-+H2O?OH-+HA-
A2-+H2O?OH-+HA-
£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£®
£¨2£©Ð´³öNaHAÈÜÒºÖÐÈÜÖʵçÀë³£Êý£¨Ka£©µÄ±í´ïʽ
Ka=
C(H+)£®C(A2-)
C(HA-)
Ka=
C(H+)£®C(A2-)
C(HA-)
£®
£¨3£©Èç¹û25¡æʱ£¬0.10mol?L-1 H2AÈÜÒºµÄpH=-lg0.11£¬Ôò0.10mol?L-1µÄH2AÈÜÒºÖÐc£¨A2-£©=
0.01
0.01
mol?L-1£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ij¶þÔªËáH2AµÄµçÀë·½³ÌʽÊÇ£ºH2A£½H++HA£ß£¬ HA£ß      A2£ß+H+¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Na2AÈÜÒºÏÔ       £¨Ìî¡°ËáÐÔ¡±¡¢¡°¼îÐÔ¡±»ò¡°ÖÐÐÔ¡±£©£¬ÀíÓÉÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©                                        £»

£¨2£©NaHAÈÜÒºÏÔ         £¨Ìî¡°ËáÐÔ¡±¡¢¡°¼îÐÔ¡±»ò¡°ÖÐÐÔ¡±£©£¬ÀíÓÉÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©                                                        £»

£¨3£©Èô0.1mol¡¤L-1¡¡NaHAÈÜÒºµÄpH=2£¬Ôò0.1mol¡¤L-1¡¡H2AÈÜÒºÖÐÇâÀë×ÓµÄÎïÖʵÄÁ¿Å¨¶È¿ÉÄÜ                 0.11mol¡¤L-1£¨Ìî¡°£¼¡±¡¢¡°£¾¡±»ò¡°=¡±£©£¬ÀíÓÉÊÇ                                               £»

£¨4£©0.1mol¡¤L-1¡¡NaHAÈÜÒºÖи÷Àë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ                                              ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨¢ñ£©»¯Ñ§Æ½ºâÒƶ¯Ô­Àí£¬Í¬ÑùÒ²ÊÊÓÃÓÚÆäËûƽºâ

£¨1£©ÒÑÖªÔÚ°±Ë®ÖдæÔÚÏÂÁÐƽºâ£ºNH3£«H2ONH3¡¤H2ONH£«OH£­

Ïò°±Ë®ÖмÓÈëMgCl2¹ÌÌåʱ£¬Æ½ºâÏò¡¡       Òƶ¯£¬OH£­µÄŨ¶È         

ÏòŨ°±Ë®ÖмÓÈëÉÙÁ¿NaOH¹ÌÌ壬ƽºâÏò         Òƶ¯£¬´Ëʱ·¢ÉúµÄÏÖÏóÊǣߣߣߣߣߣߣߣߣߣߣߡ£

£¨2£©ÂÈ»¯ÌúË®½âµÄÀë×Ó·½³ÌʽΪ£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£¬ÏòÂÈ

»¯ÌúÈÜÒºÖмÓÈë̼Ëá¸Æ·ÛÄ©£¬·¢ÏÖ̼Ëá¸ÆÖð½¥Èܽ⣬²¢²úÉúÎÞÉ«ÆøÌ壬ÆäÀë×Ó·½³Ì

ʽΪ£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£¬Í¬Ê±ÓкìºÖÉ«³ÁµíÉú³É£¬ÆäÔ­ÒòÊÇ    

_                      _____£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£

£¨3£©ÏòMg(OH)2µÄÐü×ÇÒºÖмÓÈëNH4ClÈÜÒº£¬ÏÖÏó                        £¬Ô­

ÒòΪ                                                                    

                                                                      ¡£

£¨¢ò£©Ä³¶þÔªËá H2A µÄµçÀë·½³ÌʽÊÇ£ºH2A=H++HA£¬HA-A2-+H+¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©H2AÊÇ          £¨Ìî¡°Ç¿µç½âÖÊ¡±»ò¡°Èõµç½âÖÊ¡±»ò¡°·Çµç½âÖÊ¡±£©

