0  399692  399700  399706  399710  399716  399718  399722  399728  399730  399736  399742  399746  399748  399752  399758  399760  399766  399770  399772  399776  399778  399782  399784  399786  399787  399788  399790  399791  399792  399794  399796  399800  399802  399806  399808  399812  399818  399820  399826  399830  399832  399836  399842  399848  399850  399856  399860  399862  399868  399872  399878  399886  447090 

2.(2008山东济南)解方程:2(x-1)+1=0.

解:2x-2+1=0……1分

2x=1……1分

X=……3分

试题详情

17. 解(1)设2007职业中专的在校生为x 万 人             

根据题意得:1500×1.2x -1500x =600     ··························································· 3分

解得:                    ················································ 5分

所以.

 ····························································································· 7分

答:略.                      ············································································· 8分

试题详情

16.

解:方案一获利:4×2000+6×500=11000(元)

方案二:设制奶粉x天,则

1×x+(4-x)×3=10,

得x=1(天)

故1×1×2000+3×3×1200=12800(元)

选方案二.

试题详情

15. 解:设老师捐款x元,学生捐款y元.则有

解得

     答:该校老师捐款18000元,学生捐款27000元.

试题详情

14. 解:(1)设每条成衣生产线和童装生产线平均每天生产帐篷各x、y顶,则

解得x=41,y=32.

答:每条成衣生产线平均每天生产帐篷41顶,每条童装生产线平均每天生产帐篷32顶.

(2)由3(4×41+5×32)=972<1000知,即使工厂满负荷全面转产,还不能如期完成任务.

可以从加班生产、改进技术等方面进一步挖掘生产潜力,或者动员其它厂家支援等,想法尽早完成生产任务,为灾区人民多做贡献.

试题详情

13. 解:设原计划每天挖土石方x万立方米,增调人员和设备后每天挖y万立方米

    可列出方程组:

    解之得:

  答:原计划每天挖土石方1.3万立方米,增调人员和设备后每天挖3.6万立方米

试题详情

12. 解:(1)设总厂原来每周制作帐篷千顶,分厂原来每周制作帐篷千顶.

由题意,得························································································ 3分

解得所以(千顶),(千顶).

答:在赶制帐篷的一周内,总厂、分厂各生产帐篷8千顶、6千顶.································ 6分

(2)设从(甲市)总厂调配千顶帐篷到灾区的地,则总厂调配到灾区地的帐篷为千顶,(乙市)分厂调配到灾区两地的帐篷分别为千顶.

甲、乙两市所需运送帐篷的车辆总数为辆.································································ 8分

由题意,得

.······················································································· 10分

因为,所以的增大而减小.

所以,当时,有最小值60.

答:从总厂运送到灾区地帐篷8千顶,从分厂运送到灾区两地帐篷分别为1千顶、5千顶时所用车辆最少,最少的车辆为60辆.    12分

试题详情

11. 解:设生产奥运会标志x套,生产奥运会吉祥物y套.根据题意,得

  …………………………………………2分

①×2-②得:5x=10000. 

x=2000. ………………………………………………………………6分

x=2000代入①得:5y=12000.

     ∴ y=2400.  

   答:该厂能生产奥运会标志2000套,生产奥运会吉祥物2400套.……8分

试题详情

10. (1)甲队行进了2小时,乙队行进了2.5小时.

设乙队的速度为x,则甲队为1.5x + 5.

由题意得方程  2.5x +(1.5x + 5)×2 + 1 = 176.

整理得 5.5x = 165, 解得 x = 30.

∴  1.5x + 5 = 1.5×30 + 5 = 50.

即甲队赶路的速度为50 km∕h,乙队赶路的速度为30 km∕h.

(2)设若由乙队单独施工,需x小时才能完成.

则由题意有  6×()+ 5.5×= 1.

解得  x = 11.

即乙队单独做,需要11小时才能完成任务.

试题详情

9. 解:(1)设小明他们一共了个成人,个学生,

·································································································· 4分

······················································································································ 6分

答:小明他们一共去了7个成人,4个学生.··································································· 7分

(2)若按14人购买团体票,则共需(元)

(元).

购买团体票可省24元.······························································································· 3分

试题详情


同步练习册答案