¡¾ÌâÄ¿¡¿Èçͼ£¬B,C·Ö±ðÊǺ£°¶ÏßÉϵÄÁ½¸ö³ÇÊУ¬Á½³ÇÊмäÓɱÊÖ±µÄº£±õ¹«Â·ÏàÁ¬£¬B£¬CÖ®¼äµÄ¾àÀëΪ100km£¬º£µºAÔÚ³ÇÊÐBµÄÕý¶«·½50
´¦£®´Óº£µºAµ½³ÇÊÐC£¬Ïȳ˴¬°´±±Æ«Î÷¦È½Ç£¨
£¬ÆäÖÐÈñ½Ç
µÄÕýÇÐֵΪ
£©º½Ðе½º£°¶¹«Â·P´¦µÇ½£¬ÔÙ»»³ËÆû³µµ½³ÇÊÐC£®ÒÑÖª´¬ËÙΪ25km/h£¬³µËÙΪ75km/h.
£¨1£©ÊÔ½¨Á¢ÓÉA¾Pµ½CËùÓÃʱ¼äÓë
µÄº¯Êý½âÎöʽ£»
£¨2£©ÊÔÈ·¶¨µÇ½µãPµÄλÖã¬Ê¹ËùÓÃʱ¼ä×îÉÙ£¬²¢ËµÃ÷ÀíÓÉ£®
![]()
¡¾´ð°¸¡¿£¨1£©
£¬¶¨ÒåÓòΪ
£¨2£©17.68
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©ÓÉÂÖ´¬º½Ðеķ½Î»½ÇΪ
£¬¿ÉµÃ
£¬
£¬ÓÉÖ±½ÇÈý½ÇÐεÄÐÔÖʼ°Èý½Çº¯ÊýµÄ¶¨Òå¿ÉµÃ
£¬
£¬ËùÒÔ
£¬ÔòÓÉ
¾
µ½
ËùÓÃʱ¼äÓë
µÄº¯Êý¹ØÏµÎª
£¬¿ÉµÃº¯Êý
µÄ¶¨ÒåÓòΪ
£¬ÆäÖÐÈñ½Ç
µÄÕýÇÐֵΪ
£»£¨2£©ÀûÓõ¼ÊýÑо¿º¯Êý
µÄµ¥µ÷ÐÔ£¬¿ÉµÃ
ÔÚ
Éϵݼõ£¬ÔÚ
ÉϵÝÔö£¬£¨
£©£¬ËùÒԿɵÃ
ʱº¯Êý
È¡µÃ×îСֵ£¬´Ëʱ
¡Ö17.68.
ÊÔÌâ½âÎö£º£¨1£©ÓÉÌâÒ⣬ÂÖ´¬º½Ðеķ½Î»½ÇΪ¦È£¬ËùÒÔ
£¬
£¬Ôò
£¬
£®
£® ÓÉAµ½PËùÓõÄʱ¼äΪ
£¬ÓÉPµ½CËùÓõÄʱ¼äΪ
£¬ËùÒÔÓÉA¾Pµ½CËùÓÃʱ¼äÓë¦ÈµÄº¯Êý¹ØÏµÎª
£®º¯Êý
µÄ¶¨ÒåÓòΪ
£¬ÆäÖÐÈñ½Ç
µÄÕýÇÐֵΪ
.
