24. ---- Where is your uncle’s home?
---- In New York. And he _____ in New York for four years.
A. has been living B. lived C. had been living. D. had lived
23. ---- I’d like a table for six.
---- Sorry, sir, but we don’t have any table _______ tonight.
A. fit B. suitable C. available D. comfortable
22. Our New Year party was _____ success. We sang and danced until it came to _____ end at 10 o’clock.
A. a; the B. a; an C. the; an D. /; the
21. –Would you please help me with the box?
-- ___ .
A. Yes, please B. No, please don’t C. With pleasure. D. My pleasure
12.如图,过抛物线C:y=3x2(x≥0)上一点A(t,3t2)的切线为l(0<t<1),S1是抛物线C与切线l及直线x=1所围成的面积;S2是抛物线C与切线l及直线x=0所围成的图形面积.
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(1)求切线l的方程;
(2)用t表示S1和S2;
(3)若27S2=S1,求t的值.
[解] (1)因为y′=6x,故在A点处的导数值为6t,此时切线的方程为:
y-3t2=6t(x-t),
整理得y=6tx-3t2 (0<t<1).
(2)S1=[3x2-(6tx-3t2)]dx
=(x3-3tx2+3t2x)|=t3 (0<t<1);
S2=[3x2-(6tx-3t2)]dx=(x3-3tx2+3t2x)|
=1-3t+3t2-t3=(1-t)3 (0<t<1).
(3)27S2=S1,27(1-t)3=t3 ∴t=.
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亲爱的同学请写上你的学习心得
________________________________________________________________________
11.计算由曲线y2=x,y=x2所围图形的面积.
[解] 如图所示.为了确定图形的范围,先求出这两条曲线的交点的横坐标,
解方程组得出交点的横坐标为x=0及x=1.
因此所求图形的面积
S=dx-x2dx=(x-x3)|=-=.
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10.(2008·山东,14)设函数f(x)=ax2+c(a≠0),若
f(x)dx=f(x0),0≤x0≤1,则x0的值为________.
[解析] 由已知得a+c=ax+c,
∴x=,又∵0≤x≤1,故x0=.
[答案]
9.(2008·惠州第一次模拟)一物体在力F(x)=3x+4的作用下,沿着与F相同的方向,从x=0处运动到x=4处,力F所做的功为________.
[答案] 40
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