ÈçͼËùʾ£¬³¤Îª2LµÄÇá¸Ë£¬Á½¶Ë¸÷¹Ì¶¨Ò»Ð¡Çò£¬AÇòÖÊÁ¿Îªm1£¬BÇòÖÊÁ¿Îªm2£¬ÇÒm1£¾m2£¬¹ý¸ËµÄÖеãOÓÐһˮƽ¹â»¬¹Ì¶¨Öᣬ¸Ë¿ÉÔÚ²»Í¬µÄ³õʼÌõ¼þÏÂÈÆÖáÔÚÊúֱƽÃæÄÚת¶¯£®ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®AÇòµ½×î¸ßµãµÄËٶȿÉÒÔΪÁã
B£®BÇòµ½×îµÍµãµÄËÙ¶ÈÒ»¶¨²»ÎªÁã
C£®Èô¸Ë¶ÔÖáµÄ×÷ÓÃÁ¦ÎªÁ㣬Ôò´Ëʱ¸ËµÄ½ÇËÙ¶ÈΪ
(m1+m2)g
(m1-m2)L
D£®Í¼Ê¾Î»Öø˶ÔBÇòµÄ×îСÀ­Á¦Ò»¶¨²»Îªm2g
¾«Ó¢¼Ò½ÌÍø
A¡¢¸ËÄ£ÐÍAÇòµ½×î¸ßµãµÄËٶȿÉÒÔΪÁ㣮µ±AÇòËÙ¶ÈΪÁãʱ£¬BÇòËÙ¶ÈҲΪÁ㣮¹ÊAÕýÈ·£¬B´íÎó£®
C¡¢ÔÚ×îµÍµãÓУºF2-m2g=m2L¦Ø2£¬½âµÃF2=m2g+m2L¦Ø2£®ÔÚ×î¸ßµã£¬ÓУºF1+m1g=mL¦Ø2£¬½âµÃF1=mL¦Ø2-m1g£®ÔòF1=F2£¬½âµÃ¦Ø=
(m1+m2)g
(m1-m2)L
£®¹ÊCÕýÈ·£®
D¡¢ÔÚͼʾλÖã¬BÇòµÄ×îСËÙ¶ÈΪÁ㣬Ôò×îСÀ­Á¦Îªm2g£®¹ÊD´íÎó£®
¹ÊÑ¡AC£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ÈçͼËùʾ£¬³¤Îª2LµÄÇá¸Ë£¬Á½¶Ë¸÷¹Ì¶¨Ò»Ð¡Çò£¬AÇòÖÊÁ¿Îªm1£¬BÇòÖÊÁ¿Îªm2£¬¹ý¸ËµÄÖеãOÓÐһˮƽ¹â»¬¹Ì¶¨Öᣬ¸Ë¿ÉÈÆÖáÔÚÊúֱƽÃæÄÚת¶¯£®µ±×ª¶¯µ½ÊúֱλÖÃÇÒAÇòÔÚÉ϶ˣ¬BÇòÔÚ϶Ëʱ¸ËµÄ½ÇËÙ¶ÈΪ¦Ø£¬´Ëʱ¸Ë¶ÔתÖáµÄ×÷ÓÃÁ¦ÎªÁ㣬ÔòA¡¢BÁ½Ð¡ÇòµÄÖÊÁ¿Ö®±ÈΪ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ÈçͼËùʾ£¬³¤Îª2LµÄÇá¸Ë£¬Á½¶Ë¸÷¹Ì¶¨Ò»Ð¡Çò£¬AÇòÖÊÁ¿Îªm1£¬BÇòÖÊÁ¿Îªm2£¬ÇÒm1£¾m2£¬¹ý¸ËµÄÖеãOÓÐһˮƽ¹â»¬¹Ì¶¨Öᣬ¸Ë¿ÉÔÚ²»Í¬µÄ³õʼÌõ¼þÏÂÈÆÖáÔÚÊúֱƽÃæÄÚת¶¯£®ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ÈçͼËùʾ£¬³¤Îª2LµÄ°åÃæ¹â»¬ÇÒ²»µ¼µçµÄƽ°åС³µC·ÅÔڹ⻬ˮƽÃæÉÏ£¬³µµÄÓÒ¶ËÓеµ°å£¬³µµÄÖÊÁ¿mC=4m£®½ñÔÚ¾²Ö¹µÄƽ°å³µµÄ×ó¶Ë·ÅÒ»¸ö´øµçÁ¿Îª+q£®ÖÊÁ¿ÎªmµÄÎï¿éA£¬ÔÚÖмäλÖ÷ÅÒ»¸ö¾øÔµÎïÌåB£¬ÖÊÁ¿ÎªmB=2m£®ÔÚÕû¸ö¿Õ¼ä¼ÓÉÏÒ»¸öˮƽ·½ÏòµÄÔÈÇ¿µç³¡Ê±£¬½ðÊô¿éAÓɾ²Ö¹¿ªÊ¼ÏòÓÒÔ˶¯£¬²¢ÒÔËÙ¶Èv0ÓëB·¢ÉúÅöײ£¬ÅöºóAÒÔ
v04
µÄËٶȷ´µ¯»ØÀ´£¬BÒÔÒ»¶¨ËÙ¶ÈÑØƽ°åÏòÓÒÔ˶¯ÓëC³µµÄµµ°åÏàÅö£®ÅöºóС³µµÄËٶȵÈÓÚÅöÇ°Îï¿éBËٶȵÄÒ»°ë£®Îï¿éA£®B¾ùÊÓΪÖʵ㣬A£®BÏàÅöʱµÄÏ໥×÷ÓÃÁ¦Ô¶´óÓڵ糡Á¦£¬AºÍBÅöײʱËù´øµçºÉÁ¿²»±ä£®Çó£º
£¨1£©ÔÈÇ¿µç³¡µÄ³¡Ç¿´óСºÍ·½Ïò£®
£¨2£©ÈôAµÚ¶þ´ÎÓëBÏàÅö£¬ÅжÏÊÇÔÚBÓëCÏàÅö֮ǰ»¹ÊÇÏàÅöÖ®ºó£¿
£¨3£©A´ÓµÚÒ»´ÎÓëBÏàÅöµ½µÚ¶þ´ÎÓëBÏàÅöµÄÕâ¶Îʱ¼äÄÚ£¬µç³¡Á¦¶ÔA×öµÄ¹¦£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

