![]()
| µ±×ÔÐгµ³µÂÖת¶¯Ê±£¬Í¨¹ýĦ²ÁСÂÖʹ·¢µç»úµÄÏß¿òÔÚÔÈÇ¿´Å³¡ÄÚת¶¯£¬Ïß¿òÖвúÉúÒ»ÕýÏÒ½»Á÷µç¶¯ÊÆ£¬Æä×î´óÖµ
Em=w0BSN ʽÖÐw0ΪÏß¿òת¶¯µÄ½ÇËÙ¶È£¬¼´Ä¦²ÁСÂÖת¶¯µÄ½ÇËÙ¶È£®·¢µç»úÁ½¶ËµçѹµÄÓÐЧֵ
Éè×ÔÐгµ³µÂÖת¶¯µÄ½ÇËÙ¶ÈΪw1£¬ÓÉÓÚ×ÔÐгµ³µÂÖÓëĦ²ÁСÂÖÖ®¼äÎÞÏà¶Ô»¬¶¯£¬ÓÐ R1w1=r0w 0 С³ÝÂÖת¶¯µÄ½ÇËÙ¶ÈÓë×ÔÐгµ³µÂÖת¶¯µÄ½ÇËÙ¶ÈÏàͬ£¬Ò²Îªw1£®Éè´ó³ÝÂÖת¶¯µÄ½ÇËÙ¶ÈΪw £¬ÓÐ R3w =R2w 1 ÓÉÒÔÉϸ÷ʽ½âµÃ
´úÈëÊý¾ÝµÃ w =3.2rad£¯s
|
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£ºÎïÀí½ÌÑÐÊÒ ÌâÐÍ£º038
£¨1£©»³ö²âÁ¿RµÄµç·ͼ£®
£¨2£©Í¼aÖеÄ6¸öµã±íʾʵÑéÖвâµÃµÄ6×éµçÁ÷I¡¢µçѹUµÄÖµ£¬ÊÔд³ö¸ù¾Ý´ËͼÇóRÖµµÄ²½Ö裬
Çó³öµÄµç×èÖµR=________________£¨±£Áô3λÓÐЧÊý×Ö£©
![]()
![]()
![]()
ͼ
£¨3£©´ý²âµç×èÊÇÒ»¸öÓɾùÔȲÄÁÏÖÆ³ÉµÄÔ²ÖùÌ壬ÓÃÓαêΪ50·Ö¶ÈµÄ¿¨³ß²âÁ¿Æä³¤¶ÈÓëÖ±¾¶£¬½á¹û·Ö±ðÈçͼb¡¢Í¼cËùʾ£®ÓÉͼ¿ÉÖªÆä³¤¶ÈΪ_______£¬Ö±¾¶Îª________£®
£¨4£©ÓÉÒÔÉÏÊý¾Ý¿ÉÇó³ö________£®£¨±£Áô3λÓÐЧÊý×Ö£©
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º013
(2003¡¤È«¹ú¸ß¿¼)ÈçͼËùʾ£¬ÈÃÌ«Ñô¹â»ò°×³ãµÆ¹âͨ¹ýÆ«ÕñƬPºÍQ£¬ÒÔ¹âµÄ´«²¥·½ÏòΪÖáÐýתƫÕñƬP»òQ£¬¿ÉÒÔ¿´µ½Í¸Éä¹âµÄÇ¿¶È»á·¢Éú±ä»¯£¬ÕâÊǹâµÄÆ«ÕñÏÖÏó£®Õâ¸öʵÑé±íÃ÷
[¡¡¡¡]
![]()
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º038
