下面描绘的是醉酒驾车的违章行为,请你根据这幅漫画用英语写一篇短文。要求描述图片的内容,分析问题存在的根源和解决的办法,并发表一下你的看法。
注意:1.可适当发挥想象,避免简单描述。
2.词数150左右。开头已经写好,不计入总词数。
3.作文中不得提及考生所在学校和本人姓名。
This is a picture which describes vividly a kind of common phenomenon among some drivers in our country.
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1-5 CCBAC 6-10 ACBBC 11-15 CBCAA 16-20 BCBAC
21-25 ADABB 26-30 CCADB 31-35 AACBA 36-40 DBACB 41-45 ABDCA 46-50DBACD 51-55 AADBC A) CBDC B) BADC C) BCDC D) DAC 1. takes 2. available 3.short 4. absent 5.aware 6. Causes 7. population 8. disappearance 9. access 10. Solution
This is a picture which describes vividly a kind of common phenomenon among some drivers in our country. In the picture, a drunk driver is caught speeding. He has drunk so much that he can’t walk normally. How can he drive a car in such bad condition?
It is well known that drunk driving has been the leading cause of road accidents, but some people still drive after drinking. What are the reasons for the phenomenon? The lack of safety awareness is the direct reason why there exists so much drunk driving. Besides, some people believe that drinking a little does no harm to their driving. If traffic accidents happen, it will be too late for them to regret what they have done.
Drunk driving is a great danger both to our society and to drivers. It is necessary to forbid drinking before driving. It’s time we took some measures to make a total ban on it. Firstly, we should reinforce the traffic security education to raise people’s awareness towards safety. Secondly, the government should make stricter laws about it and punish drunk drivers severely. Thirdly, we can make posters and signs warning people not to drive after drinking .
In my opinion , the approaches above should be followed and gradually spread out all over the country. Only in this way can people build up their self-conscience and pay enough attention to their daily driving. If we can keep on doing this, the road accidents will decrease soon in the future.
第二节(共15小题;每小题1分,满分15分)
听下面5段对话或独白。每段对话或独白后有几个小题,从题中所给的A、B、C三
个选项中选出最佳选项,并标在试卷的相应位置。听每段对话或独白前,你将有时间阅
读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。每段对话或独
白读两遍。
听第6段材料,回答第6至8题。
6. Where is the man working?
A. In a fast restaurant. B. In a computer company. C. At a school.
7. Why will the man change his job?
A. To try something new. B. To get more experience. C. To make more money.
8. How does the woman feel about the man?
A. Satisfied. B. Disappointed. C. Interested.
听第7段材料,回答第9至11题。
9. Who is the woman?
A. The man's sister. B. The man's wife. C. The man's girlfriend.
10. Why do they want to have a change about their weekends?
A. They seldom invite friends over.
B. They seldom watch football games.
C. They seldom spend the weekends together.
11. What do they plan to do this weekend?
A. Play cards. B. Have tea. C. Go for a picnic.
听第8段材料,回答第12至14题。
12. How long had the man been waiting for her?
A. Nearly an hour. B. More than an hour. C. About five minutes.
13. Why didn't she tell her boss about her appointment?
A. She didn't think the work was hard to do.
B. She didn't think the boss would let her go.
C. She didn't think the work would take long.
14. What does the man think of the woman's being late at last?
A. Understandable. B. Unforgivable. C. Unbelievable.
听第9段材料,回答第15至17题。
15. How long does the man often sleep at night?
A. 3 hours. B. 5 hours. C. 7 hours.
16. What is the main cause of the man's feeling bad?
A. Too little exercise. B. Much worry about work. C. Strong desire for a better job.
17. What does the woman give to the man?
A. A new job. B. Medicine for sleep. C. Some advice.
听第10段材料,回答第18至20题。
18. Why is the speaker leaving for London?
A. To visit some museums. B. To attend a conference. C. To go on business.
19. What will the speaker do in London?
A. Meet his old teacher. B. Study English literature. C. See the dentist.
20. Who does the speaker want John to telephone?
A. Peter. B. The teacher. C. The dentist.
2.只要注意到
,即可迅速得到答案.
