ÔÚ¡°ºîʽÁªºÏÖÆ¼î·¨¡±µÄ¹¤ÒÕÁ÷³ÌÖУ¬×îºóÒ»²½ÊÇÓüÓÈÈ̼ËáÇâÄÆµÄ·½·¨À´ÖÆÈ¡´¿¼î¡£Ä³´¿¼îÉú²ú³§ÖƵõIJúÆ·Na2CO3ÖлìÓÐÉÙÁ¿NaHCO3¡£ÎªÁ˲ⶨ²úÆ·ÖÐNa2CO3µÄÖÊÁ¿·ÖÊý£¬È¡100g»ìºÏÎï¼ÓÈÈ(2NaHCO3Na2CO3+CO2¡ü+H2O, Na2CO3ÊÜÈȲ»·Ö½â£©£¬·´Ó¦¹ý³ÌÖÐÉú³É¶þÑõ»¯Ì¼ÆøÌåµÄÖÊÁ¿Ó뷴Ӧʱ¼äµÄ¹ØÏµÈçͼËùʾ¡£

Çë½â´ðÏÂÁÐÎÊÌ⣺
£¨1£©·´Ó¦¹ý³ÌÖÐÉú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª       g
£¨2£©100g»ìºÏÎïÖÐNaHCO3µÄÖÊÁ¿£»

£¨1£©0.22 £¨2£©0.84

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøÔÚ¡°ºîʽÁªºÏÖÆ¼î·¨¡±µÄ¹¤ÒÕÁ÷³ÌÖУ¬×îºóÒ»²½ÊÇÓüÓÈÈ̼ËáÇâÄÆµÄ·½·¨À´ÖÆÈ¡´¿¼î£®Ä³´¿¼îÉú²ú³§ÖƵõIJúÆ·Na2CO3ÖлìÓÐÉÙÁ¿NaHCO3£®ÎªÁ˲ⶨ²úÆ·ÖÐNa2CO3µÄÖÊÁ¿·ÖÊý£¬È¡100g»ìºÏÎï¼ÓÈÈ£¨2NaHCO3
  ¡÷  
.
 
Na2CO3+H2O+CO2¡ü£¬Na2CO3ÊÜÈȲ»·Ö½â£©£¬·´Ó¦¹ý³ÌÖÐÉú³É¶þÑõ»¯Ì¼ÆøÌåµÄÖÊÁ¿Ó뷴Ӧʱ¼äµÄ¹ØÏµÈçͼËùʾ£®
Çë½â´ðÏÂÁÐÎÊÌ⣺
£¨1£©·´Ó¦¹ý³ÌÖÐÉú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª
 
g£»
£¨2£©100g»ìºÏÎïÖÐNaHCO3µÄÖÊÁ¿£»
£¨3£©100g»ìºÏÎïÖÐNa2CO3µÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2008?²ýÆ½ÇøÒ»Ä££©ÔÚ¡°ºîʽÁªºÏÖÆ¼î·¨¡±µÄ¹¤ÒÕÁ÷³ÌÖУ¬×îºóÒ»²½ÊÇÓüÓÈÈ̼ËáÇâÄÆµÄ·½·¨À´ÖÆÈ¡´¿¼î£®Ä³´¿¼îÉú²ú³§ÖƵõIJúÆ·Na2CO3ÖлìÓÐÉÙÁ¿NaHCO3£®ÎªÁ˲ⶨ²úÆ·ÖÐNa2CO3µÄÖÊÁ¿·ÖÊý£¬È¡100g»ìºÏÎï¼ÓÈÈ£¨2NaHCO3
  ¡÷  
.
 
Na2CO3+H2O+CO2¡ü£¬Na2CO3ÊÜÈȲ»·Ö½â£©£¬·´Ó¦¹ý³ÌÖÐÉú³É¶þÑõ»¯Ì¼ÆøÌåµÄÖÊÁ¿Ó뷴Ӧʱ¼äµÄ¹ØÏµÈçͼËùʾ£®
Çë½â´ðÏÂÁÐÎÊÌ⣺
£¨1£©100g»ìºÏÎïÖÐNaHCO3µÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿
£¨2£©·´Ó¦ºóËùµÃ̼ËáÄÆµÄÖÊÁ¿ÊǶàÉÙ£¿
£¨3£©Ð¡¾üÒªÅäÖÆ20¡æÊ±Na2CO3µÄ±¥ºÍÈÜÒº£¬²éÕÒ×ÊÁÏ£¬µÃµ½ÏÂ±í£®
ζÈÈܽâ¶ÈÑÎ 10¡æ 20¡æ 30¡æ 40¡æ
Na2CO3 12.5g 21.5g 39.7g 49.0g
NaHCO3 8.1g 9.6g 11.1g 12.7g
¸ù¾ÝÉϱíÊý¾Ý¼ÆË㣬20¡æÊ±ÓÃ43g Na2CO3ÅäÖÆ³É±¥ºÍÈÜÒºµÄÖÊÁ¿Îª
243
243
g£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