£¨2003¡¤È«¹ú£©ÈçͼËùʾ£¬Ôø¾Á÷ÐйýÒ»ÖÖÏò×ÔÐгµ³µÍ·µÆ¹©µçµÄСÐͽ»Á÷·¢µç»ú£¬Í¼aΪÆä½á¹¹Ê¾Òâͼ£¬Í¼ÖÐN¡¢SÊÇÒ»¶Ô¹Ì¶¨µÄ´Å¼«£¬abcdΪ¹Ì¶¨ÔÚתÖáÉϵľØÐÎÏß¿ò£¬×ªÖá¹ýbc±ßÖеãÓëab±ßƽÐУ¬ËüµÄÒ»¶ËÓÐÒ»°ë¾¶r0=1.0cmµÄĦ²ÁСÂÖ£¬Ð¡ÂÖÓë×ÔÐгµ³µÂֵıßÔµÏà½Ó´¥£¬ÈçͼbËùʾ£®µ±³µÂÖת¶¯Ê±£¬ÒòĦ²Á¶ø´ø¶¯Ð¡ÂÖת¶¯£¬´Ó¶øÊ¹Ïß¿òÔڴż«¼äת¶¯£¬ÉèÏß¿òÓÉN=800Ôѵ¼ÏßȦ×é³É£¬Ã¿ÔÑÏßȦµÄÃæ»ýS=20cm2£¬´Å¼«¼äµÄ´Å³¡¿ÉÊÓ×÷ÔÈÇ¿´Å³¡£¬´Å¸ÐӦǿ¶ÈB=0.010T£¬×ÔÐгµ³µÂֵİ뾶R1=35cm£¬Ð¡³ÝÂֵİ뾶R2=4.0cm£®´ó³ÝÂֵİ뾶R3=10.0cm£¨¼ûͼb£©£®ÏÖ´Ó¾²Ö¹¿ªÊ¼Ê¹´ó³ÝÂÖ¼ÓËÙת¶¯£¬ÎÊ´ó³ÝÂֵĽÇËÙ¶ÈΪ¶à´ó²ÅÄÜʹ·¢µç»úÊä³öµçѹµÄÓÐЧֵU=3.2V£®£¨¼Ù¶¨Ä¦²ÁСÂÖÓë×ÔÐгµ³µÂÖÖ®¼äÎÞÏà¶Ô»¬¶¯£©
![]()
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º038
(2003¡¤È«¹úпγ̾í)Èçͼ¼×ËùʾΪһ¸ùÊúÖ±Ðü¹ÒµÄ²»¿ÉÉ쳤µÄÇáÉþ£¬Ï¶Ë˩һСÎï¿éA£¬É϶˹̶¨ÔÚCµãÇÒÓëÒ»ÄܲâÁ¿ÉþµÄÀÁ¦µÄ²âÁ¦´«¸ÐÆ÷ÏàÁ¬£®ÒÑÖªÓÐÒ»ÖÊÁ¿Îª
µÄ×Óµ¯BÑØË®Æ½·½ÏòÒÔËÙ¶È
ÉäÈëAÄÚ(δ´©Í¸)£¬½Ó×ÅÁ½ÕßÒ»ÆðÈÆCµãÔÚÊúÖ±ÃæÄÚ×öÔ²ÖÜÔ˶¯£¬ÔÚ¸÷ÖÖ×èÁ¦¶¼¿ÉºöÂÔµÄÌõ¼þÏ£¬²âÁ¦´«¸ÐÆ÷²âµÃÉþµÄÀÁ¦FËæÊ±¼ätµÄ±ä»¯¹ØÏµÈçͼÒÒËùʾ£®ÒÑÖª×Óµ¯ÉäÈëµÄʱ¼ä¼«¶Ì£¬ÇÒͼÒÒÖÐ
ΪA¡¢B¿ªÊ¼ÒÔÏàͬËÙ¶ÈÔ˶¯µÄʱ¿Ì£®¸ù¾ÝÁ¦Ñ§¹æÂɺÍÌâÖÐ(°üÀ¨Í¼)ÌṩµÄÐÅÏ¢£¬¶Ô·´Ó³Ðü¹Òϵͳ±¾ÉíÐÔÖʵÄÎïÀíÁ¿(ÀýÈçAµÄÖÊÁ¿)¼°A¡¢BÒ»ÆðÔ˶¯µÄ¹ý³ÌÖÐÊØºãÁ¿£¬ÄãÄÜÇóµÃÄÄЩ¶¨Á¿µÄ½á¹û?
![]()
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com