例14、已知
,复数
的实部为
,虚部为1,则
的取值范围是( )
A.
B.
C.
D.![]()
[解析]由于0<a<2,故
∴
。
[答案]C
例15、知复数z=1-i,则
=( )
A.2i B.-2i C.2 D.-2
[解析]将
代入得
,选B.
[答案]B
例16、设z的共轭复数是
,或z+
=4,z·
=8,则
等于( )
A.1 B.-i C.±1 D. ±i
[解析] 可设
,由
得![]()
![]()
[答案]:D.
例17、
表示为![]()
,则
=
。
[解析]
,因此
=1。
[答案]1
例18、若复数z满足z=i(2-z)(i是虚数单位),则z=
[解析]由
.
[答案]![]()
例19、若复数(1+bi)(2+i)是纯虚数(i是虚数单位,b为实数),则b=
A -2
B -
C
D 2
[解析](1+bi)(2+i)=(2-b)+(2b+1)i,故2b+1=0,故选B;
[答案]B;
例20、 若
(
为虚数单位),则
的
值可能是
A
B
C
D ![]()
[解析]:把
代入验证即得。
[答案] D
例21、已知
是实系数一元二次方程
的两根,则
的值为 ( )
A、
B、
C、
D、![]()
[解析] 因为2+ a i,b+i( i 是虚数单位)是实系数一元二次方程
的两个根,所以a=-1,b=2,所以实系数一元二次方程
的两个根是
所以![]()
[答案]A
例22、.若复数(1+bi)(2+i)是纯虚数(i是虚数单位,b是实数),则b=
A.-2
B.
C.
D.2
[解析]
,依题意
,
选 D .
[答案]D
例23、已知
是实数,
是春虚数,则
=( )
(A)1 (B)-1 (C)
(D)-![]()
[解析]:由
是纯虚数,则
且
故
=1.
[答案]A
例24、复数
( )
A.2 B.-2 C.
D. ![]()
[解析]:![]()
![]()
[答案]:A.
例25、若复数(a2-3a+2)+(a-1)i是纯虚数,则实数a的值为( )
A.1 B.2 C.1或2 D.-1
[解析]由
得
,且![]()
![]()
[答案]B
例25、若复数
(
)是纯虚数,则
= .2
[解析]由
,所以
=2.
[答案].2
例26、.已知zi+z=2,则复数z=()
A.1-i B.1+i C.2i D.-2i
[解析]由zi+z=2得Z=
,所以选A项.
[答案]A
例27、.已知i是虚数单位,![]()
R,且
是纯虚数,则
等于( )
A.1 B.-1 C.i D.-i
[解析]由
=
是纯虚数,得m=2,所以
=
.
例28、若z1=a+2i,z2=3-4i,且
为纯虚数,则实数a的值是 ▲ .
[解析]
=
,则由条件可得3a-8=0,得a=
.
例29、已知
,且
(
为虚数单位),则z=_______;
=_______.
[解析]设Z=a+bi,则
,所以由条件
得:
,所以
,即z=2i,
=
.
[答案]2i,
.
例30、已知复数
,则
等于( )
A.
B.
C.
D.![]()
[解析]
.
[答案] D
例30、若
,则
的值是( )。
A.1 B.0 C.-1 D.-2
[解析]
.
[答案]B
例31、已知
的虚部为 (
)
A.1 B.-1 C.
D.![]()
[解析]
,故虚部是1.
[答案]A
例32、复数
(
是虚数单位)在复平面上对应的点位于 ( )
A.第一象限 B.第二象限 C.第三象限 D.第四象限
[解析]
,所以在第二象限.
[答案]B
例33、若
(其中
是虚数单位,b是实数),则b= ( )
A.-4 B.4 C.-8 D.8
[解析]
,所以b=-8.
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