ÔÚ¡°ºîʽÁªºÏÖÆ¼î·¨¡±µÄ¹¤ÒÕÁ÷³ÌÖУ¬×îºóÒ»²½ÊÇÓüÓÈÈ̼ËáÇâÄÆµÄ·½·¨À´ÖÆÈ¡´¿¼î£®Ä³´¿¼îÉú²ú³§ÖƵõIJúÆ·Na2CO3ÖлìÓÐÉÙÁ¿NaHCO3£®ÎªÁ˲ⶨ²úÆ·ÖÐNa2CO3µÄÖÊÁ¿·ÖÊý£¬È¡100g»ìºÏÎï¼ÓÈÈ£¨2NaHCO3Êýѧ¹«Ê½Na2CO3+H2O+CO2¡ü£¬Na2CO3ÊÜÈȲ»·Ö½â£©£¬·´Ó¦¹ý³ÌÖÐÉú³É¶þÑõ»¯Ì¼ÆøÌåµÄÖÊÁ¿Ó뷴Ӧʱ¼äµÄ¹ØÏµÈçͼËùʾ£®
Çë½â´ðÏÂÁÐÎÊÌ⣺
£¨1£©100g»ìºÏÎïÖÐNaHCO3µÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿
£¨2£©·´Ó¦ºóËùµÃ̼ËáÄÆµÄÖÊÁ¿ÊǶàÉÙ£¿
£¨3£©Ð¡¾üÒªÅäÖÆ20¡æÊ±Na2CO3µÄ±¥ºÍÈÜÒº£¬²éÕÒ×ÊÁÏ£¬µÃµ½ÏÂ±í£®
ζÈÈܽâ¶ÈÑÎ10¡æ20¡æ30¡æ40¡æ
Na2CO312.5g21.5g39.7g49.0g
NaHCO38.1g9.6g11.1g12.7g
¸ù¾ÝÉϱíÊý¾Ý¼ÆË㣬20¡æÊ±ÓÃ43g Na2CO3ÅäÖÆ³É±¥ºÍÈÜÒºµÄÖÊÁ¿Îª________g£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚ¡°ºîʽÁªºÏÖÆ¼î·¨¡±µÄ¹¤ÒÕÁ÷³ÌÖУ¬×îºóÒ»²½ÊÇÓüÓÈÈ̼ËáÇâÄÆµÄ·½·¨À´ÖÆÈ¡´¿¼î¡£Ä³´¿¼îÉú²ú³§ÖƵõIJúÆ·ÖлìÓÐÉÙÁ¿¡£ÎªÁ˲ⶨ²úÆ·ÖеÄÖÊÁ¿·ÖÊý£¬È¡100g»ìºÏÎï¼ÓÈÈ£¬ÊÜÈȲ»·Ö½â£©£¬·´Ó¦¹ý³ÌÖÐÉú³É¶þÑõ»¯Ì¼ÆøÌåµÄÖÊÁ¿Ó뷴Ӧʱ¼äµÄ¹ØÏµÈçͼËùʾ¡£

    Çë½â´ðÏÂÁÐÎÊÌ⣺

£¨1£©·´Ó¦¹ý³ÌÖÐÉú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª__________________g£»

£¨2£©100g»ìºÏÎïÖеÄÖÊÁ¿£»

£¨3£©100g»ìºÏÎïÖеÄÖÊÁ¿·ÖÊý¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2012Äê11ÔÂÖп¼»¯Ñ§Ä£ÄâÊÔ¾í£¨23£©£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

ÔÚ¡°ºîʽÁªºÏÖÆ¼î·¨¡±µÄ¹¤ÒÕÁ÷³ÌÖУ¬×îºóÒ»²½ÊÇÓüÓÈÈ̼ËáÇâÄÆµÄ·½·¨À´ÖÆÈ¡´¿¼î£®Ä³´¿¼îÉú²ú³§ÖƵõIJúÆ·Na2CO3ÖлìÓÐÉÙÁ¿NaHCO3£®ÎªÁ˲ⶨ²úÆ·ÖÐNa2CO3µÄÖÊÁ¿·ÖÊý£¬È¡100g»ìºÏÎï¼ÓÈÈ£¨2NaHCO3Na2CO3+H2O+CO2¡ü£¬Na2CO3ÊÜÈȲ»·Ö½â£©£¬·´Ó¦¹ý³ÌÖÐÉú³É¶þÑõ»¯Ì¼ÆøÌåµÄÖÊÁ¿Ó뷴Ӧʱ¼äµÄ¹ØÏµÈçͼËùʾ£®
Çë½â´ðÏÂÁÐÎÊÌ⣺
£¨1£©·´Ó¦¹ý³ÌÖÐÉú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª______g£»
£¨2£©100g»ìºÏÎïÖÐNaHCO3µÄÖÊÁ¿£»
£¨3£©100g»ìºÏÎïÖÐNa2CO3µÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