£¨2£©ÓÉ£¨1£©£¬
£¬
£¬
£¬Áî
£¬½âµÃ
£¬Éè¦È0
£¬Ê¹![]()
|
| ¦È0 |
|
|
| 0 |
|
| ¼õº¯Êý | ¼«Ð¡Öµ | Ôöº¯Êý |
ËùÒÔ£¬µ±
ʱº¯Êýf(¦È)È¡µÃ×îСֵ£¬´ËʱBP=
¡Ö17.68
£¬
´ð£ºÔÚBCÉÏÑ¡Ôñ¾àÀëBΪ17.68
´¦ÎªµÇ½µã£¬ËùÓÃʱ¼ä×îÉÙ£®
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÒÑÖªº¯Êý
£¬£¨ÆäÖÐ
£©µÄͼÏóÓëxÖáµÄ½»µãÖУ¬ÏàÁÚÁ½¸ö½»µãÖ®¼äµÄ¾àÀëΪ
£¬ÇÒͼÏóÉÏÒ»¸ö×îµÍµãΪ
£®
£¨¢ñ£©Çó
µÄ½âÎöʽ£»
£¨¢ò£©µ±
£¬Çó
µÄÖµÓò£®
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿½üÄêÀ´£¬ÍøÂçµçÉÌÒѾÇÄÈ»½øÈëÁ˹ã´óÊÐÃñµÄÈÕ³£Éú»î£¬²¢ÂýÂý¸Ä±äÁËÈËÃǵÄÏû·Ñ·½Ê½ÎªÁ˸üºÃµØ·þÎñÃñÖÚ£¬Ä³µçÉÌÔÚÆä¹Ù·½APPÖÐÉèÖÃÁËÓû§ÆÀ¼Û·´À¡ÏµÍ³£¬ÒÔÁ˽âÓû§¶ÔÉÌÆ·×´¿öºÍÓŻݻµÄÆÀ¼ÛÏÖ´ÓÆÀ¼ÛϵͳÖÐËæ»ú³é³ö200Ìõ½ÏΪÏêϸµÄÆÀ¼ÛÐÅÏ¢½øÐÐͳ¼Æ£¬ÉÌÆ·×´¿öºÍÓŻݻÆÀ¼ÛµÄ2¡Á2ÁÐÁª±íÈçÏ£º
¶ÔÓŻݻºÃÆÀ | ¶ÔÓŻݻ²»ÂúÒâ | ºÏ¼Æ | |
¶ÔÉÌÆ·×´¿öºÃÆÀ | 100 | 20 | 120 |
¶ÔÉÌÆ·×´¿ö²»ÂúÒâ | 50 | 30 | 80 |
ºÏ¼Æ | 150 | 50 | 200 |
£¨I£©ÄÜ·ñÔÚ·¸´íÎóµÄ¸ÅÂʲ»³¬¹ý0.001µÄǰÌáÏÂÈÏΪÓŻݻºÃÆÀÓëÉÌÆ·×´¿öºÃÆÀÖ®¼äÓйØÏµ£¿
£¨¢ò£©ÎªÁË»ØÀ¡Óû§£¬¹«Ë¾Í¨¹ýAPPÏòÓû§Ëæ»úÅÉËÍÿÕÅÃæ¶îΪ0Ôª£¬1Ôª£¬2ÔªµÄÈýÖÖÓÅ»ÝȯÓû§Ã¿´ÎʹÓÃAPP¹ºÎïºó£¬¶¼¿É»ñµÃÒ»ÕÅÓÅ»Ýȯ£¬ÇÒ¹ºÎïÒ»´Î»ñµÃ1ÔªÓÅ»Ýȯ£¬2ÔªÓÅ»ÝȯµÄ¸ÅÂÊ·Ö±ðÊÇ
£¬
£¬¸÷´Î»ñÈ¡ÓÅ»ÝȯµÄ½á¹ûÏ໥¶ÀÁ¢ÈôijÓû§Ò»ÌìʹÓÃÁËAPP¹ºÎïÁ½´Î£¬¼Ç¸ÃÓû§µ±Ìì»ñµÃµÄÓÅ»ÝÈ¯Ãæ¶îÖ®ºÍΪX£¬ÇóËæ»ú±äÁ¿XµÄ·Ö²¼ÁкÍÊýѧÆÚÍû£®
²Î¿¼Êý¾Ý