£¨2£©Na2A ÈÜÒºÏÔ      £¨Ìî¡°ËáÐÔ¡±¡¢¡°¼îÐÔ¡±»ò¡°ÖÐÐÔ¡±£©£¬ÀíÓÉÊÇ£¨ÓÃÀë×Ó·½

³Ìʽ±íʾ£©                                     £»

£¨3£©NaHA ÈÜÒºÏÔ     £¨Ìî¡°ËáÐÔ¡±¡¢¡°¼îÐÔ¡±»ò¡°ÖÐÐÔ¡±£©£¬ÀíÓÉÊÇ£¨ÓÃÀë×Ó·½

³Ìʽ±íʾ£©                       £»

£¨4£©Èô 0£®1mol¡¤L-1NaHA ÈÜÒºµÄ pH=2£¬Ôò 0£®1mol¡¤L-1 H2AÈÜÒºÖÐÇâÀë×ÓµÄÎïÖÊ

µÄÁ¿Å¨¶È¿ÉÄÜ    0£®11mol¡¤L£¨Ìî¡°£¼¡±¡¢¡°£¾¡±»ò¡°£½¡±£©£¬ÀíÓÉÊÇ£º                                                             £»

£¨5£©0£®1mol¡¤L NaHAÈÜÒºÖи÷Àë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ                                               ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêɽ¶«Ê¡Î«·»Êи߶þº®¼Ù×÷Òµ»¯Ñ§£¨Èý£©ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨¢ñ£©»¯Ñ§Æ½ºâÒƶ¯Ô­Àí£¬Í¬ÑùÒ²ÊÊÓÃÓÚÆäËûƽºâ
£¨1£©ÒÑÖªÔÚ°±Ë®ÖдæÔÚÏÂÁÐƽºâ£ºNH3£«H2ONH3¡¤H2O NH£«OH£­
Ïò°±Ë®ÖмÓÈëMgCl2¹ÌÌåʱ£¬Æ½ºâÏò¡¡      Òƶ¯£¬OH£­µÄŨ¶È         
ÏòŨ°±Ë®ÖмÓÈëÉÙÁ¿NaOH¹ÌÌ壬ƽºâÏò         Òƶ¯£¬´Ëʱ·¢ÉúµÄÏÖÏóÊǣߣߣߣߣߣߣߣߣߣߣߡ£
£¨2£©ÂÈ»¯ÌúË®½âµÄÀë×Ó·½³ÌʽΪ£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£¬ÏòÂÈ»¯ÌúÈÜÒºÖмÓÈë̼Ëá¸Æ·ÛÄ©£¬·¢ÏÖ̼Ëá¸ÆÖð½¥Èܽ⣬²¢²úÉúÎÞÉ«ÆøÌ壬ÆäÀë×Ó·½³ÌʽΪ£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£¬Í¬Ê±ÓкìºÖÉ«³ÁµíÉú³É£¬ÆäÔ­ÒòÊÇ    
£¨3£©ÏòMg(OH)2µÄÐü×ÇÒºÖмÓÈëNH4ClÈÜÒº£¬ÏÖÏó                        £¬Ô­
ÒòΪ                                                    
£¨¢ò£©Ä³¶þÔªËá H2A µÄµçÀë·½³ÌʽÊÇ£ºH2A=H++HA£¬HA-A2-+H+¡£»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©H2AÊÇ          £¨Ìî¡°Ç¿µç½âÖÊ¡±»ò¡°Èõµç½âÖÊ¡±»ò¡°·Çµç½âÖÊ¡±£©
£¨2£©Na2A ÈÜÒºÏÔ     £¨Ìî¡°ËáÐÔ¡±¡¢¡°¼îÐÔ¡±»ò¡°ÖÐÐÔ¡±£©£¬ÀíÓÉÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©                                     £»
£¨3£©NaHA ÈÜÒºÏÔ    £¨Ìî¡°ËáÐÔ¡±¡¢¡°¼îÐÔ¡±»ò¡°ÖÐÐÔ¡±£©£¬ÀíÓÉÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©                       £»
£¨4£©Èô 0£®1mol¡¤L-1NaHA ÈÜÒºµÄ pH=2£¬Ôò 0£®1mol¡¤L-1 H2AÈÜÒºÖÐÇâÀë×ÓµÄÎïÖʵÄÁ¿Å¨¶È¿ÉÄÜ  0.11mol¡¤L£¨Ìî¡°£¼¡±¡¢¡°£¾¡±»ò¡°£½¡±£©£¬ÀíÓÉÊÇ£º                   £»
£¨5£©0£®1mol¡¤L NaHAÈÜÒºÖи÷Àë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ                         ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ìɽ¶«Ê¡Î«·»Êи߶þº®¼Ù×÷Òµ»¯Ñ§£¨Èý£©ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨¢ñ£©»¯Ñ§Æ½ºâÒƶ¯Ô­Àí£¬Í¬ÑùÒ²ÊÊÓÃÓÚÆäËûƽºâ

