sin = , cos = . tan = ,记忆口诀: 六.两角和与差的三角函数 查看更多

 

题目列表(包括答案和解析)

(1)计算:lg5(lg8+lg1000)+(lg2
3
2+lg
1
6
+lg0.06;
(2)化简
sin (180°-α)•sin(270°-α)•tan(90°-α)
sin(90°+α)•tan(270°+α)•tan(360°-α)

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(1)已知tanα=-4,求
4sinα+2cosα
5cosα+3sinα
的值:
(2)化简
sin(180°-α)•sin(270°-α)•tan(90°-α)
sin(90°+α)•tan(270°+α)•tan(360°-α)

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(Ⅰ)计算:0.064-
1
3
-(-
1
8
)0+7log72+0.25
5
2
×0.5-4

(Ⅱ)化简
sin(180°-α)sin(270°-α)tan(180°-α)
sin(90°+α)tan(180°+α)tan(360°-α)

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(09年长沙一中第八次月考文)sin (270°) = (   )

A.1                          B.0                            C.1                           D.

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cos(75°+α)=
1
3
,180°<α<270°
,则cos(105°-α)+sin(α-105°)=(  )

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