P£¨K2¡Ýk£© | 0.150 | 0.100 | 0.050 | 0.025 | 0.010 | 0.005 | 0.001 |
k | 2.072 | 2.706 | 3.841 | 5.024 | 6.635 | 7.879 | 10.828 |
²Î¿¼¹«Ê½£ºK2
£¬ÆäÖÐn£½a+b+c+d
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿Ä³¹«Ô°Óû½«Ò»¿é¿ÕµØ¹æ»®³ÉÈçͼËùʾµÄÇøÓò£¬ÆäÖÐÔڱ߳¤Îª20Ã×µÄÕý·½ÐÎ
ÄÚÖÖÖ²¾ºìÉ«Óô½ðÏ㣬ÔÚÕý·½ÐÎ
µÄÊ£Óಿ·Ö£¨¼´ËĸöÖ±½ÇÈý½ÇÐÎÄÚ£©ÖÖÖ²»ÆÉ«Óô½ðÏ㣮ÏÖÒªÔÚÒÔ
Ϊ±ß³¤µÄ¾ØÐÎ
ÄÚÖÖÖ²ÂÌÉ«²Ýƺ£¬ÒªÇóÂÌÉ«²ÝƺµÄÃæ»ýµÈÓÚ»ÆÉ«Óô½ðÏãµÄÃæ»ý£®Éè
£¬
Ã×£®
![]()
£¨1£©Çó
Óë
Ö®¼äµÄº¯Êý¹ØÏµÊ½£»
£¨2£©Çó
µÄ×î´óÖµ£®
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿Èçͼ£¬ÔÚÕý·½Ìå
ÖУ¬ÒÑÖªE£¬F£¬G£¬H·Ö±ðÊÇA1D1£¬B1C1£¬D1D£¬C1CµÄÖе㣮
£¨1£©ÇóÖ¤£ºEF¡ÎÆ½ÃæABHG£»
£¨2£©ÇóÖ¤£ºÆ½ÃæABHG¡ÍÆ½ÃæCFED£®
![]()
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÍøÂçÓÎϷҪʵÏֿɳÖÐø·¢Õ¹£¬±ØÐëÒª·¢Õ¹ÂÌÉ«ÍøÓÎ.Ϊ´Ë£¬¹ú¼ÒÎÄ»¯²¿½«´ÓÄÚÈÝÉ϶ÔÍøÓÎ×÷³öÇ¿ÖÆ¹æ¶¨£¬¹ú¼ÒÐÅÏ¢²úÒµ²¿»¹½«´Ó¼¼ÊõÉϼÓÇ¿¶ÔÍøÓεÄÇ¿ÖÆÏÞÖÆ£¬¿ª·¢ÏÞÖÆÍøñ«µÄÆ£ÀÍϵͳ£¬ÏÖÒÑ¿ª·¢µÄ¡°ÓÎÏ··À³ÁÃÔϵͳ¡±¹æÔòÈçÏ£º
¢Ù
СʱÒÔÄÚ£¨º¬
Сʱ£©Îª½¡¿µÊ±¼ä£¬Íæ¼ÒÔÚÕâ¶Îʱ¼äÄÚ»ñµÃµÄÀÛ»ý¾ÑéÖµ
£¨µ¥Î»£º
£©ÓëÓÎϷʱ¼ä
£¨Ð¡Ê±£©Âú×ã¹ØÏµÊ½£º
£¨
Ϊ³£Êý£©£»
¢Ú
Сʱµ½
Сʱ£¨º¬
Сʱ£©ÎªÆ£ÀÍʱ¼ä£¬Íæ¼ÒÔÚÕâ¶Îʱ¼äÄÚ»ñµÃµÄ¾ÑéֵΪ
£¨¼´ÀÛ»ý¾ÑéÖµ²»±ä£©£»
¢Û³¬¹ý
СʱΪ²»½¡¿µÊ±¼ä£¬ÀÛ»ý¾ÑéÖµ¿ªÊ¼Ëðʧ£¬ËðʧµÄ¾ÑéÖµÓë²»½¡¿µÊ±¼ä³ÉÕý±ÈÀý¹ØÏµ£¬±ÈÀýϵÊýΪ
.