£¨1£©ÒÑÖªÔÚ°±Ë®ÖдæÔÚÏÂÁÐƽºâ£ºNH3£«H2ONH3¡¤H2O NH£«OH£­

Ïò°±Ë®ÖмÓÈëMgCl2¹ÌÌåʱ£¬Æ½ºâÏò¡¡       Òƶ¯£¬OH£­µÄŨ¶È         

ÏòŨ°±Ë®ÖмÓÈëÉÙÁ¿NaOH¹ÌÌ壬ƽºâÏò          Òƶ¯£¬´Ëʱ·¢ÉúµÄÏÖÏóÊǣߣߣߣߣߣߣߣߣߣߣߡ£

£¨2£©ÂÈ»¯ÌúË®½âµÄÀë×Ó·½³ÌʽΪ£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£¬ÏòÂÈ

»¯ÌúÈÜÒºÖмÓÈë̼Ëá¸Æ·ÛÄ©£¬·¢ÏÖ̼Ëá¸ÆÖð½¥Èܽ⣬²¢²úÉúÎÞÉ«ÆøÌ壬ÆäÀë×Ó·½³Ì

ʽΪ£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£¬Í¬Ê±ÓкìºÖÉ«³ÁµíÉú³É£¬ÆäÔ­ÒòÊÇ    

_                       _____£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£

£¨3£©ÏòMg(OH)2µÄÐü×ÇÒºÖмÓÈëNH4ClÈÜÒº£¬ÏÖÏó                         £¬Ô­

ÒòΪ                                                                    

                                                                      ¡£

£¨¢ò£©Ä³¶þÔªËá H2A µÄµçÀë·½³ÌʽÊÇ£ºH2A=H++HA£¬HA-A2-+H+¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©H2AÊÇ           £¨Ìî¡°Ç¿µç½âÖÊ¡±»ò¡°Èõµç½âÖÊ¡±»ò¡°·Çµç½âÖÊ¡±£©

£¨2£©Na2A ÈÜÒºÏÔ      £¨Ìî¡°ËáÐÔ¡±¡¢¡°¼îÐÔ¡±»ò¡°ÖÐÐÔ¡±£©£¬ÀíÓÉÊÇ£¨ÓÃÀë×Ó·½

³Ìʽ±íʾ£©                                      £»

£¨3£©NaHA ÈÜÒºÏÔ     £¨Ìî¡°ËáÐÔ¡±¡¢¡°¼îÐÔ¡±»ò¡°ÖÐÐÔ¡±£©£¬ÀíÓÉÊÇ£¨ÓÃÀë×Ó·½

³Ìʽ±íʾ£©                        £»

£¨4£©Èô 0£®1mol¡¤L-1NaHA ÈÜÒºµÄ pH=2£¬Ôò 0£®1mol¡¤L-1 H2AÈÜÒºÖÐÇâÀë×ÓµÄÎïÖÊ

µÄÁ¿Å¨¶È¿ÉÄÜ    0£®11mol¡¤L£¨Ìî¡°£¼¡±¡¢¡°£¾¡±»ò¡°£½¡±£©£¬ÀíÓÉÊÇ£º                                                              £»

£¨5£©0£®1mol¡¤L NaHAÈÜÒºÖи÷Àë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ                                               ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