已知H-H键的键能为436kJ·mol-1.H-N键的键能为391kJ·mol-1.根据化学方程式: 高温.高压 催化剂 N2+3H2 2NH3 H=-92.4kJ·mol-1.则N≡N键的键能是 A.431kJ·mol-1 B.1130.4 kJ·mol-1 C.649kJ·mol-1 D.869kJ·mol-1 查看更多

 

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已知H—H键能为436kJ·mol-1,H—N键能为391kJ·mol-1,根据化学方程式:N2 + 3H2 = 2NH3   ΔH = -92.4 kJ·mol-1,则N≡N键的键能是(    )

A.431 kJ·mol-1                 B.946 kJ·mol-1

C.649 kJ·mol-1                 D.869 kJ·mol-1

 

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(7分)(1)已知:H—H键能为436kJ/mol,N≡N键能为945kJ/mol,N—H键能为391kJ/mol。根据键能计算工业合成氨的反应是___________ 反应(填“吸热”或“放热”),消耗1mol N2合成氨反应的=______________。                                                                                                                                                                                                                                                                                                        
(2) 现根据下列3个热化学反应方程式:
①Fe2O3(s)+3CO(g) =2Fe(s)+3CO2(g)        △H=―24.8kJ/mol
②3Fe2O3(s)+ CO(g) =2Fe3O4(s)+ CO2(g)      △H=―47.2kJ/mol
③Fe3O4(s)+CO(g) =3FeO(s)+CO2(g)         △H=+640.5kJ/mol
则CO气体还原FeO固体得到Fe固体和CO2气体的热化学反应方程式为        

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(7分)(1)已知:H—H键能为436kJ/mol,N≡N键能为945kJ/mol,N—H键能为391kJ/mol。根据键能计算工业合成氨的反应是___________ 反应(填“吸热”或“放热”),消耗1mol N2合成氨反应的=______________。                                                                                                                                                                                                                                                                                                         

(2) 现根据下列3个热化学反应方程式:

①Fe2O3(s)+3CO(g) =2Fe(s)+3CO2(g)        △H=―24.8kJ/mol

②3Fe2O3(s)+ CO(g) =2Fe3O4(s)+ CO2(g)      △H=―47.2kJ/mol

③Fe3O4(s)+CO(g) =3FeO(s)+CO2(g)         △H=+640.5kJ/mol

则CO气体还原FeO固体得到Fe固体和CO2气体的热化学反应方程式为        

 

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(7分)(1)已知:H—H键能为436kJ/mol,N≡N键能为945kJ/mol,N—H键能为391kJ/mol。根据键能计算工业合成氨的反应是___________ 反应(填“吸热”或“放热”),消耗1mol N2合成氨反应的=______________。                                                                                                                                                                                                                                                                                                        
(2) 现根据下列3个热化学反应方程式:
①Fe2O3(s)+3CO(g) =2Fe(s)+3CO2(g)        △H=―24.8kJ/mol
②3Fe2O3(s)+ CO(g) =2Fe3O4(s)+ CO2(g)      △H=―47.2kJ/mol
③Fe3O4(s)+CO(g) =3FeO(s)+CO2(g)         △H=+640.5kJ/mol
则CO气体还原FeO固体得到Fe固体和CO2气体的热化学反应方程式为        

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已知N≡N键的键能是945kJ﹒mol-1,N—N键的键能是159kJ﹒mol-1,H-H键的键能是

436kJ﹒mol-1,N-H键的键能是391kJ﹒mol-1,则N2(g)+3H2(g)===2NH3(g)的△H为(     )

A. 561 kJ﹒mol-1  B. -93 kJ﹒mol-1  C. -561 kJ﹒mol-1  D.+93kJ﹒mol-1

 

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