£¨1£©µ±
ʱ£¬Ð´³öÀÛ»ý¾ÑéÖµ
ÓëÓÎϷʱ¼ä
µÄº¯Êý¹ØÏµÊ½
£¬²¢Çó³öÓÎÏ·
СʱµÄÀÛ»ý¾ÑéÖµ£»
£¨2£©¶¨Òå¡°Íæ¼ÒÓäÔÃÖ¸Êý¡±ÎªÀÛ»ý¾ÑéÖµ
ÓëÓÎϷʱ¼ä
µÄ±ÈÖµ£¬¼Ç×÷
£»Èô
£¬¿ª·¢²¿ÃÅÏ£ÍûÔÚ½¡¿µÊ±¼äÄÚ£¬Õâ¿îÓÎÏ·µÄ¡°Íæ¼ÒÓäÔÃÖ¸Êý¡±²»µÍÓÚ
£¬ÇóʵÊý
µÄȡֵ·¶Î§.
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿´Ó¼×ÒÒÁ½°à¸÷Ëæ»ú³éÈ¡10Ãûͬѧ,ÈçͼËùʾµÄ¾¥Ò¶Í¼¼Ç¼ÁËÕâ20ÃûͬѧÔÚ2018Äê¸ß¿¼ÓïÎÄ×÷ÎÄÌâÄ¿Öеijɼ¨(µ¥Î»:·Ö).ÒÑÖªÓïÎÄ×÷ÎÄÌâÄ¿Âú·ÖΪ60·Ö,¡°·ÖÊý
·Ö,Ϊ¼°¸ñ:·ÖÊý
·Ö,Ϊ¸ß·Ö¡±,Èô¼×ÒÒÁ½°àµÄ³É¼¨µÄƽ¾ù·Ö¶¼ÊÇ44·Ö.
![]()
(1)Çó
,
µÄÖµ;
(2)Èô·Ö±ð´Ó¼×ÒÒÁ½°àËæ»ú¸÷³éÈ¡1Ãû³É¼¨Îª¸ß·ÖµÄѧÉú,Çó³éµ½µÄѧÉúÖÐ,¼×°àѧÉú³É¼¨¸ßÓÚÒÒ°àѧÉú³É¼¨µÄ¸ÅÂÊ.
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÒÑÖª¼¯ºÏ
£¬¶ÔÓÚ
µÄÒ»¸ö×Ó¼¯
£¬Èô´æÔÚ²»´óÓÚ
µÄÕýÕûÊý
£¬Ê¹µÃ¶Ô
ÖеÄÈÎÒâÒ»¶ÔÔªËØ
¡¢
£¬¶¼ÓÐ
£¬Ôò³Æ
¾ßÓÐÐÔÖÊ
.
£¨1£©µ±
ʱ£¬ÊÔÅжϼ¯ºÏ
ºÍ
ÊÇ·ñ¾ßÓÐÐÔÖÊ
£¿²¢ËµÃ÷ÀíÓÉ£»
£¨2£©µ±
ʱ£¬Èô¼¯ºÏ
¾ßÓÐÐÔÖÊ
.
¢ÙÄÇô¼¯ºÏ
ÊÇ·ñÒ»¶¨¾ßÓÐÐÔÖÊ
£¿²¢ËµÃ÷ÀíÓÉ£»
¢ÚÇ󼯺Ï
ÖÐÔªËØ¸öÊýµÄ×î´óÖµ.
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÒÑÖªº¯Êý
.
£¨1£©ÌÖÂÛº¯Êý
µÄµ¥µ÷ÐÔ£»
£¨2£©Èôº¯Êý
ÔÚÇø¼ä
ÉÏ´æÔÚÁ½¸ö²»Í¬Áãµã£¬ÇóʵÊý
µÄȡֵ·¶Î§.
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com