Question

ÔÚ25mL0.1mol?L^-1µÄNaOHÈÜÒºÖÐÖðµÎ¼ÓÈë0.2mol?L^-1µÄCH₃COOHÈÜÒº£¬ÈÜÒºpH±ä»¯ÇúÏßÈçͼ1Ëùʾ£®
£¨1£©BµãÈÜÒº³ÊÖÐÐÔ£¬ÓÐÈ˾ݴËÈÏΪ£¬ÔÚBµãʱNaOHÈÜÒºÓëCH₃COOHÈÜҺǡºÃÍêÈ«·´Ó¦£¬ÕâÖÖ¿´·¨ÊÇ·ñÕýÈ·£¿______£¨Ìî¡°ÊÇ¡±»ò¡°·ñ¡±£©£¬Èç¹û²»ÕýÈ·£¬Ôò¶þÕßÇ¡ºÃÍêÈ«·´Ó¦µÄµãÊÇÔÚ______£¨Ìî¡°AB¡±¡¢¡°BC¡±»ò¡°CD¡±£©Çø¼äÄÚ£®
£¨2£©¹ØÓڸõζ¨ÊµÑ飬´ÓÏÂÁÐÑ¡ÏîÖÐÑ¡³ö×îÇ¡µ±µÄÒ»ÏѡÓõζ¨¹ÜÈçͼ2Ëùʾ£©______£®

	׶ÐÎÆ¿ÖеÄÈÜÒº	µÎ¶¨¹ÜÖеÄÈÜÒº	Ñ¡ÓÃָʾ¼Á	Ñ¡Óõζ¨¹Ü
A	¼î	Ëá	ʯÈï	ÒÒ
B	Ëá	¼î	¼×»ù³È	¼×
C	¼î	Ëá	·Ó̪	¼×
D	Ëá	¼î	·Ó̪	ÒÒ

£¨3£©µÄDµãʱ£¬ÈÜÒºÖÐc£¨CH₃COO^-£©+c£¨CH₃COOH£©______2c£¨Na⁺£©£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£®
£¨4£©ÔÚCµã£¬ÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ£º______£®

Answer 1

£¨1£©NaOHÈÜÒºÓëCH₃COOHÈÜҺǡºÃÍêÈ«·´Ó¦Ê±£¬Éú³ÉÁË´×ËáÄÆ£¬´×Ëá¸ùÀë×ÓË®½â£¬ÈÜÒºÏÔʾ¼îÐÔ£¬ÈÜÒºµÄpH´óÓÚ7£»¶þÕßÇ¡ºÃÍêÈ«·´Ó¦Ê±ÈÜÒºµÄpH´óÓÚ7£¬ËùÒÔÓ¦¸ÃÔÚAB¶Î£¬
¹Ê´ð°¸Îª£º·ñ£»AB£»
£¨2£©¸ù¾ÝÌâ¸ÉÐÅÏ¢£¬×¶ÐÎÆ¿ÖÐÓ¦¸ÃÊ¢·ÅÇâÑõ»¯ÄÆÈÜÒº£¬µÎ¶¨¹ÜÖÐÊ¢·Å´×Ëᣬ¶þÕßÇ¡ºÃ·´Ó¦Ê±ÈÜÒºÏÔʾ¼îÐÔ£¬Ó¦¸ÃʹÓ÷Ó̪×÷Ϊָʾ¼Á£¬ËùÒÔCÕýÈ·£¬
¹ÊÑ¡C£»
£¨3£©Dµãʱ´×ËáµÄÌå»ýΪ25mL£¬n£¨CH₃COO^-£©+n£¨CH₃COOH£©=0.2mol?L^-1¡Á0.025L=0.005mol£¬
n£¨Na⁺£©=0.1mol?L^-1¡Á0.025L=0.0025mol£¬ËùÒÔn£¨CH₃COO^-£©+n£¨CH₃COOH£©=2n£¨Na⁺£©£¬
ÓÉÓÚÈÜÒºµÄÌå»ýÏàͬ£¬ËùÒÔc£¨CH₃COO^-£©+c£¨CH₃COOH£©=2c£¨Na⁺£©£¬
¹Ê´ð°¸Îª£º=£»
£¨4£©ÔÚCµã£¬ÈÜÒºµÄpH£¼7£¬ÇâÀë×ÓŨ¶È´óÓÚÇâÑõ¸ùÀë×ÓŨ¶È£¬¸ù¾ÝµçºÉÊغ㣺CH3COO^-+OH^-=Na⁺+H⁺¿ÉÖª£¬ÈÜÒºÖУºc£¨CH₃COO^-£©£¾c£¨Na⁺£©£¾c£¨H⁺£©£¾c£¨OH^-£©£¬
¹Ê´ð°¸Îª£ºc£¨CH₃COO^-£©£¾c£¨Na⁺£©£¾c£¨H⁺£©£¾c£¨OH^-£©£®