Question

³£Î³£Ñ¹Ï£¬½«a mol CO₂ÆøÌåͨÈë1L bmol/LµÄNaOHÈÜÒºÖУ¬ÏÂÁжÔËùµÃÈÜÒºµÄÃèÊö²»ÕýÈ·µÄÊÇ(    )

A£®µ±1/2£¼a/b£¼1ʱ£¬ËùµÃÈÜÒºÖÐÒ»¶¨´æÔÚ£ºc£¨Na£«£©£«c£¨H£«£©£½2c£¨CO32-£©£«c£¨HCO3£­£©£«c£¨OH£­£©

B£®µ±a£½bʱ£¬ËùµÃÈÜÒºÖдæÔÚ£ºc£¨OH£­£©£«c£¨CO32-£©£½c£¨H£«£©£«c£¨H2CO3£©

C£®µ±a/b=2/3ʱ£¬ËùµÃÈÜÒºÖдæÔÚ£º3c£¨Na£«£©£½2c£¨CO32-£©£«2c£¨HCO3£­£©£«2c£¨H2CO3£©

D£®µ±2a£½bʱ£¬ËùµÃÈÜÒºÖдæÔÚ£ºc£¨Na£«£©£¾c£¨CO32-£©£¾c£¨OH£­£©£¾c£¨HCO3£­£©£¾c£¨H£«£©

Answer 1

C

ÊÔÌâ·ÖÎö£ºµ±1/2£¼a/b£¼1ʱ£¬¶þÑõ»¯Ì¼ºÍÇâÑõ»¯ÄÆ·´Ó¦Éú³É̼ËáÇâÄƺÍ̼ËáÄÆ£¬¸ù¾ÝµçºÉÊغãÖª£¬Ì¼ËáÇâÄÆÖдæÔÚc£¨Na⁺£©+ c£¨H^£«£©=2c£¨CO₃^2-£©+c £¨HCO₃^-£©+c £¨OH^¡ª£©£¬AÏîÕýÈ·£»µ±a=bʱ£¬¶þÑõ»¯Ì¼ºÍÇâÑõ»¯ÄÆ·´Ó¦Ç¡ºÃÉú³É̼ËáÇâÄƵ±a=b£¬¶þÑõ»¯Ì¼ºÍÇâÑõ»¯ÄÆÇ¡ºÃ·´Ó¦Éú³É̼ËáÇâÄÆ£¬¸ù¾ÝÎïÁÏÊغãÖª£¬Ì¼ËáÇâÄÆÖдæÔÚc£¨Na⁺£©=c£¨CO₃^2-£©+c £¨HCO₃^-£©+c £¨H₂CO₃£©¢Ù£¬¸ù¾ÝµçºÉÊغãÖª£¬c£¨Na⁺£©+c £¨H⁺£©=2c£¨CO₃^2-£©+c £¨HCO₃^-£©+c £¨OH^-£©¢Ú£¬½«¢Ú-¢ÙµÃc£¨CO₃^2-£©+c£¨OH^-£©=c £¨H⁺£©+c £¨H₂CO₃£©£¬BÏîÕýÈ·£»µ±a/b=2/3ʱ£¬¶þÑõ»¯Ì¼ºÍÇâÑõ»¯ÄÆ·´Ó¦Éú³É̼ËáÇâÄƺÍ̼ËáÄÆÖ®±ÈΪ1£º1£¬¸ù¾ÝÎïÁÏÊغãÖª£¬Ì¼ËáÇâÄÆÖдæÔÚc£¨Na⁺£©=c£¨CO₃^2-£©+c £¨HCO₃^-£©+c £¨H₂CO₃£©¢Ù£¬Ì¼ËáÄÆÖдæÔÚc£¨Na⁺£©=2c£¨CO₃^2-£©+2c £¨HCO₃^-£©+2c £¨H₂CO₃£©¢Ú£¬½«¢Ú+¢ÙµÃ2c£¨Na^£«£©£½3c£¨CO₃^2-£©£«3c£¨HCO₃^£­£©£«3c£¨H₂CO₃£©£¬¹ÊCÑ¡Ïî´íÎó£»µ±2a£½bʱ£¬¶þÑõ»¯Ì¼ºÍÇâÑõ»¯ÄÆ·´Ó¦Ç¡ºÃÉú³É̼ËáÄÆ£¬ÄÆÀë×Ó²»Ë®½â£¬Ì¼Ëá¸ùÀë×ÓË®½â£¬ËùÒÔc£¨Na⁺£©£¾c£¨CO₃^2-£©£¬Ì¼Ëá¸ùÀë×ÓºÍ̼ËáÇâ¸ùÀë×ÓË®½â¶¼²úÉúÇâÑõ¸ùÀë×Ó£¬µ«Ë®½â½Ï΢Èõ£¬ÇÒÖ»ÓÐ̼Ëá¸ùÀë×ÓË®½â²úÉú̼ËáÇâ¸ùÀë×Ó£¬ËùÒÔc£¨CO₃^2-£©£¾c£¨OH^-£©£¾c£¨HCO₃^-£©£¬DÕýÈ·£»Ñ¡C¡£