£¨2005?ÉîÛÚһģ£©ÈçͼËùʾ£¬³¤Îª2LµÄ°åÃæ¹â»¬ÇÒ²»µ¼µçµÄƽ°åС³µC·ÅÔڹ⻬ˮƽÃæÉÏ£¬³µµÄÓÒ¶ËÓе²°å£¬³µµÄÖÊÁ¿mC=4m£®½ñÔÚ¾²Ö¹µÄƽ°å³µµÄ×ó¶Ë·ÅÒ»¸ö´øµçºÉÁ¿Îª+q¡¢ÖÊÁ¿ÎªmA=mµÄ½ðÊô¿éA£¬Áí½«Ò»¾øԵСÎï¿éB·ÅÔÚƽ°å³µµÄÖÐÑ룬Îï¿éBµÄÖÊÁ¿mB=2m£®ÔÚÕû¸ö¿Õ¼ä¼ÓÉÏÒ»¸öˮƽ·½ÏòµÄÔÈÇ¿µç³¡Ê±£¬½ðÊô¿éAÓɾ²Ö¹¿ªÊ¼ÏòÓÒÔ˶¯£¬AÒÔËÙ¶Èv0ÓëB·¢ÉúÅöײ£¬ÅöºóAÒÔv0/4µÄËٶȷ´µ¯»ØÀ´£¬BÒÔÒ»¶¨ËÙ¶ÈÑØƽ°åÏòÓÒÔ˶¯ÓëC³µµÄµ²°åÏàÅö£®ÅöºóС³µµÄËٶȵÈÓÚÅöÇ°Îï¿éBËٶȵÄÒ»°ë£®Îï¿éA¡¢B¾ùÊÓΪÖʵ㣬A¡¢BÏàÅöʱµÄÏ໥×÷ÓÃÁ¦Ô¶´óÓڵ糡Á¦£®Çó£º
£¨1£©ÔÈÇ¿µç³¡µÄ³¡Ç¿´óСºÍ·½Ïò£»
£¨2£©ÈôAµÚ¶þ´ÎºÍBÏàÅö£¬ÅжÏÊÇÔÚBÓëCÏàÅö֮ǰ»¹ÊÇÏàÅöÖ®ºó£¿
£¨3£©A´ÓµÚÒ»´ÎÓëBÏàÅöµ½µÚ¶þ´ÎÓëBÏàÅöµÄÕâ¶Îʱ¼äÄÚ£¬µç³¡Á¦¶ÔA×öµÄ¹¦£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º2013½ì¸£½¨Ê¡¸ßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔÎïÀí ÌâÐÍ£ºÑ¡ÔñÌâ

ÈçͼËùʾ£¬³¤Îª2LµÄÇá¸Ë£¬Á½¶Ë¸÷¹Ì¶¨Ò»Ð¡Çò£¬AÇòÖÊÁ¿Îªm1£¬BÇòÖÊÁ¿Îªm2£¬¹ý¸ËµÄÖеãOÓÐһˮƽ¹â»¬¹Ì¶¨Öᣬ¸Ë¿ÉÈÆÖáÔÚÊúֱƽÃæÄÚת¶¯¡£µ±×ª¶¯µ½ÊúֱλÖÃÇÒAÇòÔÚÉ϶ˣ¬BÇòÔÚ϶Ëʱ¸ËµÄ½ÇËÙ¶ÈΪ¦Ø£¬´Ëʱ¸Ë¶ÔתÖáµÄ×÷ÓÃÁ¦ÎªÁ㣬ÔòA¡¢BÁ½Ð¡ÇòµÄÖÊÁ¿Ö®±ÈΪ£¨      £©

A£®1£º1                     B.(L¦Ø2+2g): (L¦Ø2-2g)

C. (L¦Ø2-g): (L¦Ø2+g)            D.(L¦Ø2+g): (L¦Ø2-g)

 

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